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#### The polar equation of the straight line passing through and perpendicular to the initial line is

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#### Answer:The correct answer is:

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### Related Questions to study

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#### The angle between the lines and is

#### The angle between the lines and is

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#### The polar equation of the straight line passing through and parallel to the initial line is

#### The polar equation of the straight line passing through and parallel to the initial line is

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maths-

#### The equation of the line passing through pole and is

#### The equation of the line passing through pole and is

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maths-

#### The number of points in the Cartesian plane with integral co-ordinates satisfying the inequalities |x| k, |y| k, |x – y| k ; is-

|x| k –k x k ….(1)

& |y| k –k y k ….(2)

& |x – y| k |y – x| k –k y – x k x – k y x + k ….(3)

Number of points having integral coordinates

= (2k + 1)

= (3k

& |y| k –k y k ….(2)

& |x – y| k |y – x| k –k y – x k x – k y x + k ….(3)

Number of points having integral coordinates

= (2k + 1)

^{2}– 2= (3k

^{2}+ 3k + 1).#### The number of points in the Cartesian plane with integral co-ordinates satisfying the inequalities |x| k, |y| k, |x – y| k ; is-

maths-General

|x| k –k x k ….(1)

& |y| k –k y k ….(2)

& |x – y| k |y – x| k –k y – x k x – k y x + k ….(3)

Number of points having integral coordinates

= (2k + 1)

= (3k

& |y| k –k y k ….(2)

& |x – y| k |y – x| k –k y – x k x – k y x + k ….(3)

Number of points having integral coordinates

= (2k + 1)

^{2}– 2= (3k

^{2}+ 3k + 1).maths-

#### The polar equation of is

#### The polar equation of is

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maths-

#### The cartesian equation of is

#### The cartesian equation of is

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maths-

#### A is a set containing n elements. A subset P_{1} is chosen, and A is reconstructed by replacing the elements of P_{1}. The same process is repeated for subsets P_{1}, P_{2}, … , P_{m}, with m > 1. The Number of ways of choosing P_{1}, P_{2}, …, P_{m} so that P_{1} P_{2} … P_{m}= A is -

Let A = {a

For each a

Also there is exactly one choice, viz., a

Therefore, a

P

_{1}, a_{2},…..a_{n}}.For each a

_{i}(1 i n), either a_{i}P_{j}or a_{i}P_{j}(1 j m) . Thus, there are 2^{m}choices in which a_{i}(1 j n) may belong to the P_{j}s.Also there is exactly one choice, viz., a

_{i}P_{j}for j = 1, 2, …, m, for which a_{i}P_{1}P_{2}... P_{m}.Therefore, a

_{i}P_{1}P_{2}…. P_{m}in (2^{m}– 1) ways . Since there are n elements in the set A, the number of ways of constructing subsetsP

_{1}, P_{2}, ….. , P_{m}is (2^{m}– 1)^{n}#### A is a set containing n elements. A subset P_{1} is chosen, and A is reconstructed by replacing the elements of P_{1}. The same process is repeated for subsets P_{1}, P_{2}, … , P_{m}, with m > 1. The Number of ways of choosing P_{1}, P_{2}, …, P_{m} so that P_{1} P_{2} … P_{m}= A is -

maths-General

Let A = {a

For each a

Also there is exactly one choice, viz., a

Therefore, a

P

_{1}, a_{2},…..a_{n}}.For each a

_{i}(1 i n), either a_{i}P_{j}or a_{i}P_{j}(1 j m) . Thus, there are 2^{m}choices in which a_{i}(1 j n) may belong to the P_{j}s.Also there is exactly one choice, viz., a

_{i}P_{j}for j = 1, 2, …, m, for which a_{i}P_{1}P_{2}... P_{m}.Therefore, a

_{i}P_{1}P_{2}…. P_{m}in (2^{m}– 1) ways . Since there are n elements in the set A, the number of ways of constructing subsetsP

_{1}, P_{2}, ….. , P_{m}is (2^{m}– 1)^{n}physics-

#### Two tuning forks and are vibrated together. The number of beats produced are represented by the straight line in the following graph. After loading with wax again these are vibrated together and the beats produced are represented by the line If the frequency of is the frequency of will be

or

On waxing the number of beats decreases hence

On waxing the number of beats decreases hence

#### Two tuning forks and are vibrated together. The number of beats produced are represented by the straight line in the following graph. After loading with wax again these are vibrated together and the beats produced are represented by the line If the frequency of is the frequency of will be

physics-General

or

On waxing the number of beats decreases hence

On waxing the number of beats decreases hence

maths-

#### If a hyperbola passing through the origin has and as its asymptotes, then the equation of its tranvsverse and conjugate axes are

#### If a hyperbola passing through the origin has and as its asymptotes, then the equation of its tranvsverse and conjugate axes are

maths-General

physics-

#### Which of the following curves represents correctly the oscillation given by

Given equation

At

This is case with curve marked

At

This is case with curve marked

#### Which of the following curves represents correctly the oscillation given by

physics-General

Given equation

At

This is case with curve marked

At

This is case with curve marked

maths-

#### In a triangle ABC, if a : b : c = 7 : 8 : 9, then cos A : cos B equals to

#### In a triangle ABC, if a : b : c = 7 : 8 : 9, then cos A : cos B equals to

maths-General

physics-

#### A small source of sound moves on a circle as shown in the figure and an observer is standing on Let and be the frequencies heard when the source is at and respectively. Then

At point source is moving away from observer so apparent frequency (actual frequency) At point source is coming towards observer so apparent frequency and point source is moving perpendicular to observer so

Hence

Hence

#### A small source of sound moves on a circle as shown in the figure and an observer is standing on Let and be the frequencies heard when the source is at and respectively. Then

physics-General

At point source is moving away from observer so apparent frequency (actual frequency) At point source is coming towards observer so apparent frequency and point source is moving perpendicular to observer so

Hence

Hence

maths-

#### (Area of GPL) to (Area of ALD) is equal to

#### (Area of GPL) to (Area of ALD) is equal to

maths-General

maths-

#### The polar equation of the circle with pole as centre and radius 3 is

#### The polar equation of the circle with pole as centre and radius 3 is

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maths-

#### The equation of the circle passing through pole and centre at (4,0) is

#### The equation of the circle passing through pole and centre at (4,0) is

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