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Physics-

General

Easy

Question

An Indian submarine and an enemy submarine move towards each other during maneuvers in motionless water in the Indian ocean. The Indian submarine moves at $50 blank k m divided by h comma$ and the enemy submarine at $70 blank k m divided by h.$ The Indian sub sends out a sonar signal (sound wave in water) at $1000 blank H z.$ Sonar waves travel at $5500 blank k m divided by h.$ What is the frequency detected by the Indian submarine

$1.04 k H z$
$2 k H z$
$2.5 k H z$
$4.7 k H z$

The correct answer is: $1.04 blank k H z$

Frequency detected by Indian submarine
$n to the power of ´ end exponent equals n open parentheses fraction numerator v plus v subscript E end subscript over denominator v minus v subscript I end subscript end fraction close parentheses open parentheses fraction numerator v plus v subscript I end subscript over denominator v minus v subscript E end subscript end fraction close parentheses equals 1.04 blank k H z$

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