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5 cos space theta plus 3 cos space open parentheses theta minus pi over 3 close parentheses plus 8 element of

Maths-General

  1. left square bracket negative 7 comma 1 right square bracket
  2. left square bracket 1 comma 8 right square bracket
  3. left square bracket 2 comma 15 right square bracket
  4. left square bracket 1 comma 15 right square bracket

    Answer:The correct answer is: left square bracket 1 comma 15 right square bracket

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    General
    maths-

    cos space open parentheses x plus pi over 6 close parentheses cos space open parentheses x minus pi over 6 close parentheses element of

    cos space open parentheses x plus pi over 6 close parentheses cos space open parentheses x minus pi over 6 close parentheses element of

    maths-General
    General
    maths-

    left parenthesis sin space x minus cos space x right parenthesis squared plus cos squared space open parentheses pi over 4 minus x close parentheses element of

    left parenthesis sin space x minus cos space x right parenthesis squared plus cos squared space open parentheses pi over 4 minus x close parentheses element of

    maths-General
    General
    maths-

    does not exist Extreme Values; cos space invisible function application x plus sin to the power of 4 space x element of

    does not exist Extreme Values; cos space invisible function application x plus sin to the power of 4 space x element of

    maths-General
    General
    maths-

    For all values of theta,the values of 3 minus cos space theta plus cos space open parentheses theta plus pi over 3 close parentheses lie in the interval

    For all values of theta,the values of 3 minus cos space theta plus cos space open parentheses theta plus pi over 3 close parentheses lie in the interval

    maths-General
    General
    maths-

    left parenthesis sin space x plus cos space x right parenthesis squared plus cos squared space open parentheses pi over 4 plus x close parentheses element of

    left parenthesis sin space x plus cos space x right parenthesis squared plus cos squared space open parentheses pi over 4 plus x close parentheses element of

    maths-General
    General
    maths-

    If x equals sec space theta plus tan space theta comma y equals cosec space theta minus cot space theta text  then  end text y equals

    If x equals sec space theta plus tan space theta comma y equals cosec space theta minus cot space theta text  then  end text y equals

    maths-General
    General
    maths-

    The minimum and maximum values of cos space x plus 3 square root of 2 sin space open parentheses x plus pi over 4 close parentheses plus 6 are

    The minimum and maximum values of cos space x plus 3 square root of 2 sin space open parentheses x plus pi over 4 close parentheses plus 6 are

    maths-General
    General
    maths-

    The minimum and maximum values of  sin space open parentheses x plus pi over 4 close parentheses sin space open parentheses x minus pi over 4 close parentheses are

    The minimum and maximum values of  sin space open parentheses x plus pi over 4 close parentheses sin space open parentheses x minus pi over 4 close parentheses are

    maths-General
    General
    maths-

    sin squared space x plus cos to the power of 4 space x element of

    sin squared space x plus cos to the power of 4 space x element of

    maths-General
    General
    physics-

    A piston fitted in cylindrical pipe is pulled as shown in the figure. A tuning fork is sounded at open end and loudest sound is heard at open length 13cm, 41 cm and 69 cm, the frequency of tuning fork if velocity of sound is 350 m s to the power of negative 1 end exponent is

    In a closed organ pipe in which length of air-column can be increased or decreased, the first resonance occurs at lambda divided by 4 and second resonance occurs at 3 lambda divided by 4.
    Thus, at first resonance
    fraction numerator lambda over denominator 4 end fraction equals 13 blank horizontal ellipsis open parentheses i close parentheses
    And a second resonance
    fraction numerator 3 lambda over denominator 4 end fraction equals 41 blank horizontal ellipsis open parentheses i i close parentheses


    Subtracting Eq.(i) from Eq.(ii), we have
    fraction numerator 3 lambda over denominator 4 end fraction minus fraction numerator lambda over denominator 4 end fraction equals 41 minus 13
    ⟹ fraction numerator lambda over denominator 2 end fraction equals 28
    therefore blank lambda equals 56 blank c m
    Hence, frequency of tuning fork
    v equals fraction numerator v over denominator lambda end fraction equals fraction numerator 350 over denominator 56 cross times 10 to the power of negative 2 end exponent end fraction equals 365 blank H z

    A piston fitted in cylindrical pipe is pulled as shown in the figure. A tuning fork is sounded at open end and loudest sound is heard at open length 13cm, 41 cm and 69 cm, the frequency of tuning fork if velocity of sound is 350 m s to the power of negative 1 end exponent is

    physics-General
    In a closed organ pipe in which length of air-column can be increased or decreased, the first resonance occurs at lambda divided by 4 and second resonance occurs at 3 lambda divided by 4.
    Thus, at first resonance
    fraction numerator lambda over denominator 4 end fraction equals 13 blank horizontal ellipsis open parentheses i close parentheses
    And a second resonance
    fraction numerator 3 lambda over denominator 4 end fraction equals 41 blank horizontal ellipsis open parentheses i i close parentheses


    Subtracting Eq.(i) from Eq.(ii), we have
    fraction numerator 3 lambda over denominator 4 end fraction minus fraction numerator lambda over denominator 4 end fraction equals 41 minus 13
    ⟹ fraction numerator lambda over denominator 2 end fraction equals 28
    therefore blank lambda equals 56 blank c m
    Hence, frequency of tuning fork
    v equals fraction numerator v over denominator lambda end fraction equals fraction numerator 350 over denominator 56 cross times 10 to the power of negative 2 end exponent end fraction equals 365 blank H z
    General
    physics-

    In a sine wave, position of different particles at time t equals 0 is shown in figure. The equation for this wave travelling along positive x minus a x i s can be

    As is clear from figure, att equals 0 comma x equals 0, displacementy equals 0. Therefore, option (a)or (d)may be correct.
    In case of (d);y equals A sin invisible function application left parenthesis k x minus omega t right parenthesis
    fraction numerator d y over denominator d t end fraction equals A cos invisible function application left parenthesis k x minus omega t right parenthesis open square brackets negative omega close square brackets
    fraction numerator d y over denominator d x end fraction equals A cos invisible function application left parenthesis k x minus omega t right parenthesis open square brackets k close square brackets
    fraction numerator fraction numerator d y over denominator d t end fraction over denominator d y divided by d x end fraction equals fraction numerator negative omega A cos invisible function application left parenthesis k x minus omega t right parenthesis over denominator k A cos invisible function application left parenthesis k x minus omega t right parenthesis end fraction equals negative fraction numerator omega over denominator k end fraction equals negative v
    fraction numerator d y over denominator d t end fraction equals negative v open parentheses fraction numerator d y over denominator d x end fraction close parentheses
    i e blank p a r t i c l e blank v e l o c i t y equals negative left parenthesis w a v e blank s p e e d right parenthesis cross times s l o p e.
    And slope at x equals 0 and t equals 0is positive, in figure. Therefore, particle velocity is in negative y-direction.

    In a sine wave, position of different particles at time t equals 0 is shown in figure. The equation for this wave travelling along positive x minus a x i s can be

    physics-General
    As is clear from figure, att equals 0 comma x equals 0, displacementy equals 0. Therefore, option (a)or (d)may be correct.
    In case of (d);y equals A sin invisible function application left parenthesis k x minus omega t right parenthesis
    fraction numerator d y over denominator d t end fraction equals A cos invisible function application left parenthesis k x minus omega t right parenthesis open square brackets negative omega close square brackets
    fraction numerator d y over denominator d x end fraction equals A cos invisible function application left parenthesis k x minus omega t right parenthesis open square brackets k close square brackets
    fraction numerator fraction numerator d y over denominator d t end fraction over denominator d y divided by d x end fraction equals fraction numerator negative omega A cos invisible function application left parenthesis k x minus omega t right parenthesis over denominator k A cos invisible function application left parenthesis k x minus omega t right parenthesis end fraction equals negative fraction numerator omega over denominator k end fraction equals negative v
    fraction numerator d y over denominator d t end fraction equals negative v open parentheses fraction numerator d y over denominator d x end fraction close parentheses
    i e blank p a r t i c l e blank v e l o c i t y equals negative left parenthesis w a v e blank s p e e d right parenthesis cross times s l o p e.
    And slope at x equals 0 and t equals 0is positive, in figure. Therefore, particle velocity is in negative y-direction.
    General
    maths-

    The function sin space open parentheses x squared close parentheses plus cosplus cos space square root of x is

    The function sin space open parentheses x squared close parentheses plus cosplus cos space square root of x is

    maths-General
    General
    maths-

    0 less or equal than a less or equal than 3 comma 0 less or equal than b less or equal than 3 and the equation x squared plus 4 plus 3 cos space left parenthesis a x plus b right parenthesis equals 2 x has at least one solution then the value of (a+b)

    0 less or equal than a less or equal than 3 comma 0 less or equal than b less or equal than 3 and the equation x squared plus 4 plus 3 cos space left parenthesis a x plus b right parenthesis equals 2 x has at least one solution then the value of (a+b)

    maths-General
    General
    maths-

    If fraction numerator sin to the power of 4 space theta over denominator a end fraction plus fraction numerator cos to the power of 4 begin display style space end style theta over denominator b end fraction equals fraction numerator 1 over denominator a plus b end fraction text  then  end text fraction numerator sin to the power of 8 begin display style text end text end style theta over denominator a cubed end fraction plus fraction numerator cos to the power of 8 begin display style space end style theta over denominator b cubed end fraction equals

    If fraction numerator sin to the power of 4 space theta over denominator a end fraction plus fraction numerator cos to the power of 4 begin display style space end style theta over denominator b end fraction equals fraction numerator 1 over denominator a plus b end fraction text  then  end text fraction numerator sin to the power of 8 begin display style text end text end style theta over denominator a cubed end fraction plus fraction numerator cos to the power of 8 begin display style space end style theta over denominator b cubed end fraction equals

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    General
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    The period of the function f left parenthesis x right parenthesis equals left square bracket 6 x plus 7 right square bracket plus cos space pi x minus 6 x where [.] de-notes the greatest integer function, is

    The period of the function f left parenthesis x right parenthesis equals left square bracket 6 x plus 7 right square bracket plus cos space pi x minus 6 x where [.] de-notes the greatest integer function, is

    maths-General