Maths-

General

Easy

### Question

#### If f (x) =

- -1
- 1
- 2
- 3

### Hint:

#### The correct answer is: 2

#### Given, f (x) =

To find : f (x) =

By formula :

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### Related Questions to study

Maths-

#### The value of the integral dx is :

#### The value of the integral dx is :

Maths-General

maths-

#### Assertion : Let be a function defined by f(x) = . Then f is many-one function.

Reason : If either or domain of f, then y = f(x) is one-one function.</span

#### Assertion : Let be a function defined by f(x) = . Then f is many-one function.

Reason : If either or domain of f, then y = f(x) is one-one function.</span

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#### Assertion : Fundamental period of .

Reason : If the period of f(x) is and the period of g(x) is , then the fundamental period of f(x) + g(x) is the L.C.M. of and T

#### Assertion : Fundamental period of .

Reason : If the period of f(x) is and the period of g(x) is , then the fundamental period of f(x) + g(x) is the L.C.M. of and T

maths-General

Maths-

#### Function f(x) = 2x + 1 is-

#### Function f(x) = 2x + 1 is-

Maths-General

maths-

#### If f(x) is an even function and Exist for all 'X' then f'(1)+f'(-1) is-

that the range of x – [x] is [0 , 1) then of [x] – x is (–1 , 0]

#### If f(x) is an even function and Exist for all 'X' then f'(1)+f'(-1) is-

maths-General

that the range of x – [x] is [0 , 1) then of [x] – x is (–1 , 0]

physics-

#### In two separate collisions, the coefficient of restitutions and are in the ratio 3:1.In the first collision the relative velocity of approach is twice the relative velocity of separation ,then the ratio between relative velocity of approach and the relative velocity of separation in the second collision is

#### In two separate collisions, the coefficient of restitutions and are in the ratio 3:1.In the first collision the relative velocity of approach is twice the relative velocity of separation ,then the ratio between relative velocity of approach and the relative velocity of separation in the second collision is

physics-General

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#### Suppose for. If g(x) is the function whose graph is the reflection of the graph of f(x) with respect to the line y = x, then g(x) equals–

#### Suppose for. If g(x) is the function whose graph is the reflection of the graph of f(x) with respect to the line y = x, then g(x) equals–

Maths-General

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#### A spotlight installed in the ground shines on a wall. A woman stands between the light and the wall casting a shadow on the wall. How are the rate at which she walks away from the light and rate at which her shadow grows related ?

#### A spotlight installed in the ground shines on a wall. A woman stands between the light and the wall casting a shadow on the wall. How are the rate at which she walks away from the light and rate at which her shadow grows related ?

maths-General

physics-

#### If reaction is R and coefficient of friction is, what is work done against friction in moving a body by distance d?

As shown a block of mass is lying over rough horizontal surface. Let be the coeeficient of kinetic friction between the two surfaces in contact. The force Of friction between the block and horizontal surface is given by

(

To move the block without acceleration, the force (P)required will be just equal to the force of friction , ie ,

If d is the distance moved , then work done is given by

#### If reaction is R and coefficient of friction is, what is work done against friction in moving a body by distance d?

physics-General

As shown a block of mass is lying over rough horizontal surface. Let be the coeeficient of kinetic friction between the two surfaces in contact. The force Of friction between the block and horizontal surface is given by

(

To move the block without acceleration, the force (P)required will be just equal to the force of friction , ie ,

If d is the distance moved , then work done is given by

physics-

#### The force acting on a particle moving in a straight line is shown in figure. What is the work done by the force on the particle in the 1^{st} meter of the trajectory

Work done Area under curve of - graph

= Area of triangle

= Area of triangle

#### The force acting on a particle moving in a straight line is shown in figure. What is the work done by the force on the particle in the 1^{st} meter of the trajectory

physics-General

Work done Area under curve of - graph

= Area of triangle

= Area of triangle

physics-

#### The pointer reading load graph for a spring balance is as given in the figure. The spring constant is

Spring constant Slope of curve

#### The pointer reading load graph for a spring balance is as given in the figure. The spring constant is

physics-General

Spring constant Slope of curve

physics-

#### The force acting on a body moving along -axis varies with the position of the particle as shown in the fig

The body is in stable equilibrium at

When particle moves away from the origin then at position force is zero and at , force is positive (repulsive in nature) so particle moves further and does not return back to original position the equilibrium is not stable Similarly at position force is zero and at , force is negative (attractive in nature) So particle return back to original position the equilibrium is stable

#### The force acting on a body moving along -axis varies with the position of the particle as shown in the fig

The body is in stable equilibrium at

physics-General

When particle moves away from the origin then at position force is zero and at , force is positive (repulsive in nature) so particle moves further and does not return back to original position the equilibrium is not stable Similarly at position force is zero and at , force is negative (attractive in nature) So particle return back to original position the equilibrium is stable

physics-

#### A frictionless track ends in a circular loop of radius . A body slides down the track from point which is it height . Maximum value of for the body to successfully complete the loop is

Condition for vertical looping

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physics-General

Condition for vertical looping

physics-

#### Velocity-time graph of a particle of mass 2 kg moving in a straight line is as shown in figure. Work done by all forces on the particle is

Initial velocity of particle,

Final velocity of the particle,

According to work-energy theorem,

Final velocity of the particle,

According to work-energy theorem,

#### Velocity-time graph of a particle of mass 2 kg moving in a straight line is as shown in figure. Work done by all forces on the particle is

physics-General

Initial velocity of particle,

Final velocity of the particle,

According to work-energy theorem,

Final velocity of the particle,

According to work-energy theorem,

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#### Domain of definition of the function, is

#### Domain of definition of the function, is

Maths-General