Maths-
General
Easy

Question

Find the solution of the system of equations.
y equals negative 4 x squared plus x plus 1
y equals negative 7 x plus 1

hintHint:

An equation of the a x squared plus 2 a x equals 0 can be simplified into a x open parentheses x plus 2 close parentheses equals 0. This can be further solved by equating it to zero.
We are asked to solve the set of equation.

The correct answer is: We are asked to solve the set of equation.


    Step 1 of 3:
    The LHS of the given set of equation is the same. Hence, we can equate them;
    table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell negative 7 x plus 1 equals negative 4 x squared plus x plus 1 end cell row cell 4 x squared minus x minus 1 minus 7 x plus 1 equals 0 end cell row cell 4 x squared minus 8 x equals 0 space space space space space space space space space space space space space space space space space space end cell end table
    Step 2 of 3:
    Now, simplify the equation and solve for the variable x:
    table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell 4 x squared minus 8 x equals 0 end cell row cell 4 x left parenthesis x minus 8 right parenthesis equals 0 end cell row cell 4 x equals 0 space space space space space space space space space space space end cell row cell x equals 0 space space space space space space space space space space space space space space end cell row cell x minus 8 equals 0 space space space space space space space space space end cell row cell x equals 8 space space space space space space space space space space space space space space space end cell end table
    Thus, the solutions of the variable are:x equals 0 space & x equals 8
    Step 3 of 3:
    Find the value of y by substituting the values of x in any of the given equation.
    When x=0,
    table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell y equals negative 7 x plus 1 end cell row cell y equals 0 plus 1 space space space space space space end cell row cell y equals 1 space space space space space space space space space space space space end cell end table
    When x=8,
    table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell y equals negative 7 x plus 1 space space space end cell row cell y equals negative 7 left parenthesis 8 right parenthesis plus 1 end cell row cell y equals negative 56 plus 1 space space space end cell row cell y equals negative 55 space space space space space space space space space end cell end table
    Thus, the required sets of solutions are: (0, 1) and (8, -55)
     

    You can also solve a set of equation by graphing them. The points where the equations intersect all together would be their solutions.

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