Maths-
General
Easy

Question

PQ and RS are respectively the smallest and longest sides of a quadrilateral PQRS. Show that ∠ P > ∠ R

hintHint:

Hint :-As we know angles opposite longer sides are greater
Angle opposite to smaller sides are smaller

The correct answer is: Hence proved


    Aim :- Prove ∠P  ∠R


     
    In triangle PQR,
    PQ < QR (PQ is smallest)
    so, ∠PRQ ∠QPR
    In triangle PSR,
    PS < SR  (RS is longest side)
    ∠ PRS ∠ RPS
    Adding above results we get,
    ∠PRQ + ∠PRS ∠QPR + ∠RPS
    ∠R  ∠P
    Hence proved

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