Physics-
General
Easy

Question

A string of length L is fixed at one end and the string makes fraction numerator 2 over denominator pi end fraction rev/s around the vertical axis through, the fixed and as shown in the figure, then tension in the string is

  1. M L    
  2. 2 blank M L    
  3. 4blank M L    
  4. 16blank M L    

The correct answer is: 16blank M L


    T sin invisible function application theta equals M omega to the power of 2 end exponent R (i)
    T sin invisible function application theta equals M omega to the power of 2 end exponent L blank s i n blank theta (ii)
    T equals M omega to the power of 2 end exponent L
    equals M bullet 4 pi to the power of 2 end exponent n to the power of 2 end exponent L
    equals M bullet 4 pi to the power of 2 end exponent open parentheses fraction numerator 2 over denominator pi end fraction close parentheses to the power of 2 end exponent L
    equals 16 blank M L

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