Physics-

General

Easy

Question

# What is the equivalent resistance between in the given circuit?

## The correct answer is:

### and are in series

are in parallel

and are in series

and are in parallel

and are in series

Now, and are in parallel

### Related Questions to study

physics-

### The current in the 1 resistor shown in the circuit is

In the given circuit 4 resistors are connected in parallel, this combination is connected in series with 1 resistance.

Also, R’’=2 +1 =3

From Ohm’s law,

Also, R’’=2 +1 =3

From Ohm’s law,

### The current in the 1 resistor shown in the circuit is

physics-General

In the given circuit 4 resistors are connected in parallel, this combination is connected in series with 1 resistance.

Also, R’’=2 +1 =3

From Ohm’s law,

Also, R’’=2 +1 =3

From Ohm’s law,

physics-

### The current in the 1 resistor shown in the circuit is

In the given circuit 4 resistors are connected in parallel, this combination is connected in series with 1 resistance.

Also, R’’=2 +1 =3

From Ohm’s law,

Also, R’’=2 +1 =3

From Ohm’s law,

### The current in the 1 resistor shown in the circuit is

physics-General

Also, R’’=2 +1 =3

From Ohm’s law,

physics-

### The total current supplied to the given circuit by the battery is

The equivalent circuit of the given circuit is as shown

Resistances 6 and 2 are in parallel

Resistances

Resistances 3 and 3 are in parallel

The current,

Resistances 6 and 2 are in parallel

Resistances

Resistances 3 and 3 are in parallel

The current,

### The total current supplied to the given circuit by the battery is

physics-General

The equivalent circuit of the given circuit is as shown

Resistances 6 and 2 are in parallel

Resistances

Resistances 3 and 3 are in parallel

The current,

Resistances 6 and 2 are in parallel

Resistances

Resistances 3 and 3 are in parallel

The current,

physics-

### A current of 2A flows in an electric circuit as shown in figure. The potential difference, in volts( are potentials at R and S respectively) is

Current through each arm

PRQ and PSQ=1A

From Eqs. (i) and (ii), we get

PRQ and PSQ=1A

From Eqs. (i) and (ii), we get

### A current of 2A flows in an electric circuit as shown in figure. The potential difference, in volts( are potentials at R and S respectively) is

physics-General

Current through each arm

PRQ and PSQ=1A

From Eqs. (i) and (ii), we get

PRQ and PSQ=1A

From Eqs. (i) and (ii), we get

physics-

### A 3 V battery with negligible internal resistance is connected in a circuit as shown in the figure. The current I, in the circuit will be

Resistance in the arms AC and BC are in series,

∴ R’=3+3=6

Now, R’ and 3 are in parallel,

Now, V=IR

∴ R’=3+3=6

Now, R’ and 3 are in parallel,

Now, V=IR

### A 3 V battery with negligible internal resistance is connected in a circuit as shown in the figure. The current I, in the circuit will be

physics-General

Resistance in the arms AC and BC are in series,

∴ R’=3+3=6

Now, R’ and 3 are in parallel,

Now, V=IR

∴ R’=3+3=6

Now, R’ and 3 are in parallel,

Now, V=IR

physics-

### The equivalent resistance between the points A and B will be (each resistance is

15 )

The circuit can be shown as given below

The equivalent resistance between D and C.

Now, between A and B, the resistance of upper part ADCB,

Between A and B, the resistance of middle part AOB

Therefore, equivalent resistance between A and B

The equivalent resistance between D and C.

Now, between A and B, the resistance of upper part ADCB,

Between A and B, the resistance of middle part AOB

Therefore, equivalent resistance between A and B

### The equivalent resistance between the points A and B will be (each resistance is

15 )

physics-General

The circuit can be shown as given below

The equivalent resistance between D and C.

Now, between A and B, the resistance of upper part ADCB,

Between A and B, the resistance of middle part AOB

Therefore, equivalent resistance between A and B

The equivalent resistance between D and C.

Now, between A and B, the resistance of upper part ADCB,

Between A and B, the resistance of middle part AOB

Therefore, equivalent resistance between A and B

physics-

### There resistances of 4 each are connected as shown in figure. If the point D divides the resistance into two equal halves, the resistance between points A and D will be

The equivalent circuit is given by

4 and 2 resistances are in series on both sides.

Then 6 and6 resistances are in parallel on both sides

R=3

4 and 2 resistances are in series on both sides.

Then 6 and6 resistances are in parallel on both sides

R=3

### There resistances of 4 each are connected as shown in figure. If the point D divides the resistance into two equal halves, the resistance between points A and D will be

physics-General

The equivalent circuit is given by

4 and 2 resistances are in series on both sides.

Then 6 and6 resistances are in parallel on both sides

R=3

4 and 2 resistances are in series on both sides.

Then 6 and6 resistances are in parallel on both sides

R=3

physics-

### A particle starts from rest at and moves in a straight line with an acceleration as shown below. The velocity of the particle at is

Velocity of graph Area of- graph

### A particle starts from rest at and moves in a straight line with an acceleration as shown below. The velocity of the particle at is

physics-General

Velocity of graph Area of- graph

maths-

### Period of is

### Period of is

maths-General

Maths-

### Period of

### Period of

Maths-General

physics-

### In a network as shown in the figure, the potential difference across the resistance 2R is (the cell has an emf of E volt and has no ingternal resistance)

In the given circuit, resistors 4R and 2R are connected in parallel while resistance R is connected in series to it.

Hence, equivalent resistance is

Given, emf is E volts, therefore

Potential difference across R is

Potential difference across 2R is

Hence, equivalent resistance is

Given, emf is E volts, therefore

Potential difference across R is

Potential difference across 2R is

### In a network as shown in the figure, the potential difference across the resistance 2R is (the cell has an emf of E volt and has no ingternal resistance)

physics-General

In the given circuit, resistors 4R and 2R are connected in parallel while resistance R is connected in series to it.

Hence, equivalent resistance is

Given, emf is E volts, therefore

Potential difference across R is

Potential difference across 2R is

Hence, equivalent resistance is

Given, emf is E volts, therefore

Potential difference across R is

Potential difference across 2R is

physics-

### In the adjoining figure the equivalent resistance between A and B is

Equivalent circuit of the given circuit is

Between points C and D resistors 2, 2 and 2 are in series, therefore, their equivalent resistance,

Resistors R’ and 6 are in parallel, therefore their equivalent resistance is given by

Now between points A and B 1, 3 and 1 are in series.

Therefore, resultant resistance is

R=1+3+1=5

Between points C and D resistors 2, 2 and 2 are in series, therefore, their equivalent resistance,

Resistors R’ and 6 are in parallel, therefore their equivalent resistance is given by

Now between points A and B 1, 3 and 1 are in series.

Therefore, resultant resistance is

R=1+3+1=5

### In the adjoining figure the equivalent resistance between A and B is

physics-General

Equivalent circuit of the given circuit is

Between points C and D resistors 2, 2 and 2 are in series, therefore, their equivalent resistance,

Resistors R’ and 6 are in parallel, therefore their equivalent resistance is given by

Now between points A and B 1, 3 and 1 are in series.

Therefore, resultant resistance is

R=1+3+1=5

Between points C and D resistors 2, 2 and 2 are in series, therefore, their equivalent resistance,

Resistors R’ and 6 are in parallel, therefore their equivalent resistance is given by

Now between points A and B 1, 3 and 1 are in series.

Therefore, resultant resistance is

R=1+3+1=5

physics-

### The charge on the capacitor of capacitance shown in the figure below will be

### The charge on the capacitor of capacitance shown in the figure below will be

physics-General

physics-

### Each resistance shown in figure is 2. The equivalent resistance between A and B is

Given circuit is a balanced Wheatstone bridge. So, diagonal resistance of 2 will be ineffective.

Equivalent resistance of upper arms

=2+2=4

Equivalent resistance of lower arms

=2+2=4

Equivalent resistance of upper arms

=2+2=4

Equivalent resistance of lower arms

=2+2=4

### Each resistance shown in figure is 2. The equivalent resistance between A and B is

physics-General

Given circuit is a balanced Wheatstone bridge. So, diagonal resistance of 2 will be ineffective.

Equivalent resistance of upper arms

=2+2=4

Equivalent resistance of lower arms

=2+2=4

Equivalent resistance of upper arms

=2+2=4

Equivalent resistance of lower arms

=2+2=4

physics-

### The equivalent resistance across A and B is

The equivalent circuit can be redrawn as

we have,

So, the given circuit is a balanced Wheatstone’s bridge.

Hence, the equivalent resistance

we have,

So, the given circuit is a balanced Wheatstone’s bridge.

Hence, the equivalent resistance

### The equivalent resistance across A and B is

physics-General

The equivalent circuit can be redrawn as

we have,

So, the given circuit is a balanced Wheatstone’s bridge.

Hence, the equivalent resistance

we have,

So, the given circuit is a balanced Wheatstone’s bridge.

Hence, the equivalent resistance