Physics-

#### Average torque on a projectile of mass , initial speed and angles of projection , between initial and final position and as shown in figure about the point of projection is

Physics-General

#### Answer:The correct answer is: Time of flight.

Horizontal range,

Change in angular momentum,

about point of projection

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### Related Questions to study

physics-

#### A small body of mass slides down from the top of a hemisphere of radius . The surface of block and hemisphere are frictionless. The height at which the body lose contact with the surface of the sphere is

#### A small body of mass slides down from the top of a hemisphere of radius . The surface of block and hemisphere are frictionless. The height at which the body lose contact with the surface of the sphere is

physics-General

physics-

#### Three balls are dropped from the top of a building with equal speed at different angles. When the balls strike ground their velocities are and respectively, then

All the balls are projected from the same height, therefore their velocities will be equal.

#### Three balls are dropped from the top of a building with equal speed at different angles. When the balls strike ground their velocities are and respectively, then

physics-General

All the balls are projected from the same height, therefore their velocities will be equal.

maths-

#### The equation of the plane containing the line where al + bm + cn is equal to

Since these two lines are intersecting so shortest distance between the lines will be 0.

Hence (c) is the correct answer.

Hence (c) is the correct answer.

#### The equation of the plane containing the line where al + bm + cn is equal to

maths-General

Since these two lines are intersecting so shortest distance between the lines will be 0.

Hence (c) is the correct answer.

Hence (c) is the correct answer.

physics-

#### A string of length is fixed at one end and the string makes rev/s around the vertical axis through, the fixed and as shown in the figure, then tension in the string is

(i)

(ii)

(ii)

#### A string of length is fixed at one end and the string makes rev/s around the vertical axis through, the fixed and as shown in the figure, then tension in the string is

physics-General

(i)

(ii)

(ii)

physics-

#### A point *P* moves in counter-clockwise direction on a circular path as shown in the figure. The movement of *P* is such that it sweeps out length where is in metre and *t *is in second. The radius of the path is 20 m. The acceleration of *P* when *t* =2s is nearly

#### A point *P* moves in counter-clockwise direction on a circular path as shown in the figure. The movement of *P* is such that it sweeps out length where is in metre and *t *is in second. The radius of the path is 20 m. The acceleration of *P* when *t* =2s is nearly

physics-General

physics-

#### A thin prism with angle and made from glass of refractive index 1.54 is combined with another thin prism of refractive index 1.72 to produce dispersion without deviation. The angle of prism will be

Þ A'

#### A thin prism with angle and made from glass of refractive index 1.54 is combined with another thin prism of refractive index 1.72 to produce dispersion without deviation. The angle of prism will be

physics-General

Þ A'

physics-

#### A triangular prism of glass is shown in the figure. A ray incident normally to one face is totally reflected, if . The index of refraction of glass is

For total internal reflection

or

or

#### A triangular prism of glass is shown in the figure. A ray incident normally to one face is totally reflected, if . The index of refraction of glass is

physics-General

For total internal reflection

or

or

physics-

#### Which of the following diagrams, shows correctly the dispersion of white light by a prism

Because in dispersion of white light, the rays of different colours are not parallel to each other. Also deviation takes place in same direction.

#### Which of the following diagrams, shows correctly the dispersion of white light by a prism

physics-General

Because in dispersion of white light, the rays of different colours are not parallel to each other. Also deviation takes place in same direction.

physics-

#### A piece of wire is bent in the shape of a parabola $y=k{x}^{2}(y$-axis vertical) with a bead of mass $m$ on it. The bead can side on the wire without friction. It stays at the lowest point of the parabola when the wire is at rest. The wire is now accelerated parallel to the $x$-axis with a constant acceleration $a$. The distance of the new equilibrium position of the bead, where the bead can stay at rest with respect to the wire, from the $y$-axis is

$ma\mathrm{cos}\theta =mg\mathrm{cos}(90-\theta )$
$\Rightarrow \frac{a}{g}=\mathrm{tan}\theta \Rightarrow \frac{a}{g}=\frac{dy}{dx}$
$\Rightarrow \frac{d}{dx}{\left(kx\right)}^{2}=\frac{a}{g}\Rightarrow x=\frac{a}{2gk}$

#### A piece of wire is bent in the shape of a parabola $y=k{x}^{2}(y$-axis vertical) with a bead of mass $m$ on it. The bead can side on the wire without friction. It stays at the lowest point of the parabola when the wire is at rest. The wire is now accelerated parallel to the $x$-axis with a constant acceleration $a$. The distance of the new equilibrium position of the bead, where the bead can stay at rest with respect to the wire, from the $y$-axis is

physics-General

$ma\mathrm{cos}\theta =mg\mathrm{cos}(90-\theta )$
$\Rightarrow \frac{a}{g}=\mathrm{tan}\theta \Rightarrow \frac{a}{g}=\frac{dy}{dx}$
$\Rightarrow \frac{d}{dx}{\left(kx\right)}^{2}=\frac{a}{g}\Rightarrow x=\frac{a}{2gk}$

physics-

#### A bob of mass *M* is suspended by a massless string of length *L*. The horizontal velocity $v$ at position *A* is just sufficient to make it reach the point *B*. The angle $\theta $ at which the speed of the bob is half of that at *A*, satisfies

Velocity of the bob at the point

*A*$v=\sqrt{5gL}$(i) ${\left(\frac{v}{2}\right)}^{2}={v}^{2}-2gh\left(ii\right)$ $h=L(1-\mathrm{cos}\theta )(iii)$ $SolvingEqs.\left(i\right),\left(ii\right)and\left(iii\right),weget$ $\mathrm{cos}\theta =-\frac{7}{8}$ $or\theta ={cos}^{-1}\left(-\frac{7}{8}\right)=151\xb0$#### A bob of mass *M* is suspended by a massless string of length *L*. The horizontal velocity $v$ at position *A* is just sufficient to make it reach the point *B*. The angle $\theta $ at which the speed of the bob is half of that at *A*, satisfies

physics-General

Velocity of the bob at the point

*A*$v=\sqrt{5gL}$(i) ${\left(\frac{v}{2}\right)}^{2}={v}^{2}-2gh\left(ii\right)$ $h=L(1-\mathrm{cos}\theta )(iii)$ $SolvingEqs.\left(i\right),\left(ii\right)and\left(iii\right),weget$ $\mathrm{cos}\theta =-\frac{7}{8}$ $or\theta ={cos}^{-1}\left(-\frac{7}{8}\right)=151\xb0$physics-

#### A ray of light incident normally on an isosceles right angled prism travels as shown in the figure. The least value of the refractive index of the prism must be

#### A ray of light incident normally on an isosceles right angled prism travels as shown in the figure. The least value of the refractive index of the prism must be

physics-General

maths-

#### The shortest distance between the two straight line$\frac{x-4/3}{2}=\frac{y+6/5}{3}=\frac{z-3/2}{4}$ and $\frac{5y+6}{8}=\frac{2z-3}{9}=\frac{3x-4}{5}$ is

#### The shortest distance between the two straight line$\frac{x-4/3}{2}=\frac{y+6/5}{3}=\frac{z-3/2}{4}$ and $\frac{5y+6}{8}=\frac{2z-3}{9}=\frac{3x-4}{5}$ is

maths-General

maths-

#### The value of ${\int}_{0}^{100}\u200a\left\{\sqrt{x}\right\}dx$ (where {x} is the fractional part of x) is

#### The value of ${\int}_{0}^{100}\u200a\left\{\sqrt{x}\right\}dx$ (where {x} is the fractional part of x) is

maths-General

maths-

#### The value of ${\int}_{0}^{1}\u200a|\mathrm{sin}2\pi x|\mid dx$ is equal to

Given plane y + z + 1 = 0 is parallel to x-axis as 0.1 + 1.0 + 1.0 = 0
but normal to the plane will be perpendicular to x-axis.
Hence (c) is the correct answer.

#### The value of ${\int}_{0}^{1}\u200a|\mathrm{sin}2\pi x|\mid dx$ is equal to

maths-General

Given plane y + z + 1 = 0 is parallel to x-axis as 0.1 + 1.0 + 1.0 = 0
but normal to the plane will be perpendicular to x-axis.
Hence (c) is the correct answer.

maths-

#### Let $f:R\to R,f\left(x\right)=\left\{\begin{array}{c}|x-[x\left]\right|,\left[x\right]\\ |x-[x+1\left]\right|,\left[x\right]\end{array}\right.$$\begin{array}{r}\text{is odd}\\ 1\text{is even where [.]}\end{array}$ denotes greatest integer function, then ${\int}_{-2}^{4}\u200af\left(x\right)dx$ is equal to

Since these two lines are intersecting so shortest distance between the lines will be 0.
Hence (c) is the correct answer.

#### Let $f:R\to R,f\left(x\right)=\left\{\begin{array}{c}|x-[x\left]\right|,\left[x\right]\\ |x-[x+1\left]\right|,\left[x\right]\end{array}\right.$$\begin{array}{r}\text{is odd}\\ 1\text{is even where [.]}\end{array}$ denotes greatest integer function, then ${\int}_{-2}^{4}\u200af\left(x\right)dx$ is equal to

maths-General