Maths-

General

Easy

Question

ABC and DBC are two isosceles triangles on the same base BC. Show

that

Hint:

**Hint** :-As we know angles opposite to equal sides are equal .

## The correct answer is: Hence proved

### Aim :- Prove ∠ ABD = ∠ ACD

Explanation :-

In triangle ABC, AB = AC (isosceles triangle )

so, ∠ ABC = ∠ ACB

In triangle BDC, BD = DC (isosceles triangle )

∠ DBC =∠ DCB

Adding above results we get,

∠ABC + ∠ DBC = ∠ ACB + ∠ DCB

[ from diagram we get ∠ ABC + ∠ DBC = ∠ ABD and ∠ ACB + ∠ DCB = ACD

∠ ABD = ∠ACD

Hence proved

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