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A train moves from one station to another 2 hours time. Its speed-time graph during this motion is shown in the figure. The maximum acceleration during the journey is

  1. 140 blank k m blank h to the power of negative 2 end exponent    
  2. 160 blank k m blank h to the power of negative 2 end exponent    
  3. 100 blank k m blank h to the power of negative 2 end exponent    
  4. 120 blank k m blank h to the power of negative 2 end exponent    

The correct answer is: 160 blank k m blank h to the power of negative 2 end exponent


    Maximum acceleration will be represented by C D part of the graph
    Acceleration equals fraction numerator d v over denominator d t end fraction equals fraction numerator left parenthesis 60 minus 20 right parenthesis over denominator 0.25 end fraction equals 160 blank k m divided by h to the power of 2 end exponent

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