Maths-
General
Easy

Question

In the figure, A C parallel to stack B E with bar on top text  and  end text stack B F with bar on top text  bisects  end text angle C B E text If  end text stack F B with bar on top perpendicular stack A B with bar on top text  then  end text angle C B A minus angle C A B equals

  1.    
  2. 10°    
  3. 15°    
  4. 20°    

The correct answer is: 0°


    angle C B F equals angle E B F equals x space left parenthesis B F space i s space a space b i s e c t o r right parenthesis
I n space t r i a n g l e space A B C
angle B C A equals angle C B E space left parenthesis a l t e r n a t e space i n t e r i o r space a n g l e s right parenthesis
angle B C A equals 2 x
angle C B A equals 90 to the power of ring operator minus x
A l s o comma
angle B C A plus angle C A B equals angle C B D thin space left parenthesis e x t e r i o r space a n g l e s space o f space t r i a n g l e space i s space e q u a l space t o space t h e space s u m space o f space b o t h space o p p o s i t e space a n g l e s right parenthesis
2 x plus angle C A B equals angle C B D
2 x plus angle C A B equals 90 to the power of ring operator plus x
angle C A B equals 90 to the power of ring operator plus x minus 2 x
angle C A B equals 90 to the power of ring operator minus x
angle C B A minus angle C A B equals 90 to the power of ring operator minus x minus left parenthesis 90 minus x right parenthesis
space space space space space space space space space space space space space space space space space space space space space equals 0


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