Physics
A particle is projected vertically upwards with velocity .30 ms-1 Find the ratio of average speed and instantaneous velocity after 6s.[g=10 ms-1 ]
PhysicsGeneral
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maths-General
physics
A particle moves 4 m in the south direction. Then it moves 3 m in the west direction. The time taken by the particle is 2 second. What is the ratio between average speed and average velocity
A particle moves 4 m in the south direction. Then it moves 3 m in the west direction. The time taken by the particle is 2 second. What is the ratio between average speed and average velocity
physicsGeneral
physics-
In the adjacent figure is shown a closed path
A long straight conductor carrying a current
passes through
and perpendicular to the plane of the paper. Then which of the following holds good?

A long straight conductor carrying current
passes through
then by symmetry, all points of the circular path are equivalent and hence the magnitude of magnetic field should be same at these points.
The circulation of magnetic field along the circle is
(using Ampere’s law)
The circulation of magnetic field along the circle is
In the adjacent figure is shown a closed path
A long straight conductor carrying a current
passes through
and perpendicular to the plane of the paper. Then which of the following holds good?

physics-General
A long straight conductor carrying current
passes through
then by symmetry, all points of the circular path are equivalent and hence the magnitude of magnetic field should be same at these points.
The circulation of magnetic field along the circle is
(using Ampere’s law)
The circulation of magnetic field along the circle is
physics-
A current I enters a circular coil of radius R, branches into two parts and then recombines as shown in the circuit diagram

The resultant magnetic field at the centre of the coil is
Magnetic field a 

Magnetic field at

The resultant magnetic field at the centre

So, magnetic field become is zero.
Magnetic field at
The resultant magnetic field at the centre
So, magnetic field become is zero.
A current I enters a circular coil of radius R, branches into two parts and then recombines as shown in the circuit diagram

The resultant magnetic field at the centre of the coil is
physics-General
Magnetic field a 

Magnetic field at

The resultant magnetic field at the centre

So, magnetic field become is zero.
Magnetic field at
The resultant magnetic field at the centre
So, magnetic field become is zero.
physics-
The figure shows the cross-section of a long cylindrical conductor of radius a carrying a uniformly distributed current i. The magnetic field due to current at P is

The current enclosed with in the circle

Ampere’s law
gives

or
Ampere’s law
or
The figure shows the cross-section of a long cylindrical conductor of radius a carrying a uniformly distributed current i. The magnetic field due to current at P is

physics-General
The current enclosed with in the circle

Ampere’s law
gives

or
Ampere’s law
or
biology
In angiosperms, female gametophyte is represented by
In angiosperms, female gametophyte is represented by
biologyGeneral
physics-
A long insulated copper wire is closely wound as a spiral of N turns. The spiral has inner radius a and outer radius b. The spiral lies in the
plane and a steady current
flows through the wire. The Z-component of the magnetic field at the centre of the spiral is

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If we take a small strip of
at distance
from centre, then number of turns in this strip would be,

Magnetic field due to this element at the centre of the coil will be


Magnetic field due to this element at the centre of the coil will be
A long insulated copper wire is closely wound as a spiral of N turns. The spiral has inner radius a and outer radius b. The spiral lies in the
plane and a steady current
flows through the wire. The Z-component of the magnetic field at the centre of the spiral is

900553 |
physics-General
If we take a small strip of
at distance
from centre, then number of turns in this strip would be,

Magnetic field due to this element at the centre of the coil will be


Magnetic field due to this element at the centre of the coil will be
physics
The motion of a particle along a straight line is described by the function .X=(3T-2)2 Calculate the acceleration after 10 s.
The motion of a particle along a straight line is described by the function .X=(3T-2)2 Calculate the acceleration after 10 s.
physicsGeneral
physics
Rohit completes a semi circular path of radius R in 10 seconds. Calculate average speed and average velocity in ms-1.
Rohit completes a semi circular path of radius R in 10 seconds. Calculate average speed and average velocity in ms-1.
physicsGeneral
physics-
If Young’s modulus of elasticity Y for a material is one and half times its rigidity coefficient
the Poisson’s ratio
will be
Young’s modulus, 
We know that

⟹
We know that
⟹
If Young’s modulus of elasticity Y for a material is one and half times its rigidity coefficient
the Poisson’s ratio
will be
physics-General
Young’s modulus, 
We know that

⟹
We know that
⟹
physics
Given figure shows a graph at acceleration
time for a rectilinear motion. Find average acceleration in first 10 seconds

Given figure shows a graph at acceleration
time for a rectilinear motion. Find average acceleration in first 10 seconds

physicsGeneral
physics-
Four wires of the same material are stretched by the same load. Which one of them will elongate most if their dimensions are as follows
Because, wires of the same material are stretched by the same load. So, F and Y will be constant.
We can see that, L=100 cm and r = 1mm will elongate most.
Four wires of the same material are stretched by the same load. Which one of them will elongate most if their dimensions are as follows
physics-General
Because, wires of the same material are stretched by the same load. So, F and Y will be constant.
We can see that, L=100 cm and r = 1mm will elongate most.
physics-
Two thick wires and two thin wires, all of same material and same length, form a square in three different ways P,Q and R as shown in the figure. With correct connections shown, the magnetic field due to the current flow, at the centre of the loop will be zero in case of

In
and
current divides equally in two halves because of equal resistances in the two halves. Due to equal currents in two halves the magnetic field at the centre will be zero.
Two thick wires and two thin wires, all of same material and same length, form a square in three different ways P,Q and R as shown in the figure. With correct connections shown, the magnetic field due to the current flow, at the centre of the loop will be zero in case of

physics-General
In
and
current divides equally in two halves because of equal resistances in the two halves. Due to equal currents in two halves the magnetic field at the centre will be zero.
physics-
A current
is flowing through the loop. The direction of the current and the shape of the loop are as shown in the figure.
The magnetic field at the centre of the loop is
times.


(i) Magnetic field at the centre due to the curved portion 
According to right hand screw rule, the magnetic field will be into the plane of paper.

(ii) Magnetic field at
due to
is zero.
(iii) Magnetic field at the centre due to the curved portion
is
According to
right hand screw rule, the magnetic field will be into the plane of paper.
(iv) Magnetic field at
due to
is zero.
Hence, the resultant magnetic field at

According to right hand screw rule, the magnetic field will be into the plane of paper.

(ii) Magnetic field at
(iii) Magnetic field at the centre due to the curved portion
right hand screw rule, the magnetic field will be into the plane of paper.
(iv) Magnetic field at
Hence, the resultant magnetic field at
A current
is flowing through the loop. The direction of the current and the shape of the loop are as shown in the figure.
The magnetic field at the centre of the loop is
times.


physics-General
(i) Magnetic field at the centre due to the curved portion 
According to right hand screw rule, the magnetic field will be into the plane of paper.

(ii) Magnetic field at
due to
is zero.
(iii) Magnetic field at the centre due to the curved portion
is
According to
right hand screw rule, the magnetic field will be into the plane of paper.
(iv) Magnetic field at
due to
is zero.
Hence, the resultant magnetic field at

According to right hand screw rule, the magnetic field will be into the plane of paper.

(ii) Magnetic field at
(iii) Magnetic field at the centre due to the curved portion
right hand screw rule, the magnetic field will be into the plane of paper.
(iv) Magnetic field at
Hence, the resultant magnetic field at
physics-
A part of a long wire carrying a current
is bent into a circle of radius r as shown in figure. The net magnetic field at the centre O of the circular loop is

The magnitude of the magnetic field at point
due to straight part of wire is

is perpendicular to the plane of the page, directed upwards (right hand plam rule 1).
The field at the centre
due to the current loop of radius
is


is also perpendicular to the page, directed upwards (right hand screw rule).


The field at the centre

A part of a long wire carrying a current
is bent into a circle of radius r as shown in figure. The net magnetic field at the centre O of the circular loop is

physics-General
The magnitude of the magnetic field at point
due to straight part of wire is

is perpendicular to the plane of the page, directed upwards (right hand plam rule 1).
The field at the centre
due to the current loop of radius
is


is also perpendicular to the page, directed upwards (right hand screw rule).


The field at the centre
