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A 20mu F capacitor is connected to 45 V battery through a circuit whose resistance is 2000capital omega. What is the final charge on the capacitor?

  1. 9 cross times 10 to the power of negative 4 end exponent C    
  2. 9.154 cross times 10 to the power of negative 4 end exponent C    
  3. 9.8 cross times 10 to the power of negative 4 end exponent C    
  4. None of these    

The correct answer is: 9 cross times 10 to the power of negative 4 end exponent C


    We know that in steady state the capacitor behaves like as an open circuit i e, capacitor will not pass the current.

    So, the potential difference across the capacitor = 45 V
    Hence , the final charge on the capacitor is
    q equals C V
    Here , C equals 20 mu F comma blank V equals 45 blank V
    therefore blank q equals 20 cross times 10 to the power of negative 6 end exponent cross times 45
    orblank q equals 900 cross times 10 to the power of negative 6 end exponent
    orblank q equals 9 cross times 10 to the power of negative 4 end exponent C

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