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Physics-

General

Easy

Question

Figure shows the graphical variation of displacement with time for the case of a particle moving along a straight line. The accelerations of the particle during the intervals $O A comma A B comma B C$ and $C D$ are respectively

$O A A B B C C D$
$-$ 0 + 0
+ 0 + +
$-$ 0 $-$ 0

The correct answer is: $O A A B B C C D$

The portion $O A$ of the graphs is convex upward. It represents negative acceleration. The portion $A B$ represents negative acceleration. The portion $A B$ represents that $x$ is not changing with time. Clearly, it is a case of zero acceleration. The portion $B C$ of the graph is concave upward. It represents positive acceleration. The portion $C D$ is a straight line sloping upward to the right. It represents uniform velocity and hence acceleration is zero

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