In the given figure, ABCD is a Cyclic Quadrilateral $stack D E with bar on top perpendicular stack A B with bar on top comma open floor B A O equals 40 to the power of ring operator end exponent comma O A D equals 20 to the power of ring operator end exponent close$ and $angle O C D equals 50 to the power of ring operator end exponent$ then

If ABCD is a square, MDC is an Equilateral Triangle. Find the value of x

So here we were given a square PQRS and in that an equilateral triangle STR is present. We used the concept of equilateral triangle to solve the answer. So the angle x is equal to 105 degrees.

If ABCD is a square, MDC is an Equilateral Triangle. Find the value of x

So here we were given a square PQRS and in that an equilateral triangle STR is present. We used the concept of equilateral triangle to solve the answer. So the angle x is equal to 105 degrees.

If PQRS is a Square and STR is an Equilateral Triangle. Find the value of a

So here we were given a square PQRS and in that an equilateral triangle STR is present. We used the concept of equilateral triangle to solve the answer. So the angle a is equal to 75 degrees.

If PQRS is a Square and STR is an Equilateral Triangle. Find the value of a

So here we were given a square PQRS and in that an equilateral triangle STR is present. We used the concept of equilateral triangle to solve the answer. So the angle a is equal to 75 degrees.

In a Trapezium ABCD, as shown, $A B parallel to D C comma A D equals D C equals B C equals 20 c m$ and $angle equals 60 º$ then length of AB is

In the following diagram, the bisectors of interior angles of the Parallelogram PQRS enclose a Quadrilateral ABCD. Then find angle A.

In a Rhombus PQRS; if $angle Q S R equals x to the power of ring operator text then ∠ end text P equals$ ?

In an Isosceles Trapezium PQRS, $P R equals left parenthesis 5 x plus 2 right parenthesis text and end text Q S equals left parenthesis 8 x minus 7 right parenthesis c m$ then find the length of PR.

In DABC, if AD is bisector $left floor B A C$ and DE bisects $open floor B D A comma open floor B equals 40 to the power of ring operator end exponent comma ∣ C equals 80 to the power of ring operator end exponent close close$ find $left floor B E D$

Therefore, $angle B E D$ is 85.

In DABC, if AD is bisector $left floor B A C$ and DE bisects $open floor B D A comma open floor B equals 40 to the power of ring operator end exponent comma ∣ C equals 80 to the power of ring operator end exponent close close$ find $left floor B E D$

Therefore, $angle B E D$ is 85.

Find ‘b’ in the given figure

Therefore, the value of b is 125.

Find ‘b’ in the given figure

Therefore, the value of b is 125.

Find x in the given figure

Therefore, the value of x is 65.

Find x in the given figure

Therefore, the value of x is 65.

Find x.

Therefore, the value of X is 70.

Find x.

Therefore, the value of X is 70.

Two circles of the same radii are

So we understood the concept of circles and how they can be equal with the same radii, so Congruent circles are those whose radii are equal.

Two circles of the same radii are