Maths-

General

Easy

Question

# The shaded portion in the given figure shows a circular path enclosed by the two concentric circles. If the inner circumference of the path is 176 m and the uniform width of the circular path is 3.5 m, find the area of the path

Hint:

### Area of the path is the difference of the areas of two circles

## The correct answer is: 346.5 m2

### It is given that Inner circumference of the path= 176 m

2 r = 172 r = 176

r = 14 m

Radius of outer circle = Radius of inner circle + Width of path

= (14 + 3.5 ) m

= 17.5 m

We know that Area of a circle = r^{2}

Area of the path = Area of outer circle – Area of inner circle

= × (17.5)^{2} - × 14^{2}

= ( 17.5 – 14)(17.5 + 14)

(a^{2} – b^{2}) = (a – b)(a + b)

= × 3.5 × 31.5

= 346.5 m^{2}

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