Question

# For the ellipse 3x^{2} + 4y^{2} – 6x + 8y – 5 = 0

- centre is (2, -1)
- eccentricity is
- foci are (3, 1) and (-1, 1)
- centre is (1, -1), e = .

Hint:

**Standard form of ellipse **

## The correct answer is: centre is (1, -1), e = .

### Given :

Step 1 Convert in standard form

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