General
Easy
Maths-

In the diagram, if triangle A B C and capital delta P Q R are Equilateral then find text C  end text X Y

Maths-General

  1. 10 to the power of 0 end exponent    
  2. 40 to the power of 0 end exponent    
  3. 30 to the power of 0 end exponent    
  4. 20 to the power of 0 end exponent    

    Answer:The correct answer is: 20 to the power of 0 end exponent

    Book A Free Demo

    +91

    Grade*

    Related Questions to study

    General
    maths-

    In given figure stack A B with rightwards arrow on top equals stack A C with bar on top and stack B C with bar on top equals stack C D with bar on top comma if B A C equals 80 to the power of ring operator end exponent blankthen find ∣ C D B

    In given figure stack A B with rightwards arrow on top equals stack A C with bar on top and stack B C with bar on top equals stack C D with bar on top comma if B A C equals 80 to the power of ring operator end exponent blankthen find ∣ C D B

    maths-General
    General
    maths-

    if a to the power of 2 end exponent plus b to the power of 2 end exponent plus c to the power of 2 end exponent equals a b plus b c plus c a then the triangle is

    if a to the power of 2 end exponent plus b to the power of 2 end exponent plus c to the power of 2 end exponent equals a b plus b c plus c a then the triangle is

    maths-General
    General
    maths-

    In triangle A B C if AD is bisector of stack B A C with blank below and DE bisects open floor B D A comma open floor B equals 40 to the power of ring operator end exponent comma open floor C equals 80 to the power of ring operator end exponent close close close find left floor B E D.

    In triangle A B C if AD is bisector of stack B A C with blank below and DE bisects open floor B D A comma open floor B equals 40 to the power of ring operator end exponent comma open floor C equals 80 to the power of ring operator end exponent close close close find left floor B E D.

    maths-General
    General
    maths-

    in triangle A B C text  , end text BC = 13, CA=14, AB=15. If D is a point on stack A C with bar on top such that stack B D with bar on top perpendicular stack A C with bar on top then length of stack B D with bar on top.

    in triangle A B C text  , end text BC = 13, CA=14, AB=15. If D is a point on stack A C with bar on top such that stack B D with bar on top perpendicular stack A C with bar on top then length of stack B D with bar on top.

    maths-General
    General
    maths-

    The three s ides of triangle A B C are extended as shown so that B D equals fraction numerator 1 over denominator 2 end fraction A B comma C E equals fraction numerator 1 over denominator 2 end fraction B C and A F equals fraction numerator 1 over denominator 2 end fraction C A Find the ratio of the area of capital delta D E F to that of triangle A B C.

    The three s ides of triangle A B C are extended as shown so that B D equals fraction numerator 1 over denominator 2 end fraction A B comma C E equals fraction numerator 1 over denominator 2 end fraction B C and A F equals fraction numerator 1 over denominator 2 end fraction C A Find the ratio of the area of capital delta D E F to that of triangle A B C.

    maths-General
    General
    physics-

    A train moves from one station to another 2 hours time. Its speed-time graph during this motion is shown in the figure. The maximum acceleration during the journey is

    Maximum acceleration will be represented by C D part of the graph
    Acceleration equals fraction numerator d v over denominator d t end fraction equals fraction numerator left parenthesis 60 minus 20 right parenthesis over denominator 0.25 end fraction equals 160 blank k m divided by h to the power of 2 end exponent

    A train moves from one station to another 2 hours time. Its speed-time graph during this motion is shown in the figure. The maximum acceleration during the journey is

    physics-General
    Maximum acceleration will be represented by C D part of the graph
    Acceleration equals fraction numerator d v over denominator d t end fraction equals fraction numerator left parenthesis 60 minus 20 right parenthesis over denominator 0.25 end fraction equals 160 blank k m divided by h to the power of 2 end exponent
    General
    physics-

    The position of a particle at any instant t is given by x equals acos omega t. The speed-time graph of the particle is

    therefore blank x equals acos omega t
    therefore v equals fraction numerator d x over denominator d t end fraction equals negative a omega sin invisible function application omega t
    The instantaneous speed is given by modulus of instantaneous velocity.
    therefore blankspeedequals open vertical bar u close vertical bar equals open vertical bar negative a omega sin invisible function application omega t close vertical bar
    Hence, [c] is correct.

    The position of a particle at any instant t is given by x equals acos omega t. The speed-time graph of the particle is

    physics-General
    therefore blank x equals acos omega t
    therefore v equals fraction numerator d x over denominator d t end fraction equals negative a omega sin invisible function application omega t
    The instantaneous speed is given by modulus of instantaneous velocity.
    therefore blankspeedequals open vertical bar u close vertical bar equals open vertical bar negative a omega sin invisible function application omega t close vertical bar
    Hence, [c] is correct.
    General
    physics-

    The velocity-time graph of a body moving in a straight line is shown in the figure. The displacement and distance travelled by the body in 6 blank s e c are respectively

    Displacement = Summation of all the area with sign
    equals open parentheses A subscript 1 end subscript close parentheses plus open parentheses negative A subscript 2 end subscript close parentheses plus open parentheses A subscript 3 end subscript close parentheses equals open parentheses 2 cross times 4 close parentheses plus open parentheses negative 2 cross times 2 close parentheses plus open parentheses 2 cross times 2 close parentheses

    therefore D i s p l a c e m e n t equals 8 blank m
    Distance = Summation of all the areas without sign
    equals open vertical bar A subscript 1 end subscript close vertical bar plus open vertical bar negative A subscript 2 end subscript close vertical bar plus open vertical bar A subscript 3 end subscript close vertical bar equals open vertical bar 8 close vertical bar plus open vertical bar negative 4 close vertical bar plus open vertical bar 4 close vertical bar equals 8 plus 4 plus 4
    therefore D i s t a n c e equals 16 blank m

    The velocity-time graph of a body moving in a straight line is shown in the figure. The displacement and distance travelled by the body in 6 blank s e c are respectively

    physics-General
    Displacement = Summation of all the area with sign
    equals open parentheses A subscript 1 end subscript close parentheses plus open parentheses negative A subscript 2 end subscript close parentheses plus open parentheses A subscript 3 end subscript close parentheses equals open parentheses 2 cross times 4 close parentheses plus open parentheses negative 2 cross times 2 close parentheses plus open parentheses 2 cross times 2 close parentheses

    therefore D i s p l a c e m e n t equals 8 blank m
    Distance = Summation of all the areas without sign
    equals open vertical bar A subscript 1 end subscript close vertical bar plus open vertical bar negative A subscript 2 end subscript close vertical bar plus open vertical bar A subscript 3 end subscript close vertical bar equals open vertical bar 8 close vertical bar plus open vertical bar negative 4 close vertical bar plus open vertical bar 4 close vertical bar equals 8 plus 4 plus 4
    therefore D i s t a n c e equals 16 blank m
    General
    maths-

    In triangle A B C If stack A P with bar on top bisects angle A B comma stack B P with bar on top bisects ÐABC stack A P with bar on top equals square root of 3 comma stack B P with bar on top equals square root of 3 and CP = 3 then find Area of triangle A B C.

    In triangle A B C If stack A P with bar on top bisects angle A B comma stack B P with bar on top bisects ÐABC stack A P with bar on top equals square root of 3 comma stack B P with bar on top equals square root of 3 and CP = 3 then find Area of triangle A B C.

    maths-General
    General
    maths-

    Find the value of ' ' x in the following figure

    Find the value of ' ' x in the following figure

    maths-General
    General
    maths-

    What is the value of 'a '?

    What is the value of 'a '?

    maths-General
    General
    maths-

    ABCD is a square then find ' a ' in the given figure

    ABCD is a square then find ' a ' in the given figure

    maths-General
    General
    maths-

    In an Isosceles Trapezium PQRS, PR = (5 x + 2) and QS = (8x-7 cm - ) then find the length of PR.

    In an Isosceles Trapezium PQRS, PR = (5 x + 2) and QS = (8x-7 cm - ) then find the length of PR.

    maths-General
    General
    maths-

    In a Rhombus PQRS; QRS = xº then P = ?

    In a Rhombus PQRS; QRS = xº then P = ?

    maths-General
    General
    maths-

    In the following diagram, the bisectors of interior angles of the Parallelogram PQRS enclose a Quadrilateral ABCD. Then find angle A.

    In the following diagram, the bisectors of interior angles of the Parallelogram PQRS enclose a Quadrilateral ABCD. Then find angle A.

    maths-General