Physics

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Question

# A car moving over a straight path covers a distance x with constant speed 10ms^{-1} and then the same distance with constant speed of V_{1.}If average speed of the car is , 16 ms^{-1 }then V_{2}=..._{}

- 30 ms
^{-1} - 20 ms
^{-1} - 40 ms
^{-1} - 25 ms
^{-1}

^{-1}^{-1}^{-1}^{-1}## The correct answer is: 40 ms^{-1}

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