Maths-
General
Easy

Question

Find the sum which will amount to Rs. 364.80 at 31 half % per annum in 8 years at simple interest

Hint:

Use the formula of total amount and proceed.

The correct answer is: Rs 285.


    Complete step by step solution:
    Let the sum of money = P
    We know the formula for total amount = A = P + SI
    where A is the total amount, T is the principal amount and R is simple interest.
    We know that S I equals fraction numerator P T R over denominator 100 end fraction
    where P is Principal amount, T is number of years and R is rate of interest
    So, A equals P plus fraction numerator P T R over denominator 100 end fraction…(i)
    Here, we have A equals 364.80 comma T equals 8 comma R equals 3 1 half equals 3.5 straight percent sign text  and  end text P equals ?
    On substituting these values in (i), we get 364.80 equals P plus fraction numerator p cross times 8 cross times 3.5 over denominator 100 end fraction
    On further simplifications, we get 364.80 equals P plus.28 P
    table attributes columnspacing 1em end attributes row cell not stretchy rightwards double arrow 1.28 P equals 364.80 end cell row cell not stretchy rightwards double arrow P equals R s 285 end cell end table
    Hence the sum of money P = Rs 285.

    Related Questions to study

    General
    Maths-

    The simple interest on a sum of money at the end of 3 years is of the sum itself. What rate percent was charged?

    Complete step by step solution:
    Let the sum of money = P
    It is given that SI is 3 over 16 times the sum itself = 3 over 16P.
    We calculate simple interest by the formula, S I equals fraction numerator P T R over denominator 100 end fraction
    where P is Principal amount, T is number of years and R is rate of interest
    Here, we have S I equals 3 over 16 P comma T equals 3 text  and  end text R equals ?
    On substituting the known values we get, 3 over 6 P equals fraction numerator P cross times 3 cross times R over denominator 100 end fraction
    On further simplifications, we have 1 over 16 equals R over 100.
    not stretchy rightwards double arrow R equals 100 over 16 equals 6.25 straight percent sign

    The simple interest on a sum of money at the end of 3 years is of the sum itself. What rate percent was charged?

    Maths-General
    Complete step by step solution:
    Let the sum of money = P
    It is given that SI is 3 over 16 times the sum itself = 3 over 16P.
    We calculate simple interest by the formula, S I equals fraction numerator P T R over denominator 100 end fraction
    where P is Principal amount, T is number of years and R is rate of interest
    Here, we have S I equals 3 over 16 P comma T equals 3 text  and  end text R equals ?
    On substituting the known values we get, 3 over 6 P equals fraction numerator P cross times 3 cross times R over denominator 100 end fraction
    On further simplifications, we have 1 over 16 equals R over 100.
    not stretchy rightwards double arrow R equals 100 over 16 equals 6.25 straight percent sign
    General
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    A theatre company uses the revenue function R left parenthesis x right parenthesis equals negative 50 x squared plus 250 x dollars. The cost functions of the production C left parenthesis x right parenthesis equals 450 minus 50 x. What ticket price is needed for the theatre to break even?


    A theatre company uses the revenue function R left parenthesis x right parenthesis equals negative 50 x squared plus 250 x dollars. The cost functions of the production C left parenthesis x right parenthesis equals 450 minus 50 x. What ticket price is needed for the theatre to break even?

    Maths-General

    General
    Maths-

    Rewrite the equation as a system of equations, and then use a graph to solve.
    0.5 x squared plus 4 x equals negative 12 minus 1.5 x

    Hint:
    A graph is a geometrical representation of an equation or an expression. It can be used to find solutions of equation.
    We are asked to rewrite the equation as system of equations and graph them to solve it.
    Step 1 of 3:
    Equate each side of the equation to a new variable, y:




    Here we get two points where both the graphs intersect each other. The points are (-8, 0) and (-3, -7.5). Thus, we can say that the solutions to the given set of equation are the points of intersection.
     Note:
    When you graph a quadratic equation find three coordinate points to get the curve. But when it is a linear equation, just two points would give the path of the line.

    Rewrite the equation as a system of equations, and then use a graph to solve.
    0.5 x squared plus 4 x equals negative 12 minus 1.5 x

    Maths-General
    Hint:
    A graph is a geometrical representation of an equation or an expression. It can be used to find solutions of equation.
    We are asked to rewrite the equation as system of equations and graph them to solve it.
    Step 1 of 3:
    Equate each side of the equation to a new variable, y:




    Here we get two points where both the graphs intersect each other. The points are (-8, 0) and (-3, -7.5). Thus, we can say that the solutions to the given set of equation are the points of intersection.
     Note:
    When you graph a quadratic equation find three coordinate points to get the curve. But when it is a linear equation, just two points would give the path of the line.
    parallel
    General
    Maths-

    Rewrite the equation as a system of equations, and then use a graph to solve.
    x squared minus 6 x equals 2 x minus 16



    Thus, the solutions are (0, 0) and (1, -14)
    Step 3 of 3:
    Plot the points and join them to get the respective graph.

    Here, there is just one point where both the graphs intersect each other. The point is (4, -8). Thus, we can say that the point is the solution of the set of equation.
    Note:
    When you graph a quadratic equation find three coordinate points to get the curve. But when it is a linear equation, just two points would give the path of the line.

    Rewrite the equation as a system of equations, and then use a graph to solve.
    x squared minus 6 x equals 2 x minus 16

    Maths-General


    Thus, the solutions are (0, 0) and (1, -14)
    Step 3 of 3:
    Plot the points and join them to get the respective graph.

    Here, there is just one point where both the graphs intersect each other. The point is (4, -8). Thus, we can say that the point is the solution of the set of equation.
    Note:
    When you graph a quadratic equation find three coordinate points to get the curve. But when it is a linear equation, just two points would give the path of the line.
    General
    Maths-

    Find the simple interest on Rs. 6500 at 14% per annum for 73 days?

    Complete step by step solution:
    We calculate simple interest by the formula, S I equals fraction numerator P T R over denominator 100 end fraction
    where P is Principal amount, T is number of years and R is rate of interest
    Here, we have P equals 6500 comma T equals 73 over 365 equals 1 fifth text  and  end text R equals 14 straight percent sign
    On substituting the known values we get, S I equals fraction numerator 6500 cross times 1 fifth cross times 14 over denominator 100 end fraction
    On further simplifications, we have S I equals 18200 over 100 equals 182 rupees.
    Thus, SI = 182 Rupees.

    Find the simple interest on Rs. 6500 at 14% per annum for 73 days?

    Maths-General
    Complete step by step solution:
    We calculate simple interest by the formula, S I equals fraction numerator P T R over denominator 100 end fraction
    where P is Principal amount, T is number of years and R is rate of interest
    Here, we have P equals 6500 comma T equals 73 over 365 equals 1 fifth text  and  end text R equals 14 straight percent sign
    On substituting the known values we get, S I equals fraction numerator 6500 cross times 1 fifth cross times 14 over denominator 100 end fraction
    On further simplifications, we have S I equals 18200 over 100 equals 182 rupees.
    Thus, SI = 182 Rupees.
    General
    Maths-

    Rewrite the equation as a system of equations, and then use a graph to solve.
    2 x squared plus 3 x equals 2 x plus 1





    Here, they graphs intersect at two point; (-1 -1) and (0.5, 2). This means that the solutions of the system of equation are (-1 -1) and (0.5, 2).
    Note:
    Solutions of a set of equation can be found by graphing the equations and finding the intersecting points. The points where they intersect are the solutions.

    Rewrite the equation as a system of equations, and then use a graph to solve.
    2 x squared plus 3 x equals 2 x plus 1

    Maths-General