A block of mass of 10 kg lies on a rough inclined plane of inclination theta equals s i n to the power of negative 1 end exponent invisible function application open parentheses fraction numerator 3 over denominator 5 end fraction close parentheses with the horizontal when a force of 30N is applied on the block parallel to and upward the plane, the total force exerted by the plane on the block is nearly along (coefficient of friction is µ = fraction numerator 3 over denominator 4 end fraction ) ( g = 10 m/S subscript equals end subscript superscript 2 end superscript )

  1. OA    
  2. OB    
  3. OC    
  4. OD    

The correct answer is: OB

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