Physics-
General
Easy
Question
A cube of aluminium of sides 0.1 m is subjected to a sharing force of 100 N. The top face of the cube is displaced through 0.02 cm with respect to the bottom face. The shearing strain would be
- 0.02
- 0.1
- 0.005
- 0.002
The correct answer is: 0.002
Shearing strain = 
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