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Question

If the lines $text end text fraction numerator x over denominator 1 end fraction equals fraction numerator y over denominator 2 end fraction equals fraction numerator z over denominator 3 end fraction comma fraction numerator x minus 1 over denominator 3 end fraction equals fraction numerator y minus 2 over denominator negative 1 end fraction equals fraction numerator z minus 3 over denominator 4 end fraction text end text$ and $text end text fraction numerator x plus k over denominator 3 end fraction equals fraction numerator y minus 1 over denominator 2 end fraction equals fraction numerator z minus 2 over denominator h end fraction text end text$ are concurrent then

h = – 2, k = – 6
$h = \frac{1}{2}, k = 2$
h=6,k=2h=6,k=2
$h = 2, k = \frac{1}{2}$

The correct answer is: $h equals 2 comma k equals fraction numerator 1 over denominator 2 end fraction$

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