Biology
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Question

Finding of Miller's experiment on origin of life has provided evidence for:

  1. Theory of biogenesis    
  2. Oparin-Haldane theory    
  3. Theory of special creation    
  4. Theory of organic evolution    

The correct answer is: Oparin-Haldane theory

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Related Questions to study

General
biology

The number of codons that code different amino acids is -

   

The number of codons that code different amino acids is -

biologyGeneral
   
General
maths-

Assertion (A):If a>0,b>0 and c>0, then (a+b+c)(1a+1b+1c)9Reason (R): For positive numbers a, b, c, AMGM

AMGM=1a+1b+1c3111--b¯a.c(1)D:x2-3x-4<0(x+1)(x-4)<01<x<4x2-3x+2>0Rejectx-2)(x-1)>0=x<1arx>2(a+b+c)3(abc)13(2)multiply (1) and (2)  

Assertion (A):If a>0,b>0 and c>0, then (a+b+c)(1a+1b+1c)9Reason (R): For positive numbers a, b, c, AMGM

maths-General
AMGM=1a+1b+1c3111--b¯a.c(1)D:x2-3x-4<0(x+1)(x-4)<01<x<4x2-3x+2>0Rejectx-2)(x-1)>0=x<1arx>2(a+b+c)3(abc)13(2)multiply (1) and (2)  
General
maths-

The length of the chord joining the points (4cosθ, 4sinθ) and (4cosθ+60°, 4sin(θ+60°)of the circle x2+y2=16 is

   

The length of the chord joining the points (4cosθ, 4sinθ) and (4cosθ+60°, 4sin(θ+60°)of the circle x2+y2=16 is

maths-General
   
General
maths-

Observe the following statements and choose correct answer Statement-I:A particle p moves along a straight line, starting from a fixed point ‘O’, obeying s=16+48t-t3.the direction of p when t=5 is along OP¯ Statement-II: For a particle moving on a line, if velocity v<0 then the body moves towards the initial point.

Statement -I:    

Observe the following statements and choose correct answer Statement-I:A particle p moves along a straight line, starting from a fixed point ‘O’, obeying s=16+48t-t3.the direction of p when t=5 is along OP¯ Statement-II: For a particle moving on a line, if velocity v<0 then the body moves towards the initial point.

maths-General
Statement -I:    
General
maths-

Statement ‐ I : The equation zz¯+a¯z+az¯+λ=0 where a is a complex number, represents a circle in Argand plane if λ is real. Statement ‐II : The radius of the circle zz¯+a¯z+az¯+λ=0 is λ-aa¯

Result    

Statement ‐ I : The equation zz¯+a¯z+az¯+λ=0 where a is a complex number, represents a circle in Argand plane if λ is real. Statement ‐II : The radius of the circle zz¯+a¯z+az¯+λ=0 is λ-aa¯

maths-General
Result    
General
GeneralVideo

Divide the following fractions:
2 over 11 divided by 9 over 22

Here, we have to divide the given fractions.
Now, 2/11 ÷ 9/22
= 2/11 × 22/9
= 2/1 × 2/9
= 2 × 2 / 1 × 9
= 4/9
Hence, the correct option is (a).

Divide the following fractions:
2 over 11 divided by 9 over 22

GeneralGeneral
Here, we have to divide the given fractions.
Now, 2/11 ÷ 9/22
= 2/11 × 22/9
= 2/1 × 2/9
= 2 × 2 / 1 × 9
= 4/9
Hence, the correct option is (a).
General
biology

The third cleavage in frog's development is

The third cleavage in frog's development is

biologyGeneral
General
biology

The reason why the right kidney is slightly lower than the left is:

Excretion involves the processes in which substances of no further use or those present in excess qualities are thrown out of the body.

The reason why the right kidney is slightly lower than the left is:

biologyGeneral
Excretion involves the processes in which substances of no further use or those present in excess qualities are thrown out of the body.
General
biology

This happens if the proximal convoluted tubule is removed from nephron:

This happens if the proximal convoluted tubule is removed from nephron:

biologyGeneral
General
Biology

Which is the highest structural organization found in all enzymes?

Which is the highest structural organization found in all enzymes?

BiologyGeneral
General
Biology

The 20 different common amino acids have different-

The 20 different common amino acids have different-

BiologyGeneral
General
Maths-

A box contains 100 tickets numbered 1, 2 ...... 100. Two tickets are chosen at random. It is given that the maximum number on the two chosen tickets is not more than 10. The minimum number on them is 5 with probability

Let A be the event that the maximum number on the two chosen tickets is not more than 10 i.e., the number on them less or equal than 10 and B be the event that the maximum number on them is 5, i.e., the number on them is greater or equal than 5 we have to find P left parenthesis B divided by A right parenthesis.
Now P left parenthesis B divided by A right parenthesis equals fraction numerator P left parenthesis A intersection B right parenthesis over denominator P left parenthesis A right parenthesis end fraction equals fraction numerator n left parenthesis A intersection B right parenthesis over denominator n left parenthesis A right parenthesis end fraction
Now the number of ways of getting a number r on the two tickets is the coefficient of x to the power of r end exponent in the expansion of
left parenthesis x to the power of 1 end exponent plus x to the power of 2 end exponent plus x to the power of 3 end exponent plus........ plus x to the power of 100 end exponent right parenthesis to the power of 2 end exponent equals x to the power of 2 end exponent left parenthesis 1 plus x plus....... plus x to the power of 99 end exponent right parenthesis to the power of 2 end exponent
equals x to the power of 2 end exponent open parentheses fraction numerator 1 minus x to the power of 100 end exponent over denominator 1 minus x end fraction close parentheses to the power of 2 end exponent equals x to the power of 2 end exponent left parenthesis 1 minus 2 x to the power of 100 end exponent plus x to the power of 200 end exponent right parenthesis left parenthesis 1 minus x right parenthesis to the power of negative 2 end exponent
equals x to the power of 2 end exponent left parenthesis 1 minus 2 x to the power of 100 end exponent plus x to the power of 200 end exponent right parenthesis left parenthesis 1 plus 2 x plus 3 x to the power of 2 end exponent plus.... plus left parenthesis r plus 1 right parenthesis x to the power of r end exponent plus..... right parenthesis Thus coefficient of x to the power of 2 end exponent equals 1 comma of x to the power of 3 end exponent equals 2 comma of x to the power of 4 end exponent equals 3...... of x to the power of 10 end exponent is 9.
Hence n left parenthesis A right parenthesis equals 1 plus 2 plus 3 plus 4 plus 5 plus 6 plus 7 plus 8 plus 9 equals 45
and n left parenthesis A intersection B right parenthesis equals 4 plus 5 plus 6 plus 7 plus 8 plus 9 equals 39
Hence required probability equals fraction numerator 39 over denominator 45 end fraction equals fraction numerator 13 over denominator 15 end fraction.

A box contains 100 tickets numbered 1, 2 ...... 100. Two tickets are chosen at random. It is given that the maximum number on the two chosen tickets is not more than 10. The minimum number on them is 5 with probability

Maths-General
Let A be the event that the maximum number on the two chosen tickets is not more than 10 i.e., the number on them less or equal than 10 and B be the event that the maximum number on them is 5, i.e., the number on them is greater or equal than 5 we have to find P left parenthesis B divided by A right parenthesis.
Now P left parenthesis B divided by A right parenthesis equals fraction numerator P left parenthesis A intersection B right parenthesis over denominator P left parenthesis A right parenthesis end fraction equals fraction numerator n left parenthesis A intersection B right parenthesis over denominator n left parenthesis A right parenthesis end fraction
Now the number of ways of getting a number r on the two tickets is the coefficient of x to the power of r end exponent in the expansion of
left parenthesis x to the power of 1 end exponent plus x to the power of 2 end exponent plus x to the power of 3 end exponent plus........ plus x to the power of 100 end exponent right parenthesis to the power of 2 end exponent equals x to the power of 2 end exponent left parenthesis 1 plus x plus....... plus x to the power of 99 end exponent right parenthesis to the power of 2 end exponent
equals x to the power of 2 end exponent open parentheses fraction numerator 1 minus x to the power of 100 end exponent over denominator 1 minus x end fraction close parentheses to the power of 2 end exponent equals x to the power of 2 end exponent left parenthesis 1 minus 2 x to the power of 100 end exponent plus x to the power of 200 end exponent right parenthesis left parenthesis 1 minus x right parenthesis to the power of negative 2 end exponent
equals x to the power of 2 end exponent left parenthesis 1 minus 2 x to the power of 100 end exponent plus x to the power of 200 end exponent right parenthesis left parenthesis 1 plus 2 x plus 3 x to the power of 2 end exponent plus.... plus left parenthesis r plus 1 right parenthesis x to the power of r end exponent plus..... right parenthesis Thus coefficient of x to the power of 2 end exponent equals 1 comma of x to the power of 3 end exponent equals 2 comma of x to the power of 4 end exponent equals 3...... of x to the power of 10 end exponent is 9.
Hence n left parenthesis A right parenthesis equals 1 plus 2 plus 3 plus 4 plus 5 plus 6 plus 7 plus 8 plus 9 equals 45
and n left parenthesis A intersection B right parenthesis equals 4 plus 5 plus 6 plus 7 plus 8 plus 9 equals 39
Hence required probability equals fraction numerator 39 over denominator 45 end fraction equals fraction numerator 13 over denominator 15 end fraction.
General
Biology

All are proteins except –

All are proteins except –

BiologyGeneral
General
Biology

Protein am ion acids are called.

Protein am ion acids are called.

BiologyGeneral
General
physics-

To double the volume of a given mass of an ideal gas at 27 ℃ keeping the pressure constant, one must raise the temperature in degree centigrade to

V proportional to T rightwards double arrow fraction numerator V subscript 1 end subscript over denominator V subscript 2 end subscript end fraction equals fraction numerator T subscript 1 end subscript over denominator T subscript 2 end subscript end fraction rightwards double arrow fraction numerator V over denominator 2 V end fraction equals fraction numerator open parentheses 273 plus 27 close parentheses over denominator T subscript 2 end subscript end fraction equals fraction numerator 300 over denominator T subscript 2 end subscript end fraction
rightwards double arrow T subscript 2 end subscript equals 600 K equals 327 ℃

To double the volume of a given mass of an ideal gas at 27 ℃ keeping the pressure constant, one must raise the temperature in degree centigrade to

physics-General
V proportional to T rightwards double arrow fraction numerator V subscript 1 end subscript over denominator V subscript 2 end subscript end fraction equals fraction numerator T subscript 1 end subscript over denominator T subscript 2 end subscript end fraction rightwards double arrow fraction numerator V over denominator 2 V end fraction equals fraction numerator open parentheses 273 plus 27 close parentheses over denominator T subscript 2 end subscript end fraction equals fraction numerator 300 over denominator T subscript 2 end subscript end fraction
rightwards double arrow T subscript 2 end subscript equals 600 K equals 327 ℃