Mathematics
Grade6
Easy

Question

Maria bought 9 over 10 pounds of plums and grapes. The plums were 2 over 3 total weight. The plums’ weight is

  1. 1 half pound
  2. 7 over 10 pound
  3. 3 over 7 pound
  4. 3 over 5 pound

Hint:

In the given question, total weight of grapes and plums bought by Maria is given. It is also provided that the plums were 2 over 3 of the total weight. It is required to find the total weight of the plums. For that, we need to simply find 2 over 3 of the total weight of plums and grapes, i.e., 9 over 10. So, we need to multiply 2 over 3 by 9 over 10.

The correct answer is: 3 over 5 pound


Step by step solution:
Given,
total weight of plums and grapes = 9 over 10 pounds
weight fraction of the plums = 2 over 3
Thus, weight of the plums = 2 over 3 o f space 9 over 10
2 over 3 cross times 9 over 10
fraction numerator 2 cross times 9 over denominator 3 cross times 10 end fraction = 18 over 30 = 3 over 5 (in its simplest form)
Thus, the plums' weight is 3 over 5 pounds.
Thus, option (d) is the correct option.

Related Questions to study

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MathematicsVideo

Chloe had 3 over 4 of a pizza left. Addie ate 1 over 6 of Chloe's pizza. The fraction of the pizza Addie ate is

Step by step solution:
Given,
Chloe had 3 over 4of a pizza left.
the fraction of pizza Addie ate from Chloe = 1 over 6
Therefore, the amount of pizza Chloe had = fraction numerator 1 over denominator 6 space end fraction o f space 3 over 4
1 over 6 cross times 3 over 4
fraction numerator 1 cross times 3 over denominator 6 cross times 4 end fraction = 3 over 24
3 over 24 in its simplest form is 1 over 8.
Hence, the fraction of pizza that Addie had is 3 over 24 or 1 over 8.
Hence, option (a) is the correct option.

Chloe had 3 over 4 of a pizza left. Addie ate 1 over 6 of Chloe's pizza. The fraction of the pizza Addie ate is

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Step by step solution:
Given,
Chloe had 3 over 4of a pizza left.
the fraction of pizza Addie ate from Chloe = 1 over 6
Therefore, the amount of pizza Chloe had = fraction numerator 1 over denominator 6 space end fraction o f space 3 over 4
1 over 6 cross times 3 over 4
fraction numerator 1 cross times 3 over denominator 6 cross times 4 end fraction = 3 over 24
3 over 24 in its simplest form is 1 over 8.
Hence, the fraction of pizza that Addie had is 3 over 24 or 1 over 8.
Hence, option (a) is the correct option.
Grade6
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Multiply the following fractions.
4 over 1 cross times 1 fifth

Step by step solution:
The way to multiply a fraction is by simply multiplying straight across. The product is also supposed to be a fraction so the numerator of the product will be the product of the numerators of the given numbers and the denominator of the product will be the product of the denominators of the given numbers.
In the given question,
4 over 1 cross times 1 fifth equals fraction numerator 4 cross times 1 over denominator 1 cross times 5 end fraction equals 4 over 5 (answer)
Thus, the correct option is option(a)

Multiply the following fractions.
4 over 1 cross times 1 fifth

MathematicsGrade6
Step by step solution:
The way to multiply a fraction is by simply multiplying straight across. The product is also supposed to be a fraction so the numerator of the product will be the product of the numerators of the given numbers and the denominator of the product will be the product of the denominators of the given numbers.
In the given question,
4 over 1 cross times 1 fifth equals fraction numerator 4 cross times 1 over denominator 1 cross times 5 end fraction equals 4 over 5 (answer)
Thus, the correct option is option(a)
Grade6
MathematicsVideo

Complete the multiplication sentence.

3 × ? = 3 over 7.

Step by step solution:
Given, 3 cross times space ? space equals 3 over 7
Let us consider the number required to be found as 'x'.
Now, the equation becomes 3 cross times x equals 3 over 7
rightwards double arrow space x space equals space 3 over 7 divided by 3
Now, we all know that in fraction division, we can simply reciprocate the number to the right of the 'divided by' sign and replace the 'divided by' sign with 'x' sign and perform multiplication.
Therefore, x equals 3 over 7 cross times 1 third
rightwards double arrow x equals 1 over 7
Here, the 3 in the numerator of the first fraction gets reduced by the 3 in the denominator of the second fraction.
Thus, we get x = 1 over 7 which is the required answer.
Hence, option (d) is the correct option.

Complete the multiplication sentence.

3 × ? = 3 over 7.

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Step by step solution:
Given, 3 cross times space ? space equals 3 over 7
Let us consider the number required to be found as 'x'.
Now, the equation becomes 3 cross times x equals 3 over 7
rightwards double arrow space x space equals space 3 over 7 divided by 3
Now, we all know that in fraction division, we can simply reciprocate the number to the right of the 'divided by' sign and replace the 'divided by' sign with 'x' sign and perform multiplication.
Therefore, x equals 3 over 7 cross times 1 third
rightwards double arrow x equals 1 over 7
Here, the 3 in the numerator of the first fraction gets reduced by the 3 in the denominator of the second fraction.
Thus, we get x = 1 over 7 which is the required answer.
Hence, option (d) is the correct option.
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Choose the correct answer.

Also, consider the multiplication sentence.
2 × ? = 3 over 4.

Choose the correct answer.

Also, consider the multiplication sentence.
2 × ? = 3 over 4.

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Two-thirds of the students in your class are boys. One-eighth of the boys play soccer. The fraction of the number of boys in your class who play soccer is.

Here, it is given that 2/3 pf the students in the class are boys and among the boys 1/8 of the boys play soccer. We have to find the fraction of boys who play soccer in the class.
Number of boys who play soccer = 2⁄3 × 1⁄8
= (2×1)⁄(3×8)
= 2⁄24
= 1⁄12.
Hence, the correct option is C.

Two-thirds of the students in your class are boys. One-eighth of the boys play soccer. The fraction of the number of boys in your class who play soccer is.

MathematicsGrade6
Here, it is given that 2/3 pf the students in the class are boys and among the boys 1/8 of the boys play soccer. We have to find the fraction of boys who play soccer in the class.
Number of boys who play soccer = 2⁄3 × 1⁄8
= (2×1)⁄(3×8)
= 2⁄24
= 1⁄12.
Hence, the correct option is C.
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MathematicsVideo

Name the operation you would use.
The bleachers at a football game are 7 over 8 full, and 1 half of the fans in the bleachers are rooting for the home team. Select the fraction of the bleachers filled with home-team fans.

We are given that 7/8 of the bleachers in a football game are full and 1/2 of the fans in the bleachers are supporting the home team. We have to find the operations by which we can find the number of fans in the bleachers supporting the home team.
Number of fans who are supporting the home team = 7⁄8 × ½
= 7⁄16.
So, 7/16 of the fans in the bleachers are supporting the home team and we found it by multiplication.
Hence, the correct option is A.

Name the operation you would use.
The bleachers at a football game are 7 over 8 full, and 1 half of the fans in the bleachers are rooting for the home team. Select the fraction of the bleachers filled with home-team fans.

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We are given that 7/8 of the bleachers in a football game are full and 1/2 of the fans in the bleachers are supporting the home team. We have to find the operations by which we can find the number of fans in the bleachers supporting the home team.
Number of fans who are supporting the home team = 7⁄8 × ½
= 7⁄16.
So, 7/16 of the fans in the bleachers are supporting the home team and we found it by multiplication.
Hence, the correct option is A.
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1 1 fourth cross times 2 3 over 4=

1 1 fourth cross times 2 3 over 4=

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A team of runners is needed to run a 1 fourth-mile relay race. If each runner must run 1 over 16 mile. Find the number of runners they need to run the race.

Here, we have to find the number of runners needed to complete a ¼ mile relay race if each runner must run 1⁄16 mile.
Let the number of runners needed be x.
Then, x × 1⁄16 = ¼
=> x = ¼ ÷ 1⁄16
=> x = ¼ × 16
=> x = 4.
So, the number runners needed is 4 and the correct option is A.

A team of runners is needed to run a 1 fourth-mile relay race. If each runner must run 1 over 16 mile. Find the number of runners they need to run the race.

MathematicsGrade6
Here, we have to find the number of runners needed to complete a ¼ mile relay race if each runner must run 1⁄16 mile.
Let the number of runners needed be x.
Then, x × 1⁄16 = ¼
=> x = ¼ ÷ 1⁄16
=> x = ¼ × 16
=> x = 4.
So, the number runners needed is 4 and the correct option is A.
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Multiply 2 over 6 cross times 3 over 5.

Here, we have to multiply 2⁄6 and 3⁄5.
We have, 2⁄6 × 3⁄5
= (2×3)⁄(6×5)
= 6⁄30
= 1⁄5.
Hence, the correct option is A.

Multiply 2 over 6 cross times 3 over 5.

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Here, we have to multiply 2⁄6 and 3⁄5.
We have, 2⁄6 × 3⁄5
= (2×3)⁄(6×5)
= 6⁄30
= 1⁄5.
Hence, the correct option is A.
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Simplify 1 third cross times 1 over 6=

Here, we have to multiply 1⁄3 and 1⁄6.
We have, 1⁄3 × 1⁄6
= (1×1)⁄(3×6)
= 1⁄18.
Hence, the correct option is A.

Simplify 1 third cross times 1 over 6=

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Here, we have to multiply 1⁄3 and 1⁄6.
We have, 1⁄3 × 1⁄6
= (1×1)⁄(3×6)
= 1⁄18.
Hence, the correct option is A.
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Simplify 5 over 6 cross times 2 over 3

Here, we have to multiply 5⁄6 and 2⁄3.
We have, 5⁄6 × 2⁄3
= (5×2)⁄(6×3)
= 10⁄18.
Hence, the correct option is A.

Simplify 5 over 6 cross times 2 over 3

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Here, we have to multiply 5⁄6 and 2⁄3.
We have, 5⁄6 × 2⁄3
= (5×2)⁄(6×3)
= 10⁄18.
Hence, the correct option is A.
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Simplify 3 over 5 cross times 2 over 9

Here, we have to multiply 3⁄5 and 2⁄9.
We have, 3⁄5 × 2⁄9
= (3×2)⁄(5×9)
= 6⁄45.
Hence, the correct option is B.

Simplify 3 over 5 cross times 2 over 9

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Here, we have to multiply 3⁄5 and 2⁄9.
We have, 3⁄5 × 2⁄9
= (3×2)⁄(5×9)
= 6⁄45.
Hence, the correct option is B.
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Simplify 3 over 5 cross times 3 over 8

Here, we have to find the product of 3⁄5 and 3⁄8.
We have, 3⁄5 × 3⁄8
= (3×3)⁄(5×8)
= 9⁄40.
hence, the correct option is A.

Simplify 3 over 5 cross times 3 over 8

MathematicsGrade6
Here, we have to find the product of 3⁄5 and 3⁄8.
We have, 3⁄5 × 3⁄8
= (3×3)⁄(5×8)
= 9⁄40.
hence, the correct option is A.
Grade6
MathematicsVideo

3 over 8 cross times 2 over 3=

Step by step solution:
The way to multiply a fraction is by simply multiplying straight across. The product is also supposed to be a fraction so the numerator of the product will be the product of the numerators of the given numbers and the denominator of the product will be the product of the denominators of the given numbers.
In the given question, 3 over 8 cross times 2 over 3 equals 6 over 24
Now, the product that we have got is not in its simplest form. For that we need to divide both the numerator and the denominator by the HCF [ Highest Common Factor] of both the numbers, i.e., 6 in this question.
Hence, we get 6 over 24 equals 1 fourth
Thus, the correct option is option (a)

3 over 8 cross times 2 over 3=

MathematicsGrade6
Step by step solution:
The way to multiply a fraction is by simply multiplying straight across. The product is also supposed to be a fraction so the numerator of the product will be the product of the numerators of the given numbers and the denominator of the product will be the product of the denominators of the given numbers.
In the given question, 3 over 8 cross times 2 over 3 equals 6 over 24
Now, the product that we have got is not in its simplest form. For that we need to divide both the numerator and the denominator by the HCF [ Highest Common Factor] of both the numbers, i.e., 6 in this question.
Hence, we get 6 over 24 equals 1 fourth
Thus, the correct option is option (a)
Grade6
MathematicsVideo

1 half cross times 4 over 5=

Step by step solution:
The way to multiply a fraction is by simply multiplying straight across. The product is also supposed to be a fraction so the numerator of the product will be the product of the numerators of the given numbers and the denominator of the product will be the product of the denominators of the given numbers.
In the given question, 1 half cross times 4 over 5 equals fraction numerator 1 cross times 4 over denominator 2 cross times 5 end fraction equals 4 over 10
Now, the product that we have got is not in its simplest form. For that we need to divide both the numerator and the denominator by the HCF [ Highest Common Factor] of both the numbers, i.e., 2 in this question.
Hence, 4 over 10 equals 2 over 5
Thus, the correct option is option (c)

1 half cross times 4 over 5=

MathematicsGrade6
Step by step solution:
The way to multiply a fraction is by simply multiplying straight across. The product is also supposed to be a fraction so the numerator of the product will be the product of the numerators of the given numbers and the denominator of the product will be the product of the denominators of the given numbers.
In the given question, 1 half cross times 4 over 5 equals fraction numerator 1 cross times 4 over denominator 2 cross times 5 end fraction equals 4 over 10
Now, the product that we have got is not in its simplest form. For that we need to divide both the numerator and the denominator by the HCF [ Highest Common Factor] of both the numbers, i.e., 2 in this question.
Hence, 4 over 10 equals 2 over 5
Thus, the correct option is option (c)
parallel

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