General
Easy
Maths-

Solution of Cot squared space theta plus open parentheses square root of 3 plus fraction numerator 1 over denominator square root of 3 end fraction close parentheses Cot space theta plus 1 equals 0 is

Maths-General

  1. n pi minus pi over 6 comma n pi minus pi over 3 comma straight for all n element of Z
  2. n pi plus pi over 6 comma n pi plus pi over 3 comma straight for all n element of Z
  3. n pi plus pi over 12 comma straight for all n element of Z
  4. n pi plus pi over 4 comma straight for all n element of Z

    Answer:The correct answer is: n pi minus pi over 6 comma n pi minus pi over 3 comma straight for all n element of Z

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    Related Questions to study

    General
    maths-

    3 Sin space x plus 4 Cos space x minus 6 equals 0 then the general solution of bold x =

    3 Sin space x plus 4 Cos space x minus 6 equals 0 then the general solution of bold x =

    maths-General
    General
    maths-

    In capital delta A B C comma R to the power of 2 end exponent left parenthesis blank s i n blank 2 A plus blank s i n blank 2 B plus blank s i n blank 2 C right parenthesis equals

    Given R to the power of 2 end exponent left parenthesis blank s i n blank 2 A plus blank s i n blank 2 B plus blank s i n blank 2 C right parenthesis equals
    R to the power of 2 end exponent( 4 blank s i n blankAsinBsin C)
    equals 4 a to the power of 2 end exponent cross times fraction numerator a over denominator 2 a end fraction cross times fraction numerator b over denominator 2 a end fraction cross times fraction numerator c over denominator 2 a end fraction equals fraction numerator a b c over denominator 2 R end fraction equals 2 capital delta.

    In capital delta A B C comma R to the power of 2 end exponent left parenthesis blank s i n blank 2 A plus blank s i n blank 2 B plus blank s i n blank 2 C right parenthesis equals

    maths-General
    Given R to the power of 2 end exponent left parenthesis blank s i n blank 2 A plus blank s i n blank 2 B plus blank s i n blank 2 C right parenthesis equals
    R to the power of 2 end exponent( 4 blank s i n blankAsinBsin C)
    equals 4 a to the power of 2 end exponent cross times fraction numerator a over denominator 2 a end fraction cross times fraction numerator b over denominator 2 a end fraction cross times fraction numerator c over denominator 2 a end fraction equals fraction numerator a b c over denominator 2 R end fraction equals 2 capital delta.
    General
    physics-

    Velocity-time left parenthesis v-t right parenthesis graph for a moving object is shown in the figure. Total displacement of the object during the same interval when there is non-zero acceleration and retardation is

    Between time interval 20 blank s e c to 40 blank s e c, there is non-zero acceleration and retardation. Hence distance travelled during this interval
    equals Area between time interval 20 blank s e c to 40 blank s e c
    equals fraction numerator 1 over denominator 2 end fraction cross times 20 cross times 3 plus 20 cross times 1 equals 30 plus 20 equals 50 blank m

    Velocity-time left parenthesis v-t right parenthesis graph for a moving object is shown in the figure. Total displacement of the object during the same interval when there is non-zero acceleration and retardation is

    physics-General
    Between time interval 20 blank s e c to 40 blank s e c, there is non-zero acceleration and retardation. Hence distance travelled during this interval
    equals Area between time interval 20 blank s e c to 40 blank s e c
    equals fraction numerator 1 over denominator 2 end fraction cross times 20 cross times 3 plus 20 cross times 1 equals 30 plus 20 equals 50 blank m
    General
    maths-

    tan space open parentheses pi over 4 plus x over 2 close parentheses minus tan space open parentheses pi over 4 minus x over 2 close parentheses equals 2 then the general solution of x =

    tan space open parentheses pi over 4 plus x over 2 close parentheses minus tan space open parentheses pi over 4 minus x over 2 close parentheses equals 2 then the general solution of x =

    maths-General
    General
    maths-

    The general solution of  fraction numerator tan space 5 x minus tan space 4 x over denominator 1 plus tan space 5 x tan space 4 x end fraction equals 1 is

    The general solution of  fraction numerator tan space 5 x minus tan space 4 x over denominator 1 plus tan space 5 x tan space 4 x end fraction equals 1 is

    maths-General
    General
    physics-

    The graph between the displacement x and t for a particle moving in a straight line is shown in figure. During the interval O A comma A B comma B C and C D comma the acceleration of the particle is

    O A comma blank A B comma blank B C, C D

    Region O A shows that graph bending toward time axis i. e. acceleration is negative.
    Region A B shows that graph is parallel to time axisi. e. blankvelocity is zero. Hence acceleration is zero.
    Region B C shows that graph is bending towards displacement axis i. e. acceleration is positive.
    Region C D blankshows that graph having constant slope i. e. velocity is constant. Hence acceleration is zero

    The graph between the displacement x and t for a particle moving in a straight line is shown in figure. During the interval O A comma A B comma B C and C D comma the acceleration of the particle is

    O A comma blank A B comma blank B C, C D

    physics-General
    Region O A shows that graph bending toward time axis i. e. acceleration is negative.
    Region A B shows that graph is parallel to time axisi. e. blankvelocity is zero. Hence acceleration is zero.
    Region B C shows that graph is bending towards displacement axis i. e. acceleration is positive.
    Region C D blankshows that graph having constant slope i. e. velocity is constant. Hence acceleration is zero
    General
    maths-

    If Sin space A equals Sin space B comma Cos space A equals Cos space B text  then  end text A equals

    If Sin space A equals Sin space B comma Cos space A equals Cos space B text  then  end text A equals

    maths-General
    General
    maths-

    If Tan space bold A plus Tan space 2 bold A plus square root of 3 Tan space bold ATan 2 bold A equals square root of 3 then the general solution of A over 2 equals

    If Tan space bold A plus Tan space 2 bold A plus square root of 3 Tan space bold ATan 2 bold A equals square root of 3 then the general solution of A over 2 equals

    maths-General
    General
    maths-

    In capital delta A B C comma capital sigma a to the power of 3 end exponent blank c o s blank(B-C) equals

    A equals B equals C equals 6 0 to the power of 0 end exponent comma a equals b equals c equals 1

    In capital delta A B C comma capital sigma a to the power of 3 end exponent blank c o s blank(B-C) equals

    maths-General
    A equals B equals C equals 6 0 to the power of 0 end exponent comma a equals b equals c equals 1
    General
    maths-

    Solution of Tan space x plus Tan space open parentheses 120 to the power of 6 plus x close parentheses plus Tan space open parentheses x minus 120 to the power of ring operator close parentheses equals 0 is

    Solution of Tan space x plus Tan space open parentheses 120 to the power of 6 plus x close parentheses plus Tan space open parentheses x minus 120 to the power of ring operator close parentheses equals 0 is

    maths-General
    General
    maths-

    In capital delta A B C comma I f a comma b, care in H.P., then Sin invisible function application 2 A over 2 , Sin2 fraction numerator B over denominator 2 end fraction , Sin2 fraction numerator C over denominator 2 end fraction are in

    a comma b comma c are in H. P comma fraction numerator 1 over denominator a end fraction comma fraction numerator 1 over denominator b end fraction comma fraction numerator 1 over denominator c end fraction are in A. P fraction numerator s minus a over denominator a end fraction comma fraction numerator s minus b over denominator b end fraction comma fraction numerator s minus c over denominator c end fraction are in A. P

    In capital delta A B C comma I f a comma b, care in H.P., then Sin invisible function application 2 A over 2 , Sin2 fraction numerator B over denominator 2 end fraction , Sin2 fraction numerator C over denominator 2 end fraction are in

    maths-General
    a comma b comma c are in H. P comma fraction numerator 1 over denominator a end fraction comma fraction numerator 1 over denominator b end fraction comma fraction numerator 1 over denominator c end fraction are in A. P fraction numerator s minus a over denominator a end fraction comma fraction numerator s minus b over denominator b end fraction comma fraction numerator s minus c over denominator c end fraction are in A. P
    General
    maths-

    If Tanp space theta equals Cotq space theta then solutions of theta are in -

    If Tanp space theta equals Cotq space theta then solutions of theta are in -

    maths-General
    General
    physics-

    A cyclist starts from the centre O of a circular park of radius one kilometre, reaches the edge P of the park, then cycles along the circumference and returns to the centre along Q O as shown in figure. If the round trip takes ten minutes, the net displacement and average speed of the cyclist (in metre and kilometre per hour) is

    Net displacement equals 0 and total distance equals O P plus P Q plus Q O
    equals 1 plus fraction numerator 2 pi cross times 1 over denominator 4 end fraction plus 1 equals fraction numerator 14.28 over denominator 4 end fraction blank k m
    Average speedblank equals fraction numerator 14.28 over denominator 4 cross times 10 divided by 60 end fraction
    equals fraction numerator 6 cross times 14.28 over denominator 4 end fraction equals 21.42 blank k m divided by h

    A cyclist starts from the centre O of a circular park of radius one kilometre, reaches the edge P of the park, then cycles along the circumference and returns to the centre along Q O as shown in figure. If the round trip takes ten minutes, the net displacement and average speed of the cyclist (in metre and kilometre per hour) is

    physics-General
    Net displacement equals 0 and total distance equals O P plus P Q plus Q O
    equals 1 plus fraction numerator 2 pi cross times 1 over denominator 4 end fraction plus 1 equals fraction numerator 14.28 over denominator 4 end fraction blank k m
    Average speedblank equals fraction numerator 14.28 over denominator 4 cross times 10 divided by 60 end fraction
    equals fraction numerator 6 cross times 14.28 over denominator 4 end fraction equals 21.42 blank k m divided by h
    General
    physics-

    Acceleration velocity graph of a particle moving in a straight line is as shown in figure. The slope of velocity-displacement graph

    From acceleration-velocity graph, we have a equals k blank v blankwhere k is a constant which represents the slope of the given line.
    As, a equals v fraction numerator d v over denominator d s end fraction comma so v equals fraction numerator d v over denominator d s end fraction equals k v
    or fraction numerator d v over denominator d s end fraction equals k equals a constant
    Thus, the slope of velocity-displacement graphs is same as that of acceleration velocity. Which is constant.

    Acceleration velocity graph of a particle moving in a straight line is as shown in figure. The slope of velocity-displacement graph

    physics-General
    From acceleration-velocity graph, we have a equals k blank v blankwhere k is a constant which represents the slope of the given line.
    As, a equals v fraction numerator d v over denominator d s end fraction comma so v equals fraction numerator d v over denominator d s end fraction equals k v
    or fraction numerator d v over denominator d s end fraction equals k equals a constant
    Thus, the slope of velocity-displacement graphs is same as that of acceleration velocity. Which is constant.
    General
    physics-

    A ball is thrown vertically upwards. Which of the following graph/graphs represent velocity-time graph of the ball during its flight (air resistance is neglected)?

    In the positive region the velocity decreases linearly (during rise) and in the negative region velocity increases linearly (during fall) and the direction is opposite to each other during rise and fall, hence fall is shown in the negative region

    A ball is thrown vertically upwards. Which of the following graph/graphs represent velocity-time graph of the ball during its flight (air resistance is neglected)?

    physics-General
    In the positive region the velocity decreases linearly (during rise) and in the negative region velocity increases linearly (during fall) and the direction is opposite to each other during rise and fall, hence fall is shown in the negative region