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Question

The velocity-time and acceleration-time graphs of a particle are given as

Its position-time graph may be given as

  1.  
  2.  
  3.  

The correct answer is:

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Displacement equals open parentheses 2 cross times 4 minus 2 cross times 2 plus 2 cross times 4 close parentheses equals12m
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Displacement equals open parentheses 2 cross times 4 minus 2 cross times 2 plus 2 cross times 4 close parentheses equals12m
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The velocity-time graph of a particle in linear motion is shown. Both v and t are in SI units. What is the displacement of the particle from the origin after 8 s?

physics-General
text Displacement: = Area of upper trapezium  end text minus text  Area of lower trapezium end text
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A particle is moving along the circle x squared plus y squared equals a squared in anticlockwise direction. The x–y plane is a rough horizontal stationary surface. At the point left parenthesis a space cos theta comma space a space sin theta right parenthesis, the unit vector in the direction of friction on the particle is

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