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Maths-

General

Easy

Question

If $A equals 60 to the power of ring operator text then the value of end text open parentheses 1 plus a over c plus b over c close parentheses open parentheses 1 plus c over b minus a over b close parentheses equals$

3
2
1
$2 abc$

hint Hint:

To solve the given question $triangle$ ABC is given where $angle A equals 60 degree$ . For this we will use the cosine formula of triangles.

The correct answer is: 3

If $A equals 60 to the power of ring operator text then the value of end text open parentheses 1 plus a over c plus b over c close parentheses open parentheses 1 plus c over b minus a over b close parentheses equals$
$open parentheses fraction numerator c plus a plus b over denominator c end fraction close parentheses open parentheses fraction numerator b plus c minus a over denominator b end fraction close parentheses equals fraction numerator b c plus c squared minus a c plus a b plus a c minus a squared plus b squared plus b c minus a b over denominator c b end fraction equals fraction numerator 2 b c plus c squared plus b squared minus a squared over denominator c b end fraction equals fraction numerator 2 b c plus 2 b c space cos space A over denominator b c end fraction space space left parenthesis b y space cos i n e space f o r m u l a comma space a squared equals b squared plus c squared minus 2 b c space cos A right parenthesis equals 2 plus 2 space cos A p u t t i n g space A equals 60 degree equals 2 plus 2 space cos space 60 degree equals 2 plus 2 cross times 1 half equals 2 plus 1 equals 3$

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