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Mathematics

Grade-7

Easy

Question

An elevator descends into a mine shaft from $3 6 over 10$ above the ground level. If it goes $8 6 over 10 m$ below the ground level, find the distance covered by the elevator.

12.0
12.1
12.2
12.4

hint Hint:

In this question we will simply add the distance covered by lift above the ground level and distance below the ground.

The correct answer is: 12.2

STEP BY STEP SOLUTION
Lift distance above ground = $3 6 over 10$
Lift distance below the ground = - $8 6 over 10$
To calculate the total distance covered by life we will simple add the the distance below the ground and distance above the ground
Distance covered by lift = $3 6 over 10 plus open vertical bar negative 8 6 over 10 close vertical bar equals 3 6 over 10 plus 8 6 over 10 equals 3.6 plus 8.6 equals 12.2$
So the total distance covered by lift = 12.2 units

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