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General

Easy

Question

# If a sphere of constant radius k passes through the origin and meets the axis in A, B, C then the centroid of the triangle ABC lies on

- 9 (x
^{2} + y^{2} + z^{2})= k^{2}
- 9 (x
^{2} + y^{2} + z^{2})= 4k^{2}
- x
^{2} + y^{2} + z^{2} = k^{2}
- x
^{2} + y^{2} + z^{2} = 4k^{2}

^{2}+ y^{2}+ z^{2})= k^{2}^{2}+ y^{2}+ z^{2})= 4k^{2}^{2}+ y^{2}+ z^{2}= k^{2}^{2}+ y^{2}+ z^{2}= 4k^{2}## The correct answer is: 9 (x^{2} + y^{2} + z^{2})= 4k^{2}

### In this question we should find the locus of the centroid of ABC

Hence option 2 is correct

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