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General

Easy

Question

In an equilateral triangle of side $2 square root of 3$ cms, the circum radius is -

1 cm
$\sqrt{3}$ cm
2 cm
2 $\sqrt{3}$ cm

The correct answer is: 2 cm

Given that there is an equilateral triangle of side $2 square root of 3$ cms, we need to find the circumradius.
Given , Triangle ABC is an equilateral triangle.
So, circumradius = $fraction numerator s i d e space l e n g t h over denominator square root of 3 end fraction g i v e n space s i d e space equals space 2 square root of 3 c m T h e r e f o r e space c i r c u m r a d i u s space equals fraction numerator 2 square root of 3 over denominator square root of 3 end fraction equals space 2 c m$

The circumradius is 2cm.

Related Questions to study

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parallel

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parallel

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parallel

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parallel

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Statement-II : Every differential equation geometrically represents a family of curve having some common property.

Statement-I : Integral curves denoted by the first order linear differential equation $fraction numerator d y over denominator d x end fraction minus fraction numerator 1 over denominator x end fraction y equals negative x blank$ are family of parabolas passing through the origin.
Statement-II : Every differential equation geometrically represents a family of curve having some common property.

parallel

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