Mathematics
Grade6
Easy

Question

3 over 2 divided by 1 fourth

  1. 4
  2. 6
  3. 7
  4. 8

Hint:

The first step to dividing fractions is to find the reciprocal (reverse the numerator and denominator) of the second fraction. Next, multiply the two numerators. Then, multiply the two denominators. Finally, simplify the fractions if needed.

The correct answer is: 6


    Here, we have to divide 3⁄2 by ¼.
    We have, 3⁄2 ÷ ¼
    = 3⁄2 × 4
    = 12⁄2
    = 6.
    Hence, the correct option is B.

    Dividing two fractions is the same as multiplying the first fraction by the reciprocal of the second fraction.

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    Here, we are given that piper uses 1/5 meter of ribbon to border around a triangle of equal side length. We have to find the expression that describes the side length of the triangle.
    Total length of ribbon used = 1/5 meter.
    Number of sides of a triangle = 3.
    So, length of each side = 1⁄5 ÷ 3.
    Hence, the correct option is C.

    Piper used 1 fifth meter of ribbon to create a border around a triangle. If each side of the triangle is the same length, find the ribbon Piper used for each side. Select the correct equation representing the ribbon Piper used

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    Here, we are given that piper uses 1/5 meter of ribbon to border around a triangle of equal side length. We have to find the expression that describes the side length of the triangle.
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    5 ÷ 1 over 6

    Here, we have to divide 5 by 1⁄6.
    We have, 5 ÷ 1⁄6
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    Hence, the correct option is C.

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    MathematicsGrade6
    Here, we have to divide 5 by 1⁄6.
    We have, 5 ÷ 1⁄6
    = 5×6
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    6 ÷ 1 fourth

    Here, we have to divide 6 by ¼.
    We have, 6 ÷ ¼
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    Calculate 1 over 6 ÷ 2.

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    1⁄6 ÷ 2
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    1 over 6 cross times 1 over 7 =

    Step by step solution:
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    Step by step solution:
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    In the given question, 1 over 6 cross times 1 over 7 equals fraction numerator 1 cross times 1 over denominator 6 cross times 7 end fraction equals 1 over 42
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    1 fourth cross times 1 over 6 =

    Step by step solution:
    The way to multiply a fraction is by simply multiplying straight across. The product is also supposed to be a fraction so the numerator of the product will be the product of the numerators of the given numbers and the denominator of the product will be the product of the denominators of the given numbers.
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    In the given question, 1 fourth cross times 1 over 6 equals fraction numerator 1 cross times 1 over denominator 4 cross times 6 end fraction equals 1 over 24
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    Step by step solution:
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    Step by step solution:
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    2 over 5 cross times 3 over 7=

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    In the given question, 2 over 5 cross times 3 over 7 equals fraction numerator 2 cross times 3 over denominator 5 cross times 7 end fraction equals 6 over 35
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    7 over 8 cross times 1 half=

    Step by step solution:
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    In the given question, 7 over 8 cross times 1 half space equals space fraction numerator 7 cross times 1 over denominator 8 cross times 2 end fraction equals 7 over 16
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    7 over 8 cross times 1 half=

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    Step by step solution:
    The way to multiply a fraction is by simply multiplying straight across. The product is also supposed to be a fraction so the numerator of the product will be the product of the numerators of the given numbers and the denominator of the product will be the product of the denominators of the given numbers.
    In the given question, 7 over 8 cross times 1 half space equals space fraction numerator 7 cross times 1 over denominator 8 cross times 2 end fraction equals 7 over 16
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    Maria bought 9 over 10 pounds of plums and grapes. The plums were 2 over 3 total weight. The plums’ weight is

    Step by step solution:
    Given,
    total weight of plums and grapes = 9 over 10 pounds
    weight fraction of the plums = 2 over 3
    Thus, weight of the plums = 2 over 3 o f space 9 over 10
    2 over 3 cross times 9 over 10
    fraction numerator 2 cross times 9 over denominator 3 cross times 10 end fraction = 18 over 30 = 3 over 5 (in its simplest form)
    Thus, the plums' weight is 3 over 5 pounds.
    Thus, option (d) is the correct option.

    Maria bought 9 over 10 pounds of plums and grapes. The plums were 2 over 3 total weight. The plums’ weight is

    MathematicsGrade6
    Step by step solution:
    Given,
    total weight of plums and grapes = 9 over 10 pounds
    weight fraction of the plums = 2 over 3
    Thus, weight of the plums = 2 over 3 o f space 9 over 10
    2 over 3 cross times 9 over 10
    fraction numerator 2 cross times 9 over denominator 3 cross times 10 end fraction = 18 over 30 = 3 over 5 (in its simplest form)
    Thus, the plums' weight is 3 over 5 pounds.
    Thus, option (d) is the correct option.
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