Assertion : f(x)=sgn(x-|x|) can never become positive. reason -Turito

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Assertion : $f left parenthesis x right parenthesis equals s g n left parenthesis x minus vertical line x vertical line right parenthesis$ can never become positive.
Reason : f(x) = sgn x is always a positive function.

Maths-General

If both (A) and (R) are true but (R) is not the correct explanation of (A) .
If (A) is true but (R) is false.
If (A) is false but (R) is true.
If both (A) and (R) are true, and (R) is the correct explanation of (A) .

Answer:The correct answer is: If (A) is false but (R) is true.

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Assertion: The function defined by $f left parenthesis x right parenthesis equals x to the power of 3 end exponent plus a x to the power of 2 end exponent plus b x plus c$ is invertible if and only if $a to the power of 2 end exponent less or equal than 3 b$ .
Reason: A function is invertible if and only if it is one-to-one and onto function.

Assertion: The function defined by $f left parenthesis x right parenthesis equals x to the power of 3 end exponent plus a x to the power of 2 end exponent plus b x plus c$ is invertible if and only if $a to the power of 2 end exponent less or equal than 3 b$ .
Reason: A function is invertible if and only if it is one-to-one and onto function.

Assertion : Fundamental period of $c o s invisible function application x plus c o t invisible function application x text is end text 2 pi$ .
Reason : If the period of f(x) is $T subscript 1 end subscript$ and the period of g(x) is $T subscript 2 end subscript$ , then the fundamental period of f(x) + g(x) is the L.C.M. of $T subscript 1 end subscript$ and T

Assertion : Fundamental period of $c o s invisible function application x plus c o t invisible function application x text is end text 2 pi$ .
Reason : If the period of f(x) is $T subscript 1 end subscript$ and the period of g(x) is $T subscript 2 end subscript$ , then the fundamental period of f(x) + g(x) is the L.C.M. of $T subscript 1 end subscript$ and T

Assertion: The period of $f left parenthesis x right parenthesis equals s i n invisible function application 2 x c o s invisible function application left square bracket 2 x right square bracket minus c o s invisible function application 2 x s i n invisible function application left square bracket 2 x right square bracket$ is 1/2.
Reason: The period of x – [x] is 1.

Assertion: The period of $f left parenthesis x right parenthesis equals s i n invisible function application 2 x c o s invisible function application left square bracket 2 x right square bracket minus c o s invisible function application 2 x s i n invisible function application left square bracket 2 x right square bracket$ is 1/2.
Reason: The period of x – [x] is 1.

If f (x) = $open curly brackets table row cell e to the power of cos invisible function application x end exponent end cell cell sin invisible function application x text for end text vertical line x vertical line less or equal than 2 end cell row cell text 2, end text end cell cell text otherwise end text end cell end table comma text then end text not stretchy integral subscript text -2 end text end subscript superscript 3 end superscript f left parenthesis x right parenthesis d x equals close$

If f (x) = $open curly brackets table row cell e to the power of cos invisible function application x end exponent end cell cell sin invisible function application x text for end text vertical line x vertical line less or equal than 2 end cell row cell text 2, end text end cell cell text otherwise end text end cell end table comma text then end text not stretchy integral subscript text -2 end text end subscript superscript 3 end superscript f left parenthesis x right parenthesis d x equals close$

The value of the integral $not stretchy integral subscript e to the power of negative 1 end exponent end subscript superscript e to the power of 2 end exponent end superscript open vertical bar fraction numerator log subscript e end subscript invisible function application blank x over denominator x end fraction close vertical bar$ dx is :

The value of the integral $not stretchy integral subscript e to the power of negative 1 end exponent end subscript superscript e to the power of 2 end exponent end superscript open vertical bar fraction numerator log subscript e end subscript invisible function application blank x over denominator x end fraction close vertical bar$ dx is :

Assertion : Let $f colon R minus left curly bracket 1 , 2 comma 3 right curly bracket rightwards arrow R$ be a function defined by f(x) = $fraction numerator 1 over denominator x minus 1 end fraction plus fraction numerator 2 over denominator x minus 2 end fraction plus fraction numerator 3 over denominator x minus 3 end fraction$ . Then f is many-one function.
Reason : If either $f apostrophe left parenthesis x right parenthesis greater than 0$ or $f to the power of apostrophe left parenthesis x right parenthesis less than 0 comma for all x element of$ domain of f, then y = f(x) is one-one function.</span

Assertion : Let $f colon R minus left curly bracket 1 , 2 comma 3 right curly bracket rightwards arrow R$ be a function defined by f(x) = $fraction numerator 1 over denominator x minus 1 end fraction plus fraction numerator 2 over denominator x minus 2 end fraction plus fraction numerator 3 over denominator x minus 3 end fraction$ . Then f is many-one function.
Reason : If either $f apostrophe left parenthesis x right parenthesis greater than 0$ or $f to the power of apostrophe left parenthesis x right parenthesis less than 0 comma for all x element of$ domain of f, then y = f(x) is one-one function.</span

Assertion : Fundamental period of $c o s invisible function application x plus c o t invisible function application x text is end text 2 pi$ .
Reason : If the period of f(x) is $T subscript 1 end subscript$ and the period of g(x) is $T subscript 2 end subscript$ , then the fundamental period of f(x) + g(x) is the L.C.M. of $T subscript 1 end subscript$ and T

Assertion : Fundamental period of $c o s invisible function application x plus c o t invisible function application x text is end text 2 pi$ .
Reason : If the period of f(x) is $T subscript 1 end subscript$ and the period of g(x) is $T subscript 2 end subscript$ , then the fundamental period of f(x) + g(x) is the L.C.M. of $T subscript 1 end subscript$ and T

Assertion (A) : Graph of $open curly brackets left parenthesis x comma y right parenthesis divided by y equals 2 to the power of negative x end exponent text and end text x comma y element of R close curly brackets$
Reason (R) : In the expression a^m/n, where a, m, n × J⁺, m represents the power to which a is be raised, whereas n determines the root to be taken; these two processes may be administered in either order with the same result.

Assertion (A) : Graph of $open curly brackets left parenthesis x comma y right parenthesis divided by y equals 2 to the power of negative x end exponent text and end text x comma y element of R close curly brackets$
Reason (R) : In the expression a^m/n, where a, m, n × J⁺, m represents the power to which a is be raised, whereas n determines the root to be taken; these two processes may be administered in either order with the same result.

Function $f colon Z rightwards arrow Z comma$ f(x) = 2x + 1 is-

Function $f colon Z rightwards arrow Z comma$ f(x) = 2x + 1 is-

Statement- $1 colon$ If $f left parenthesis x right parenthesis equals vertical line x minus 1 vertical line plus vertical line x minus 2 vertical line plus vertical line x minus 3 vertical line$ Where $2 less than x less than 3$ is an identity function.
Statement- $2 colon f colon A rightwards arrow$ R defined by $f left parenthesis x right parenthesis equals x$ is an identity function.

f left parenthesis x right parenthesis equals vertical line x minus 1 vertical line plus vertical line x minus 2 vertical line plus vertical line x minus 3 vertical line

equals 2 less than x less than 3

equals x

identity function (correct)
(II)

f left parenthesis x right parenthesis equals x

is an identity function (correct)

Statement- $1 colon$ If $f left parenthesis x right parenthesis equals vertical line x minus 1 vertical line plus vertical line x minus 2 vertical line plus vertical line x minus 3 vertical line$ Where $2 less than x less than 3$ is an identity function.
Statement- $2 colon f colon A rightwards arrow$ R defined by $f left parenthesis x right parenthesis equals x$ is an identity function.

f left parenthesis x right parenthesis equals vertical line x minus 1 vertical line plus vertical line x minus 2 vertical line plus vertical line x minus 3 vertical line

equals 2 less than x less than 3

equals x

identity function (correct)
(II)

f left parenthesis x right parenthesis equals x

is an identity function (correct)

Statement I : Graph of y = tan x is symmetrical about origin
Statement II : Graph of $y equals sec squared invisible function application x$ is symmetrical about y-axis

y = tan x is odd function so must be symmetrical about origin &

y equals s e c to the power of 2 end exponent invisible function application x

is decretive of y = tan x so it must be even imply symmetrical about y-axis or vice-versa

Statement I : Graph of y = tan x is symmetrical about origin
Statement II : Graph of $y equals sec squared invisible function application x$ is symmetrical about y-axis

y = tan x is odd function so must be symmetrical about origin &

y equals s e c to the power of 2 end exponent invisible function application x

is decretive of y = tan x so it must be even imply symmetrical about y-axis or vice-versa

Statement 1 : f : R $rightwards arrow$ R and $f left parenthesis x right parenthesis equals e to the power of x end exponent plus e to the power of negative x end exponent$ is bijective.
Statement 2 : $f colon R rightwards arrow R comma space f left parenthesis x right parenthesis equals e to the power of x minus e to the power of negative x end exponent$ is bijective.

Statement 1 : f : R $rightwards arrow$ R and $f left parenthesis x right parenthesis equals e to the power of x end exponent plus e to the power of negative x end exponent$ is bijective.
Statement 2 : $f colon R rightwards arrow R comma space f left parenthesis x right parenthesis equals e to the power of x minus e to the power of negative x end exponent$ is bijective.

If f(x) is an even function and $f to the power of apostrophe left parenthesis x right parenthesis$ Exist for all 'X' then f'(1)+f'(-1) is-

that the range of x – [x] is [0 , 1) then of [x] – x is (–1 , 0]

If f(x) is an even function and $f to the power of apostrophe left parenthesis x right parenthesis$ Exist for all 'X' then f'(1)+f'(-1) is-

that the range of x – [x] is [0 , 1) then of [x] – x is (–1 , 0]

In two separate collisions, the coefficient of restitutions and are in the ratio 3:1.In the first collision the relative velocity of approach is twice the relative velocity of separation ,then the ratio between relative velocity of approach and the relative velocity of separation in the second collision is

In two separate collisions, the coefficient of restitutions and are in the ratio 3:1.In the first collision the relative velocity of approach is twice the relative velocity of separation ,then the ratio between relative velocity of approach and the relative velocity of separation in the second collision is

physics-General

Suppose $f left parenthesis x right parenthesis equals left parenthesis x plus 1 right parenthesis squared$ for $x greater or equal than negative 1$ . If g(x) is the function whose graph is the reflection of the graph of f(x) with respect to the line y = x, then g(x) equals–

Suppose $f left parenthesis x right parenthesis equals left parenthesis x plus 1 right parenthesis squared$ for $x greater or equal than negative 1$ . If g(x) is the function whose graph is the reflection of the graph of f(x) with respect to the line y = x, then g(x) equals–