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Maths-

The coefficient of x to the power of n in fraction numerator x plus 1 over denominator left parenthesis x minus 1 right parenthesis squared left parenthesis x minus 2 right parenthesis end fraction is

Maths-General

  1. 1 plus 2 n minus 3 over 2 to the power of n minus 1 end exponent
  2. 1 plus 2 n minus 3 over 2 to the power of n minus 1 end exponent
  3. 1 minus 2 n minus 3 over 2 to the power of n plus 1 end exponent
  4. 1 minus 2 n minus 3 over 2 to the power of n minus 1 end exponent

    Answer:The correct answer is: 1 minus 2 n minus 3 over 2 to the power of n plus 1 end exponent

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    A mass of 100 blank g strikes the wall with speed 5 blank m divided by s at an angle as shown in figure and it rebounds with the same speed. If the contact time is 2 cross times 10 to the power of negative 3 end exponent s e c, what is the force applied on the mass by the wall

    Force = Rate of change of momentum
    Initial momentum stack P with rightwards arrow on top subscript 1 end subscript equals m v sin invisible function application theta stack i with hat on top plus m v cos invisible function application theta blank stack j with hat on top
    Final momentum stack P with rightwards arrow on top subscript 2 end subscript equals negative m v sin invisible function application theta stack i with hat on top plus m v cos invisible function application theta blank stack j with hat on top
    therefore stack F with rightwards arrow on top equals fraction numerator increment stack P with rightwards arrow on top over denominator increment t end fraction equals fraction numerator negative 2 m v sin invisible function application theta over denominator 2 cross times 10 to the power of negative 3 end exponent end fraction
    Substituting m equals 0.1 blank k g comma blank v equals 5 blank m divided by s comma blank theta equals 60 degree
    Force on the ball stack F with rightwards arrow on top equals negative 250 square root of 3 N
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    A mass of 100 blank g strikes the wall with speed 5 blank m divided by s at an angle as shown in figure and it rebounds with the same speed. If the contact time is 2 cross times 10 to the power of negative 3 end exponent s e c, what is the force applied on the mass by the wall

    physics-General
    Force = Rate of change of momentum
    Initial momentum stack P with rightwards arrow on top subscript 1 end subscript equals m v sin invisible function application theta stack i with hat on top plus m v cos invisible function application theta blank stack j with hat on top
    Final momentum stack P with rightwards arrow on top subscript 2 end subscript equals negative m v sin invisible function application theta stack i with hat on top plus m v cos invisible function application theta blank stack j with hat on top
    therefore stack F with rightwards arrow on top equals fraction numerator increment stack P with rightwards arrow on top over denominator increment t end fraction equals fraction numerator negative 2 m v sin invisible function application theta over denominator 2 cross times 10 to the power of negative 3 end exponent end fraction
    Substituting m equals 0.1 blank k g comma blank v equals 5 blank m divided by s comma blank theta equals 60 degree
    Force on the ball stack F with rightwards arrow on top equals negative 250 square root of 3 N
    Negative sign indicates direction of the force
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    If the locus of the mid points of the chords of the ellipse fraction numerator x to the power of 2 end exponent over denominator a to the power of 2 end exponent end fraction plus fraction numerator y to the power of 2 end exponent over denominator b to the power of 2 end exponent end fraction equals 1, drawn parallel to y equals m subscript 1 end subscript x is y equals m subscript 2 end subscript x then m subscript 1 end subscript m subscript 2 end subscript equals

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    An intense stream of water of cross-sectional area A strikes a wall at an angle theta with the normal to the wall and returns back elastically. If the density of water is rho and its velocity is v,then the force exerted in the wall will be

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    equals P subscript i end subscript cos invisible function application theta plus P subscript r end subscript cos invisible function application theta
    equals 2 A v to the power of 2 end exponent blank rho cos invisible function application theta
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    equals P subscript i end subscript cos invisible function application theta plus P subscript r end subscript cos invisible function application theta
    equals 2 A v to the power of 2 end exponent blank rho cos invisible function application theta
    By definition of force, force exerted on the Wall equals 2 A v to the power of 2 end exponent blank rho cos invisible function application theta
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    The force required to stretch a spring varies with the distance as shown in the figure. If the experiment is performed with above spring of half length, the line O A will

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