Mathematics

Grade-7

Easy

Question

The distance between the two numbers represented (in red) on the number line is ______.

1.5
0.5
-1.8
-0.5

Hint:

To find the distance between two units we substract 2nd unit from the 1st.

The correct answer is: 0.5

STEP BY STEP SOLUTION
We know that the distance is the difference between the numbers.
|0.2 – 0.7|
| 0.5|
0.5 units.
So, the distance between 0.2 and 0.7 on a number line is 0.5 units

Edward bought 3 pencils of equal price of $4.20. The price of each pencil is __________.

STEP BY STEP SOLUTION
Price of 3 pencils = $4.20
Price of 1 pencil =

fraction numerator P r i c e space o f space 3 space p e n c i l s space over denominator 3 space p e n c i l s end fraction

4.20 space divided by space 3 fraction numerator 420 over denominator space 100 end fraction space divided by space 3 over 1 space equals space 420 over 100 space cross times space 1 third space equals space 420 over 300 space equals space 7 over 5

Edward bought 3 pencils of equal price of $4.20. The price of each pencil is __________.

MathematicsGrade-7

STEP BY STEP SOLUTION
Price of 3 pencils = $4.20
Price of 1 pencil =

fraction numerator P r i c e space o f space 3 space p e n c i l s space over denominator 3 space p e n c i l s end fraction

4.20 space divided by space 3 fraction numerator 420 over denominator space 100 end fraction space divided by space 3 over 1 space equals space 420 over 100 space cross times space 1 third space equals space 420 over 300 space equals space 7 over 5

Grade-7

Mathematics

The sum or difference of $negative 3.5 plus open parentheses negative 5 6 over 10 close parentheses$ is _____.

STEP BY STEP SOLUTION

negative 3.5 plus open parentheses negative 5 6 over 10 close parentheses W e space w i l l space c o n v e r t space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n space equals negative 3.5 space plus open parentheses negative 56 over 10 close parentheses N o w space w e space w i l l space c o n v e r t space f r a c t i o n space i n t o space d e c i m a l space o r space w e space c a n space a l s o space t a k e space L C M space a n d space t h e n space s o l v e space equals negative 3.5 minus 5.6 O n space s i m p l i f y i n g space w e space w i l l space g e t space equals negative 9.1

The sum or difference of $negative 3.5 plus open parentheses negative 5 6 over 10 close parentheses$ is _____.

MathematicsGrade-7

STEP BY STEP SOLUTION

negative 3.5 plus open parentheses negative 5 6 over 10 close parentheses W e space w i l l space c o n v e r t space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n space equals negative 3.5 space plus open parentheses negative 56 over 10 close parentheses N o w space w e space w i l l space c o n v e r t space f r a c t i o n space i n t o space d e c i m a l space o r space w e space c a n space a l s o space t a k e space L C M space a n d space t h e n space s o l v e space equals negative 3.5 minus 5.6 O n space s i m p l i f y i n g space w e space w i l l space g e t space equals negative 9.1

Grade-7

Mathematics

Determine the value of $fraction numerator negative 6 over denominator 9 end fraction space plus space open parentheses fraction numerator negative 4 over denominator 2 end fraction close parentheses$

STEP BY STEP SOLUTION

fraction numerator negative 6 over denominator 9 end fraction space plus space open parentheses fraction numerator negative 4 over denominator 2 end fraction close parentheses O p e n i n g space b r a c k e t s space space equals space fraction numerator negative 6 over denominator 9 end fraction space minus space 4 over 2 space T a k i n g space L C M thin space o f space 9 & 2 space left parenthesis i. e space 18 right parenthesis equals space fraction numerator negative 6 space cross times space 2 space minus space 4 space cross times space 9 over denominator 18 end fraction space equals space fraction numerator negative 12 space minus space 36 over denominator 18 end fraction space equals space 48 over 18 space equals space fraction numerator negative 24 over denominator 9 end fraction

Determine the value of $fraction numerator negative 6 over denominator 9 end fraction space plus space open parentheses fraction numerator negative 4 over denominator 2 end fraction close parentheses$

MathematicsGrade-7

STEP BY STEP SOLUTION

fraction numerator negative 6 over denominator 9 end fraction space plus space open parentheses fraction numerator negative 4 over denominator 2 end fraction close parentheses O p e n i n g space b r a c k e t s space space equals space fraction numerator negative 6 over denominator 9 end fraction space minus space 4 over 2 space T a k i n g space L C M thin space o f space 9 & 2 space left parenthesis i. e space 18 right parenthesis equals space fraction numerator negative 6 space cross times space 2 space minus space 4 space cross times space 9 over denominator 18 end fraction space equals space fraction numerator negative 12 space minus space 36 over denominator 18 end fraction space equals space 48 over 18 space equals space fraction numerator negative 24 over denominator 9 end fraction

Grade-7

Mathematics

The cost of $7 over 2$ meters of cloth is $ $231 over 4$ . The cost of one meter is __________.

STEP BY STEP SOLUTION
Cost of

7 over 2 space m

cloth = $

231 over 4

Cost of 1 meter cloth =

fraction numerator C o s t space o f space begin display style 7 over 2 end style m space c l o t h space over denominator begin display style 7 over 2 end style m end fraction

231 over 4 space divided by space 7 over 2 space equals space 231 over 2 space cross times space 2 over 7 space equals space 462 over 14 space equals space 33

Cost of 1 meter cloth = $33

The cost of $7 over 2$ meters of cloth is $ $231 over 4$ . The cost of one meter is __________.

MathematicsGrade-7

STEP BY STEP SOLUTION
Cost of

7 over 2 space m

cloth = $

231 over 4

Cost of 1 meter cloth =

fraction numerator C o s t space o f space begin display style 7 over 2 end style m space c l o t h space over denominator begin display style 7 over 2 end style m end fraction

231 over 4 space divided by space 7 over 2 space equals space 231 over 2 space cross times space 2 over 7 space equals space 462 over 14 space equals space 33

Cost of 1 meter cloth = $33

Grade-7

Mathematics

The sum or difference of $negative 2 1 fifth plus 1.03$ is ______.

STEP BY STEP SOLUTION

negative 2 1 fifth plus 1.03 C o n v e r t i n g space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n space equals negative 11 over 5 space plus space 1.03 C o n v e r t i n g space f r a c t i o n space i n t o space d e c i m a l s space equals negative 2.2 plus 1.03 equals negative 1.17

The sum or difference of $negative 2 1 fifth plus 1.03$ is ______.

MathematicsGrade-7

STEP BY STEP SOLUTION

negative 2 1 fifth plus 1.03 C o n v e r t i n g space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n space equals negative 11 over 5 space plus space 1.03 C o n v e r t i n g space f r a c t i o n space i n t o space d e c i m a l s space equals negative 2.2 plus 1.03 equals negative 1.17

Grade-7

Mathematics

The cost of each apple is $ $1 1 half$

STEP BY STEP SOLUTION
Cost of each apple =

$ 1 1 half

Cost of 8 apples = Cost of 1 apple

cross times

1 1 half space cross times space 8 over 1 space equals space 3 over 2 space cross times space 8 over 1 space equals space 24 over 2 space equals space 12

Cost of 8 apples = $12

The cost of each apple is $ $1 1 half$

MathematicsGrade-7

STEP BY STEP SOLUTION
Cost of each apple =

$ 1 1 half

Cost of 8 apples = Cost of 1 apple

cross times

1 1 half space cross times space 8 over 1 space equals space 3 over 2 space cross times space 8 over 1 space equals space 24 over 2 space equals space 12

Cost of 8 apples = $12

Grade-7

Mathematics

The value of $3 1 half space plus space open parentheses fraction numerator negative 2 over denominator 4 end fraction close parentheses$ is __________.

STEP BY STEP SOLUTION

3 1 half space minus space 2 over 4 C o n v e r t i n g space m i x e d space f r a c t i o n space i n t o space s i m p l r space f r a c t i o n space space equals space 2 over 2 space minus space 2 over 4 space T a k i n g space L C M space o f space 2 & 4 space left parenthesis i. e space 4 right parenthesis equals space fraction numerator 14 space minus space 2 over denominator 4 end fraction space equals space 12 over 4 space equals space 3

The value of $3 1 half space plus space open parentheses fraction numerator negative 2 over denominator 4 end fraction close parentheses$ is __________.

MathematicsGrade-7

STEP BY STEP SOLUTION

3 1 half space minus space 2 over 4 C o n v e r t i n g space m i x e d space f r a c t i o n space i n t o space s i m p l r space f r a c t i o n space space equals space 2 over 2 space minus space 2 over 4 space T a k i n g space L C M space o f space 2 & 4 space left parenthesis i. e space 4 right parenthesis equals space fraction numerator 14 space minus space 2 over denominator 4 end fraction space equals space 12 over 4 space equals space 3

Grade-7

Mathematics

The sum or difference of $negative 3.8 minus open parentheses negative 2 8 over 10 close parentheses$ is _______.

STEP BY STEP SOLUTION

negative 3.8 minus open parentheses negative 2 8 over 10 close parentheses C o n v e r t i n g space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n equals negative 3.8 minus open parentheses negative 28 over 10 close parentheses O p e n i n g space b r a c k e t equals negative 3.8 plus space 28 over 10 N o w space c o n v e r t space f r a c t i o n space i n t o space d e c i m a l space o r space t a k e space L C M space equals negative 3.8 plus 2.8 equals negative 1.0 A n s w e r equals space minus 1.0

The sum or difference of $negative 3.8 minus open parentheses negative 2 8 over 10 close parentheses$ is _______.

MathematicsGrade-7

STEP BY STEP SOLUTION

negative 3.8 minus open parentheses negative 2 8 over 10 close parentheses C o n v e r t i n g space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n equals negative 3.8 minus open parentheses negative 28 over 10 close parentheses O p e n i n g space b r a c k e t equals negative 3.8 plus space 28 over 10 N o w space c o n v e r t space f r a c t i o n space i n t o space d e c i m a l space o r space t a k e space L C M space equals negative 3.8 plus 2.8 equals negative 1.0 A n s w e r equals space minus 1.0

Grade-7

Mathematics

Determine the value of $text (15) end text 1 1 fourth space plus space left parenthesis 15 right parenthesis space open parentheses negative 3 over 2 close parentheses$ .

STEP BY STEP SOLUTION
]

text  (15)1  end text 1 fourth plus left parenthesis 15 right parenthesis open parentheses negative 3 over 2 close parentheses T a k i n g space 15 space c o m m o n space f r o m space b o t h space equals space 15 open square brackets 1 1 fourth space plus space open parentheses negative 3 over 2 close parentheses close square brackets space C o n v e r t i n g space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n space a n d space o p e n i n g space b r a c k e t s equals space 15 open square brackets 5 over 4 space minus space 3 over 2 close square brackets space equals space 15 open square brackets fraction numerator 5 space minus space 6 over denominator 4 end fraction close square brackets space equals space 15 open parentheses fraction numerator negative 1 over denominator 4 end fraction close parentheses M i l t i p l y i n g space 15 space i n s i d e space b r a c k e t space equals space fraction numerator negative 15 over denominator 4 end fraction

Determine the value of $text (15) end text 1 1 fourth space plus space left parenthesis 15 right parenthesis space open parentheses negative 3 over 2 close parentheses$ .

MathematicsGrade-7

STEP BY STEP SOLUTION
]

text  (15)1  end text 1 fourth plus left parenthesis 15 right parenthesis open parentheses negative 3 over 2 close parentheses T a k i n g space 15 space c o m m o n space f r o m space b o t h space equals space 15 open square brackets 1 1 fourth space plus space open parentheses negative 3 over 2 close parentheses close square brackets space C o n v e r t i n g space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n space a n d space o p e n i n g space b r a c k e t s equals space 15 open square brackets 5 over 4 space minus space 3 over 2 close square brackets space equals space 15 open square brackets fraction numerator 5 space minus space 6 over denominator 4 end fraction close square brackets space equals space 15 open parentheses fraction numerator negative 1 over denominator 4 end fraction close parentheses M i l t i p l y i n g space 15 space i n s i d e space b r a c k e t space equals space fraction numerator negative 15 over denominator 4 end fraction

Grade-7

Mathematics

The sum or difference of $5 3 over 4 plus open parentheses negative 6 1 fourth close parentheses$ is _____.

STEP BY STEP SOLUTION

5 3 over 4 plus open parentheses negative 6 1 fourth close parentheses O p e n space t h e space b r a c k e t equals 5 3 over 4 minus 6 1 fourth C o n v e r t space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n equals 23 over 4 space minus space 25 over 4 N o w space t a k i n g space L c m space o r space w e space c a n space c o n v e r t space i t space i n space d e c i m a l s equals fraction numerator 23 minus 25 over denominator 4 end fraction equals fraction numerator negative 2 over denominator 4 end fraction space o r space minus 1 half

The sum or difference of $5 3 over 4 plus open parentheses negative 6 1 fourth close parentheses$ is _____.

MathematicsGrade-7

STEP BY STEP SOLUTION

5 3 over 4 plus open parentheses negative 6 1 fourth close parentheses O p e n space t h e space b r a c k e t equals 5 3 over 4 minus 6 1 fourth C o n v e r t space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n equals 23 over 4 space minus space 25 over 4 N o w space t a k i n g space L c m space o r space w e space c a n space c o n v e r t space i t space i n space d e c i m a l s equals fraction numerator 23 minus 25 over denominator 4 end fraction equals fraction numerator negative 2 over denominator 4 end fraction space o r space minus 1 half

Grade-7

Mathematics

The sum or difference of $5 over 9 plus fraction numerator negative 8 over denominator 9 end fraction$ is _________.

STEP BY STEP SOLUTION

5 over 9 plus open parentheses fraction numerator negative 8 over denominator 9 end fraction close parentheses O p e n i n g space b r a c k e t space equals 5 over 9 minus 8 over 9 T a k i n g space L C M thin space equals fraction numerator 5 minus 8 over denominator 9 end fraction equals fraction numerator negative 3 over denominator 9 end fraction

The sum or difference of $5 over 9 plus fraction numerator negative 8 over denominator 9 end fraction$ is _________.

MathematicsGrade-7

STEP BY STEP SOLUTION

5 over 9 plus open parentheses fraction numerator negative 8 over denominator 9 end fraction close parentheses O p e n i n g space b r a c k e t space equals 5 over 9 minus 8 over 9 T a k i n g space L C M thin space equals fraction numerator 5 minus 8 over denominator 9 end fraction equals fraction numerator negative 3 over denominator 9 end fraction

Grade-7

Mathematics

The sum or difference of $fraction numerator negative 4 over denominator 5 end fraction plus 7 over 5$ is ___________.

STEP BY STEP SOLUTION

fraction numerator negative 4 over denominator 5 end fraction plus 7 over 5 T a k i n g space L C M thin space o r space c o n v e r t i n g space i n t o space d e c i m a l s space equals fraction numerator negative 4 plus 7 over denominator 5 end fraction equals 3 over 5

The sum or difference of $fraction numerator negative 4 over denominator 5 end fraction plus 7 over 5$ is ___________.

MathematicsGrade-7

STEP BY STEP SOLUTION

fraction numerator negative 4 over denominator 5 end fraction plus 7 over 5 T a k i n g space L C M thin space o r space c o n v e r t i n g space i n t o space d e c i m a l s space equals fraction numerator negative 4 plus 7 over denominator 5 end fraction equals 3 over 5

Grade-7

Mathematics

Joseph has a rope measuring $5 1 third$ in. He wants to cut into pieces each of length $1 1 third$ in. long. The number of rope pieces he gets is ___________.

STEP BY STEP SOLUTION
Length of rope =

5 1 third i n.

Length of each piece =

1 1 third i n.

How many pieces of same length can be cut down = Length of the rope

divided by

Length of each piece
Number of pieces =

5 1 third space divided by space 1 1 third C o n v e r t i n g space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n space space equals space 16 over 3 space divided by space 4 over 3 space equals space 16 over 3 space cross times space 3 over 4 space equals space 48 over 12 space equals space 4

Number of pieces that can be cut from given rope =4

Joseph has a rope measuring $5 1 third$ in. He wants to cut into pieces each of length $1 1 third$ in. long. The number of rope pieces he gets is ___________.

MathematicsGrade-7

STEP BY STEP SOLUTION
Length of rope =

5 1 third i n.

Length of each piece =

1 1 third i n.

How many pieces of same length can be cut down = Length of the rope

divided by

Length of each piece
Number of pieces =

5 1 third space divided by space 1 1 third C o n v e r t i n g space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n space space equals space 16 over 3 space divided by space 4 over 3 space equals space 16 over 3 space cross times space 3 over 4 space equals space 48 over 12 space equals space 4

Number of pieces that can be cut from given rope =4

Grade-7

Mathematics

The sum or difference of $negative 5 over 11 minus open parentheses fraction numerator negative 8 over denominator 11 end fraction close parentheses$ is ____________.

STEP BY STEP SOLUTION

space minus 5 over 11 space plus space 8 over 11 T a k i n g space L C M thin space fraction numerator negative 5 space plus space 8 space over denominator 11 end fraction S i m p l i f y i n g space space 3 over 11

The answer of this question is

3 over 11

The sum or difference of $negative 5 over 11 minus open parentheses fraction numerator negative 8 over denominator 11 end fraction close parentheses$ is ____________.

MathematicsGrade-7

STEP BY STEP SOLUTION

space minus 5 over 11 space plus space 8 over 11 T a k i n g space L C M thin space fraction numerator negative 5 space plus space 8 space over denominator 11 end fraction S i m p l i f y i n g space space 3 over 11

The answer of this question is

3 over 11

Grade-7

Mathematics

The product of 0.3 × 0.4 is _________.

STEP BY STEP SOLUTION
Product of 0.3 × 0.4 = ?

0.3 space cross times space 0.4 space C o n v e r t i n g space d e c i m a l s space i n t o space f r a c t i o n s 3 over 10 space cross times space fraction numerator 4 over denominator 10 space end fraction equals space 12 over 100 N o w space c o n v e r t i n g space f r a c t i o n space i n t o space d e c i m a l space 12 over 100 equals space 0.12

The product of 0.3 × 0.4 is _________.

MathematicsGrade-7

STEP BY STEP SOLUTION
Product of 0.3 × 0.4 = ?

0.3 space cross times space 0.4 space C o n v e r t i n g space d e c i m a l s space i n t o space f r a c t i o n s 3 over 10 space cross times space fraction numerator 4 over denominator 10 space end fraction equals space 12 over 100 N o w space c o n v e r t i n g space f r a c t i o n space i n t o space d e c i m a l space 12 over 100 equals space 0.12

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Can’t find what you’re looking for?

The distance between the two numbers represented (in red) on the number line is ______.

1.5 0.5-1.8-0.5

To find the distance between two units we substract 2nd unit from the 1st.

The correct answer is: 0.5

STEP BY STEP SOLUTIONWe know that the distance is the difference between the numbers.|0.2 – 0.7|| 0.5|0.5 units.So, the distance between 0.2 and 0.7 on a number line is 0.5 units

So, the distance between 0.2 and 0.7 on a number line is 0.5 units

Related Questions to study

Edward bought 3 pencils of equal price of $4.20. The price of each pencil is __________.

Edward bought 3 pencils of equal price of $4.20. The price of each pencil is __________.

The sum or difference of is _____.

The sum or difference of is _____.

Determine the value of

Determine the value of

The cost of meters of cloth is $ . The cost of one meter is __________.

The cost of meters of cloth is $ . The cost of one meter is __________.

The sum or difference of is ______.

The sum or difference of is ______.

The cost of each apple is $

The cost of each apple is $

The value of is __________.

The value of is __________.

The sum or difference of is _______.

The sum or difference of is _______.

Determine the value of .

Determine the value of .

The sum or difference of is _____.

The sum or difference of is _____.

The sum or difference of is _________.

The sum or difference of is _________.

The sum or difference of is ___________.

The sum or difference of is ___________.

Joseph has a rope measuring in. He wants to cut into pieces each of length in. long. The number of rope pieces he gets is ___________.

Joseph has a rope measuring in. He wants to cut into pieces each of length in. long. The number of rope pieces he gets is ___________.

The sum or difference of is ____________.

The sum or difference of is ____________.

The product of 0.3 × 0.4 is _________.

The product of 0.3 × 0.4 is _________.

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1.5
0.5
-1.8
-0.5

STEP BY STEP SOLUTION
We know that the distance is the difference between the numbers.
|0.2 – 0.7|
| 0.5|
0.5 units.
So, the distance between 0.2 and 0.7 on a number line is 0.5 units

The sum or difference of $negative 3.5 plus open parentheses negative 5 6 over 10 close parentheses$ is _____.

The sum or difference of $negative 3.5 plus open parentheses negative 5 6 over 10 close parentheses$ is _____.

Determine the value of $fraction numerator negative 6 over denominator 9 end fraction space plus space open parentheses fraction numerator negative 4 over denominator 2 end fraction close parentheses$

Determine the value of $fraction numerator negative 6 over denominator 9 end fraction space plus space open parentheses fraction numerator negative 4 over denominator 2 end fraction close parentheses$

The cost of $7 over 2$ meters of cloth is $ $231 over 4$ . The cost of one meter is __________.

The cost of $7 over 2$ meters of cloth is $ $231 over 4$ . The cost of one meter is __________.

The sum or difference of $negative 2 1 fifth plus 1.03$ is ______.

The sum or difference of $negative 2 1 fifth plus 1.03$ is ______.

The cost of each apple is $ $1 1 half$

The cost of each apple is $ $1 1 half$

The value of $3 1 half space plus space open parentheses fraction numerator negative 2 over denominator 4 end fraction close parentheses$ is __________.

The value of $3 1 half space plus space open parentheses fraction numerator negative 2 over denominator 4 end fraction close parentheses$ is __________.

The sum or difference of $negative 3.8 minus open parentheses negative 2 8 over 10 close parentheses$ is _______.

The sum or difference of $negative 3.8 minus open parentheses negative 2 8 over 10 close parentheses$ is _______.

Determine the value of $text (15) end text 1 1 fourth space plus space left parenthesis 15 right parenthesis space open parentheses negative 3 over 2 close parentheses$ .

Determine the value of $text (15) end text 1 1 fourth space plus space left parenthesis 15 right parenthesis space open parentheses negative 3 over 2 close parentheses$ .

The sum or difference of $5 3 over 4 plus open parentheses negative 6 1 fourth close parentheses$ is _____.

The sum or difference of $5 3 over 4 plus open parentheses negative 6 1 fourth close parentheses$ is _____.

The sum or difference of $5 over 9 plus fraction numerator negative 8 over denominator 9 end fraction$ is _________.

The sum or difference of $5 over 9 plus fraction numerator negative 8 over denominator 9 end fraction$ is _________.

The sum or difference of $fraction numerator negative 4 over denominator 5 end fraction plus 7 over 5$ is ___________.

The sum or difference of $fraction numerator negative 4 over denominator 5 end fraction plus 7 over 5$ is ___________.

Joseph has a rope measuring $5 1 third$ in. He wants to cut into pieces each of length $1 1 third$ in. long. The number of rope pieces he gets is ___________.

Joseph has a rope measuring $5 1 third$ in. He wants to cut into pieces each of length $1 1 third$ in. long. The number of rope pieces he gets is ___________.

The sum or difference of $negative 5 over 11 minus open parentheses fraction numerator negative 8 over denominator 11 end fraction close parentheses$ is ____________.

The sum or difference of $negative 5 over 11 minus open parentheses fraction numerator negative 8 over denominator 11 end fraction close parentheses$ is ____________.