Solve the system of equations by elimination :
4X - 3y =  - 9
3X + 2Y = - 11

The correct answer is: We can also solve these system of equations by making the coefficients of to be the same in both the equations.

Complete step by step solution:
Let 4x-3y=-9…(i)
and 3x+ 2y=-11….(ii)
On multiplying (i) with 3, we get 3(4x-3y=-9)
⇒12x - 9y = - 27…(iii)
On multiplying (ii) with 4, we get 4(3x + 2y = - 11)
⇒12x + 8y = - 44…(iv)
Now, we have the coefficients of  in (iii) and (iv) to be the same.
On subtracting (iii) from (iv),
we get LHS to be 12x + 8y - (12x - 9y) = 8y + 9y = 17y
and RHS to be - 44 - (- 27) = - 17
On equating LHS and RHS, we have 17y = - 17
⇒ y = - 1
On substituting the value of  in (i), we get 4x - 3 × - 1 = - 9

⇒ 4x + 3 = - 9

⇒ 4x = - 9 - 3

⇒ 4x = - 12

⇒ x = - 3
Hence we get x = - 3 and y= - 1
Note: We can also solve these system of equations by making the coefficients of
to be the same in both the equations.