Maths-
General
Easy
Question
Hint:
The correct answer is:
We should find the value in sinh(ix)
sinhx=(ex−e−x)/2 [identity]
∴sinh(ix)=(eix-e-ix)/2
=2(cosx+isinx)−(cosx−isinx)
sinh(ix)=isinx[eix=cosx+isinx,e−ix=cosx−isinx]
∴sinh(ix)=(eix-e-ix)/2
Hence answer is isinx
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