The number of different seven digit numbers that can be written-Turito

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Using conservation of linear momentum, we
have

Or
Using conservation of energy, we have

Where compression in the spring

Or

physics-General

Using conservation of linear momentum, we
have

Or
Using conservation of energy, we have

Where compression in the spring

Or

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The number of different seven digit numbers that can be written using only the three digits 1, 2 and 3 with the condition that the digit 2 occurs twice in each number is-

7P2 . 25 7C2 . 25 7C2 . 52 None of these

Answer:The correct answer is: 7C2 . 25

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If then assending order of A,B,C

If then assending order of A,B,C

A block C of mass is moving with velocity and collides elastically with block of mass and connected to another block of mass through spring constant .What is if is compression of spring when velocity of is same ?

A block C of mass is moving with velocity and collides elastically with block of mass and connected to another block of mass through spring constant .What is if is compression of spring when velocity of is same ?

The centre and radius of the circle are respectively

The centre and radius of the circle are respectively

The centre of the circle is

The centre of the circle is

The equation of the circle with centre at , which passes through the point is

The equation of the circle with centre at , which passes through the point is

The foot of the perpendicular from on the line is

The foot of the perpendicular from on the line is

The foot of the perpendicular from the pole on the line is

The foot of the perpendicular from the pole on the line is

The equation of the line parallel to and passing through is

The equation of the line parallel to and passing through is

The line passing through the points , (3,0) is

The line passing through the points , (3,0) is

Statement-I : If then A=Statement-II : If then Which of the above statements is true

Statement-I : If then A=Statement-II : If then Which of the above statements is true

If b > a , then the equation, (x - a) (x - b) - 1 = 0, has:

If b > a , then the equation, (x - a) (x - b) - 1 = 0, has:

If be that roots where , such that and then the number of integral solutions of λ is

If be that roots where , such that and then the number of integral solutions of λ is

If α,β then the equation with roots will be

If α,β then the equation with roots will be

If have a common factor then 'a' is equal to

If have a common factor then 'a' is equal to

The number of proper divisors of 2p. 6q. 15r is-

The number of proper divisors of 2p. 6q. 15r is-

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⁷P₂ . 2⁵
⁷C₂ . 2⁵
⁷C₂ . 5²
None of these

Answer:The correct answer is: ⁷C₂ . 2⁵

The centre and radius of the circle $r equals c o s space theta minus s i n space theta$ are respectively

The centre and radius of the circle $r equals c o s space theta minus s i n space theta$ are respectively

The centre of the circle $r squared minus 2 r left parenthesis 3 c o s space theta plus 4 s i n space theta right parenthesis minus 24$ is

The centre of the circle $r squared minus 2 r left parenthesis 3 c o s space theta plus 4 s i n space theta right parenthesis minus 24$ is

The equation of the circle with centre at $open parentheses 1 comma 0 to the power of 0 end exponent close parentheses$ , which passes through the point $open parentheses 0 comma fraction numerator pi over denominator 2 end fraction close parentheses$ is

The equation of the circle with centre at $open parentheses 1 comma 0 to the power of 0 end exponent close parentheses$ , which passes through the point $open parentheses 0 comma fraction numerator pi over denominator 2 end fraction close parentheses$ is

The foot of the perpendicular from $left parenthesis negative 1 comma pi divided by 6 right parenthesis$ on the line $r left parenthesis 3 s i n space theta plus square root of 3 c o s space theta right parenthesis equals 3$ is

The foot of the perpendicular from $left parenthesis negative 1 comma pi divided by 6 right parenthesis$ on the line $r left parenthesis 3 s i n space theta plus square root of 3 c o s space theta right parenthesis equals 3$ is

The foot of the perpendicular from the pole on the line $r left parenthesis c o s space theta plus square root of 3 s i n space theta right parenthesis equals 2$ is

The foot of the perpendicular from the pole on the line $r left parenthesis c o s space theta plus square root of 3 s i n space theta right parenthesis equals 2$ is

The equation of the line parallel to $r left square bracket 3 C o s space theta plus 2 S i n space theta right square bracket equals 5$ and passing through $open parentheses 2 comma fraction numerator pi over denominator 2 end fraction close parentheses$ is

The equation of the line parallel to $r left square bracket 3 C o s space theta plus 2 S i n space theta right square bracket equals 5$ and passing through $open parentheses 2 comma fraction numerator pi over denominator 2 end fraction close parentheses$ is

The line passing through the points $open parentheses 2 comma fraction numerator pi over denominator 2 end fraction close parentheses$ , (3,0) is

The line passing through the points $open parentheses 2 comma fraction numerator pi over denominator 2 end fraction close parentheses$ , (3,0) is

If $alpha comma beta$ be that roots $4 x squared minus 16 x plus lambda equals 0$ where $lambda element of R$ , such that $1 less than alpha less than 2$ and $2 less than beta less than 3$ then the number of integral solutions of λ is

If $alpha comma beta$ be that roots $4 x squared minus 16 x plus lambda equals 0$ where $lambda element of R$ , such that $1 less than alpha less than 2$ and $2 less than beta less than 3$ then the number of integral solutions of λ is

If α,β then the equation $x squared minus 3 x plus 1 equals 0$ with roots $fraction numerator 1 over denominator alpha minus 2 end fraction comma fraction numerator 1 over denominator beta minus 2 end fraction$ will be

If α,β then the equation $x squared minus 3 x plus 1 equals 0$ with roots $fraction numerator 1 over denominator alpha minus 2 end fraction comma fraction numerator 1 over denominator beta minus 2 end fraction$ will be

If $x squared minus 11 x plus a text and end text x squared minus 14 x plus 2 a$ have a common factor then 'a' is equal to

If $x squared minus 11 x plus a text and end text x squared minus 14 x plus 2 a$ have a common factor then 'a' is equal to

The number of proper divisors of 2p. 6q. 15^r is-

The number of proper divisors of 2p. 6q. 15^r is-