Maths-
General
Easy

Question

Total number of solutions of the equation 3x + 2 tan x =fraction numerator 5 straight pi over denominator 2 end fraction in x element of [0, 2straight pi] is equal to

  1. 1
  2. 2
  3. 3
  4. 4

hintHint:

Here, we have given is 3x + 2 tanx = fraction numerator 5 straight pi over denominator 2 end fraction. We have to find how many solutions it has. Firstly, separate the tanx. And draw the graph for tanx and find the intersection point this equation. The intersection point is solution It given region to [ 0, 2π].

The correct answer is: 1


    Here we have to find the how many solutions it has.
    Firstly, the equation is
    3x + 2 tanx = fraction numerator 5 straight pi over denominator 2 end fraction
    2tanx = fraction numerator 5 straight pi over denominator 2 end fraction – 3x
    tanx =fraction numerator 5 straight pi over denominator 4 end fraction3 over 23/2 x
    let y = tanx ; y = fraction numerator 5 straight pi over denominator 4 end fraction3 over 2 x
    Now using graph,
    At x = 0, y = fraction numerator 5 straight pi over denominator 4 end fraction
    And at y = 0, x = fraction numerator 5 straight pi over denominator 6 end fraction
    Given region of graph is [ 0, 2π ] .
    Hence, according to graph it intersects = 3 so it has 3 number of solutions
    Therefore, the correct answer is 3

    In this question, we use the graph of tanx . The intersection is the total number of solutions of this equation. The graph region is [ 0, 2π ].

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