In the given diagram, $fraction numerator A O over denominator O C end fraction equals fraction numerator B O over denominator O D end fraction equals fraction numerator 1 over denominator 2 end fraction text and end text A B equals 5 c m$ Find the value of DC.

ABCD is a quadrilateral. AD and BD are the angle bisectors of angle A and B which meet at ‘O’. If $angle C equals 70 to the power of ring operator end exponent comma angle D equals 50 to the power of ring operator end exponent. text Find end text angle A O B$

So we have given a quadrilateral where we have $A O$ and $B O$ are the angle bisectors of angles $A$ and $B$ which meet at $O$ . The measurements of the angles and side lengths of quadrilaterals are used to categorise them. So the angle AOB is 60 degree.

ABCD is a quadrilateral. AD and BD are the angle bisectors of angle A and B which meet at ‘O’. If $angle C equals 70 to the power of ring operator end exponent comma angle D equals 50 to the power of ring operator end exponent. text Find end text angle A O B$

In the unit Square, find the distance from E to $stack A D with bar on top$ in terms of a and b the length of $stack D F with bar on top text and end text stack A G with bar on top$ , respectively

Therefore the correct option is choice 1

In the unit Square, find the distance from E to $stack A D with bar on top$ in terms of a and b the length of $stack D F with bar on top text and end text stack A G with bar on top$ , respectively

Therefore the correct option is choice 1

ABCD is a Parallelogram, $A E perpendicular D C text and end text C F perpendicular A D$ If DC=16cm, AE = 8 cm and CF = 10 cm, Find AD

Here we used the concept of parallelogram and identified some concepts of corresponding attitudes. A parallelogram is a two-dimensional flat shape with four angles. The internal angles on either side are equal. So the dimension of AD is 12.8 cm.

ABCD is a Parallelogram, $A E perpendicular D C text and end text C F perpendicular A D$ If DC=16cm, AE = 8 cm and CF = 10 cm, Find AD

Two Rectangles ABCD and DBEF are as shown in the figure. The area of Rectangle DBEF is

So here we used the concept of rectangle and triangle, and we understood the relation between them to solve this question. The total of the triangles' individual areas makes up the rectangle's surface area.So the area of rectangle DBEF is 12 cm².

Two Rectangles ABCD and DBEF are as shown in the figure. The area of Rectangle DBEF is

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In the given figure, ABCD is a Cyclic Quadrilateral $stack D E with bar on top perpendicular stack A B with bar on top comma open floor B A O equals 40 to the power of ring operator end exponent comma O A D equals 20 to the power of ring operator end exponent close$ and $angle O C D equals 50 to the power of ring operator end exponent$ then

maths-General

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In the figure below $stack A B with bar on top parallel to stack D C with bar on top comma stack A E with bar on top parallel to stack B C with bar on top text and end text stack A F with bar on top parallel to stack B D with bar on top$ If $open floor D equals x to the power of ring operator end exponent comma open floor C equals y to the power of 0 end exponent close close$ , $E A B equals k to the power of ring operator end exponent$ and $open floor A B P equals p to the power of ring operator end exponent comma close$ then which of the following is correct ?

maths-General

If ABCD is a square, MDC is an Equilateral Triangle. Find the value of x

So here we were given a square PQRS and in that an equilateral triangle STR is present. We used the concept of equilateral triangle to solve the answer. So the angle x is equal to 105 degrees.

If ABCD is a square, MDC is an Equilateral Triangle. Find the value of x

So here we were given a square PQRS and in that an equilateral triangle STR is present. We used the concept of equilateral triangle to solve the answer. So the angle x is equal to 105 degrees.

If PQRS is a Square and STR is an Equilateral Triangle. Find the value of a

So here we were given a square PQRS and in that an equilateral triangle STR is present. We used the concept of equilateral triangle to solve the answer. So the angle a is equal to 75 degrees.

If PQRS is a Square and STR is an Equilateral Triangle. Find the value of a

So here we were given a square PQRS and in that an equilateral triangle STR is present. We used the concept of equilateral triangle to solve the answer. So the angle a is equal to 75 degrees.

In a Trapezium ABCD, as shown, $A B parallel to D C comma A D equals D C equals B C equals 20 c m$ and $angle equals 60 º$ then length of AB is

In the following diagram, the bisectors of interior angles of the Parallelogram PQRS enclose a Quadrilateral ABCD. Then find angle A.

In a Rhombus PQRS; if $angle Q S R equals x to the power of ring operator text then ∠ end text P equals$ ?

In an Isosceles Trapezium PQRS, $P R equals left parenthesis 5 x plus 2 right parenthesis text and end text Q S equals left parenthesis 8 x minus 7 right parenthesis c m$ then find the length of PR.

ABCD is a square then find 'a’ in the given figure

What is the value of 'a’?