Question
The angle between the lines
and
is
Hint:
A line has length but no width, making it a one-dimensional figure. A line is made up of a collection of points that can be stretched indefinitely in opposing directions. Two points in a two-dimensional plane determine it. Collinear points are two points that are located on the same line. We have to find the angle between the lines
and
.
The correct answer is: 
The intersection of two perpendicular lines results in the formation of the cartesian plane, a two-dimensional coordinate plane. The X-axis is the horizontal line, and the Y-axis is the vertical line. The Cartesian coordinate point (x, y) indicates that the distance from the origin is x in the horizontal direction and y in the vertical direction.
Now the given lines are:
and
The cartesian form will be:
2x + 5y = 3
2y − 5x = −4
Slopes of these lines are −5/2 and 2/5
Here, we can say that the product of slopes is −1
Hence, these lines are perpendicular so the angles between them is 90 degrees.
2y − 5x = −4
Here, we can say that the product of slopes is −1
Hence, these lines are perpendicular so the angles between them is 90 degrees.
Here we used the concept of cartesian lines and some trigonometric terms to solve. With the help of slope we identified the angle between them. Hence, these lines are perpendicular so the angle between them is 90 degrees.
Related Questions to study
The polar equation of the straight line passing through
and perpendicular to the initial line is
The polar equation of the straight line passing through
and perpendicular to the initial line is
The polar equation of the straight line passing through
and parallel to the initial line is
The polar equation of the straight line passing through
and parallel to the initial line is
The equation of the line passing through pole and
is
The equation of the line passing through pole and
is
The polar equation of
is
Here we used the concept of polar coordinate system and also the trigonometric ratios to find the solution. So the equation is .
The polar equation of
is
Here we used the concept of polar coordinate system and also the trigonometric ratios to find the solution. So the equation is .
The cartesian equation of
is
Here we used the concept of the polar coordinate system and also the trigonometric ratios to find the solution. So the equation is .
The cartesian equation of
is
Here we used the concept of the polar coordinate system and also the trigonometric ratios to find the solution. So the equation is .
Two tuning forks
and
are vibrated together. The number of beats produced are represented by the straight line
in the following graph. After loading
with wax again these are vibrated together and the beats produced are represented by the line
If the frequency of
is
the frequency of
will be

Two tuning forks
and
are vibrated together. The number of beats produced are represented by the straight line
in the following graph. After loading
with wax again these are vibrated together and the beats produced are represented by the line
If the frequency of
is
the frequency of
will be

If a hyperbola passing through the origin has
and
as its asymptotes, then the equation of its tranvsverse and conjugate axes are
Here we used the concept of polar coordinate system and also the trigonometric ratios to find the solution.
If a hyperbola passing through the origin has
and
as its asymptotes, then the equation of its tranvsverse and conjugate axes are
Here we used the concept of polar coordinate system and also the trigonometric ratios to find the solution.