Maths-
General
Easy

Question


ABC and DBC are two isosceles triangles on the same base BC. Show
that straight angle ABD equals straight angle ACD

hintHint:

Hint :-As we know angles opposite to equal sides are equal .

The correct answer is: Hence proved


    Aim :- Prove ∠ ABD = ∠ ACD
    Explanation :-
    In triangle ABC, AB = AC (isosceles triangle )
    so, ∠ ABC = ∠ ACB
    In triangle BDC, BD = DC (isosceles triangle )
    ∠ DBC =∠ DCB
    Adding above results we get,
    ∠ABC  + ∠ DBC = ∠ ACB + ∠ DCB
    [ from diagram we get ∠ ABC  + ∠ DBC = ∠ ABD and ∠ ACB + ∠ DCB = ACD
     ∠ ABD = ∠ACD
    Hence proved

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