Maths-
General
Easy

Question

If f open parentheses x plus y close parentheses equals f open parentheses x close parentheses f open parentheses y close parentheses and f open parentheses x close parentheses equals 1 plus g open parentheses x close parentheses h open parentheses x close parentheses where stack Lt with x rightwards arrow 0 below invisible function application g open parentheses x close parentheses equals 0 comma stack Lt with x rightwards arrow 0 below invisible function application h open parentheses x close parentheses exists, then f open parentheses x close parentheses is continuous on

  1. ϕ    
  2. R    
  3. R minus open curly brackets 0 close curly brackets    
  4. R minus open curly brackets 1 close curly brackets    

The correct answer is: R



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