Maths-
General
Easy

Question

The smallest value of theta satisfying the equation square root of 3 left parenthesis Cot space theta plus Tan space theta right parenthesis equals 4 IS

  1. fraction numerator 2 pi over denominator 3 end fraction
  2. pi over 3
  3. pi over 6
  4. pi over 12

The correct answer is: pi over 6

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A block of mass of 10 kg lies on a rough inclined plane of inclination theta equals s i n to the power of negative 1 end exponent invisible function application open parentheses fraction numerator 3 over denominator 5 end fraction close parentheses with the horizontal when a force of 30N is applied on the block parallel to and upward the plane, the total force exerted by the plane on the block is nearly along (coefficient of friction is µ = fraction numerator 3 over denominator 4 end fraction ) ( g = 10 m/S subscript equals end subscript superscript 2 end superscript )

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A block of mass 3 kg is at rest on a rough inclined plane as shown in the figure. The magnitude of net force exerted by the surface on the block will be (g=10 m/S subscript equals end subscript superscript 2 end superscript )

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