Mathematics
Grade6
Easy

Question

A train travels with a constant speed of 54 miles per hour. Distance travelled by the train in 30 minutes would be ____________.

  1. 25
  2. 31
  3. 35
  4. 27

hintHint:

In this question, we are given the speed of the train. It is 54 miles per hour. We are also given the time for which the train travels. It is 30 minutes. Using this data, we are asked to find the distance travelled by train in the given time. We can try to find an equation using these quantity to get the value.

The correct answer is: 27


    The given values of speed and time are as follows
    Speed = 54 miles per hour
    Time = 30 minutes 
    We have to find the distance travelled.
    We know the formula for speed.
                   S p e e d space equals fraction numerator D i s tan c e over denominator T i m e end fraction space
    e will rearrange the above formula for distance, as we don’t have it’s value
    We will multiply the L.H.S and R.H.S of the formula by time. .
    T i m e space cross times space s p e e d space equals space fraction numerator T i m e space cross times space D i s tan c e over denominator T i m e end fraction 
               Time × speed = Distance.
    Rearranging we get. 
            Distance = Speed × Time
    We will substitute the values of speed and time in above equation
    Before that, we will have to make the units same. So we will find the speed in miles per minute. The sleep is in miles per hour. So to convert it into miles per minute we will have to convert the hour into minutes. 1 hour means 60 minutes. So we will divide the speed by 60 minutes to get the value.
    S p e e d space equals fraction numerator 54 space m i l e s over denominator h o u r end fraction
space space space space space space space space space space space space space equals space fraction numerator 54 space m i l e s over denominator 1 cross times 60 space m i n u t e s end fraction
space space space space space space space space space space space space space equals space fraction numerator 27 space m i l e s over denominator 30 space m i n u t e end fraction
    We will substitute this value in the equation for distance
    We get
    Distance = Speed × Time.
    =  27 over 30 × 30
    = 27 miles
    Therefore, the distance travelled is 27 miles.
    So the option which is '27’, is the right option.

    We should be familiar with different units. To see if the ratio is right we can cross check the units of the quantities.

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