Maths-
General
Easy

Question

Compare ∠𝑅𝑂𝑄 and ∠𝑃𝑂𝑄

The correct answer is: 10 digres


    • Step by step explanation: 
      • Step 1:
      • Find ROQ:
    • Align the protractor with the ray OR on 90o as shown above. 
    • Start reading the outer scale from the 90°.
    • Step 2:
    • From the figure we can see that ray OR is aligned on mark 90o. And ray OQ is aligned on mark 130o.
    Hence, the measure of ROQ = (130o - 90o).

     ROQ = 40o.

    • Step 3:
    • Find POQ:
      • Align the protractor with the ray OP on 0o as shown above. 
      • Start reading the inner scale from the 0°.
      • Step 4:
      • From the figure we can see that ray OP is aligned on mark 0o. And ray OQ is aligned on mark 50o.
    Hence, the measure of POQ = 50o.

    POQ = 50o.

    • Step 5:
    • Compare ∠POQ and ∠ROQ
    Hence, ∠POQ is greater than ∠ROQ by 10o.
    • Final Answer:
    Hence, ∠POQ is greater than ∠ROQ by 10o.

    Related Questions to study

    General
    Maths-

    Fun- time Amusement park charges straight $ 12.50 for admission and then straight $ 0.75 per ride. Rivers edge park charges straight $ 18.50 for admission and then straight $ 0.50 per ride. For What number of rides is the cost the same at both parks?

    Ans :- The number of rides at which the cost the same at both parks is 24.
    Explanation :-
    Given the admission fee and per ride cost of both the parks .
    Let n be the no.of rides at which the costs are the same at both parks.
    Step 1:- find the total cost for n rides at Fun- time Amusement park.
    $12.50 for admission and then $0.75 per ride
    So, total cost = admission fee + no.of rides × cost per ride.
    Total cost at Fun- time Amusement park = $12.50 + n($0.75)
    Step 2:- find the total cost for n rides at Rivers edge park.
    $18.50 for admission and then $0.50 per ride
    So, total cost = admission fee + no.of rides × cost per ride.
    Total cost at Rivers edge park  = $18.50 + n($0.50)
    Step 3:- Equate both the costs to find n
    $18.50 + n($0.50) =  $12.50 + n($0.75)
    $18.50 -  $12.50 = n($0.75) - n($0.50)
    $6 = n($0.25)
    n = 6 × 4
    ∴n = 24
    ∴The number of rides at which the cost the same at both parks is 24.

    Fun- time Amusement park charges straight $ 12.50 for admission and then straight $ 0.75 per ride. Rivers edge park charges straight $ 18.50 for admission and then straight $ 0.50 per ride. For What number of rides is the cost the same at both parks?

    Maths-General
    Ans :- The number of rides at which the cost the same at both parks is 24.
    Explanation :-
    Given the admission fee and per ride cost of both the parks .
    Let n be the no.of rides at which the costs are the same at both parks.
    Step 1:- find the total cost for n rides at Fun- time Amusement park.
    $12.50 for admission and then $0.75 per ride
    So, total cost = admission fee + no.of rides × cost per ride.
    Total cost at Fun- time Amusement park = $12.50 + n($0.75)
    Step 2:- find the total cost for n rides at Rivers edge park.
    $18.50 for admission and then $0.50 per ride
    So, total cost = admission fee + no.of rides × cost per ride.
    Total cost at Rivers edge park  = $18.50 + n($0.50)
    Step 3:- Equate both the costs to find n
    $18.50 + n($0.50) =  $12.50 + n($0.75)
    $18.50 -  $12.50 = n($0.75) - n($0.50)
    $6 = n($0.25)
    n = 6 × 4
    ∴n = 24
    ∴The number of rides at which the cost the same at both parks is 24.

    General
    Maths-

    Identify the pair of congruent angles formed by the bannister
    lines.

    SOLUTION:
    HINT: Use the property of parallel lines angle rules.
    Complete step by step solution:
    Here we have,
    straight angle 1 equals straight angle 4(vertically opposite angles)
    straight angle 2 equals straight angle 3(vertically opposite angles)
    straight angle 1 equals straight angle 5(corresponding angles)
    straight angle 2 equals straight angle 6(corresponding angles)
    straight angle 3 equals straight angle 5 (co-interior angles)
    straight angle 4 equals straight angle 6  (co-interior angles)
    straight angle 3 equals straight angle 6 (alternate interior angles)
    straight angle 4 equals straight angle 5 (alternate interior angles)
    straight angle 2 equals straight angle 7 (alternate exterior angles)
    straight angle 1 equals straight angle 8 (alternate exterior angles)
    straight angle 3 equals straight angle 7(corresponding angles)
    straight angle 4 equals straight angle 8(corresponding angles)
    straight angle 5 equals straight angle 8(vertically opposite angles)
    straight angle 6 equals straight angle 7(vertically opposite angles)

    Identify the pair of congruent angles formed by the bannister
    lines.

    Maths-General
    SOLUTION:
    HINT: Use the property of parallel lines angle rules.
    Complete step by step solution:
    Here we have,
    straight angle 1 equals straight angle 4(vertically opposite angles)
    straight angle 2 equals straight angle 3(vertically opposite angles)
    straight angle 1 equals straight angle 5(corresponding angles)
    straight angle 2 equals straight angle 6(corresponding angles)
    straight angle 3 equals straight angle 5 (co-interior angles)
    straight angle 4 equals straight angle 6  (co-interior angles)
    straight angle 3 equals straight angle 6 (alternate interior angles)
    straight angle 4 equals straight angle 5 (alternate interior angles)
    straight angle 2 equals straight angle 7 (alternate exterior angles)
    straight angle 1 equals straight angle 8 (alternate exterior angles)
    straight angle 3 equals straight angle 7(corresponding angles)
    straight angle 4 equals straight angle 8(corresponding angles)
    straight angle 5 equals straight angle 8(vertically opposite angles)
    straight angle 6 equals straight angle 7(vertically opposite angles)
    General
    Maths-

    A Line passes through the points (4,19) and (9,24). Write a linear function in the form y = mx + b for this line.

    The two given points are (4 , 19) and (9 , 24).
    Using two – point form, equation of the line is
    (y – y1) = m (x – x1)  where  m = fraction numerator y subscript 2 minus y subscript 1 over denominator x subscript 2 minus x subscript 1 end fraction

    rightwards double arrow m = fraction numerator 24 minus 19 over denominator 9 minus 4 end fraction

         = 5 over 5 =  1
    Now,  equation of the line is (y – y1) = m (x – x1)
    (y – 19) = 1(x – 4)
    y – 19  =  x – 4
    y =  x – 4 + 19
    y = x + 15

    A Line passes through the points (4,19) and (9,24). Write a linear function in the form y = mx + b for this line.

    Maths-General
    The two given points are (4 , 19) and (9 , 24).
    Using two – point form, equation of the line is
    (y – y1) = m (x – x1)  where  m = fraction numerator y subscript 2 minus y subscript 1 over denominator x subscript 2 minus x subscript 1 end fraction

    rightwards double arrow m = fraction numerator 24 minus 19 over denominator 9 minus 4 end fraction

         = 5 over 5 =  1
    Now,  equation of the line is (y – y1) = m (x – x1)
    (y – 19) = 1(x – 4)
    y – 19  =  x – 4
    y =  x – 4 + 19
    y = x + 15

    parallel
    General
    Maths-

    Use the diagram to find the measure of the indicated angle. Then classify the angle.

    iii) ∠𝑃𝑂𝑆

    • Step by step explanation: 
      • Step 1:
    • Align the protractor with the ray PO as shown above. 
    • Start reading the outer scale from the 0°.
    • Step 2:
    • From the figure we can see that the ray OS is aligned on mark 180o.
    Hence, the measure of POS = 180o.

    POS = 180o.

    • Final Answer:
    Hence, ∠POS = 180o, is straight angle.

    Use the diagram to find the measure of the indicated angle. Then classify the angle.