Question

# ABCD is a quadrilateral. AD and BD are the angle bisectors of angle A and B which meet at ‘O’. If

- 40°
- 60°
- 80
- 90°

Hint:

### A closed quadrilateral has four sides, four vertices, and four angles. It is a form of polygon. In order to create it, four non-collinear points are joined. Quadrilaterals always have a total internal angle of 360 degrees. Here we have given ABCD is a quadrilateral. $AO$ and $BO$ are the angle bisectors of angles $A$ and $B$ which meet at $O. We have to find angle AOB.$

## The correct answer is: 60°

### A quadrilateral is a flat shape with four edges and four corners, also known as vertices. The quadrilateral has angles at each of its four vertices, or corners. The angles at the vertices of a quadrilateral ABCD are A, B, C, and D. A quadrilateral has the following sides: AB, BC, CD, and DA.

We have given ABCD is a quadrilateral and $AO$ and $BO$ are the angle bisectors of angles $A$ and $B$ which meet at $O$.

So we have given a quadrilateral where we have $AO$ and $BO$ are the angle bisectors of angles A and B which meet at O. The measurements of the angles and side lengths of quadrilaterals are used to categorise them. So the angle AOB is 60 degree.

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So here we were given a square PQRS and in that an equilateral triangle STR is present. We used the concept of equilateral triangle to solve the answer. So the angle x is equal to 105 degrees.

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So here we were given a square PQRS and in that an equilateral triangle STR is present. We used the concept of equilateral triangle to solve the answer. So the angle x is equal to 105 degrees.

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So here we were given a square PQRS and in that an equilateral triangle STR is present. We used the concept of equilateral triangle to solve the answer. So the angle a is equal to 75 degrees.

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