Physics-
If the shear modulus of a wire material is 5.9
then the potential energy of a wire of
in diameter and 5 cm long twisted through an angle of 10’ , is
Physics-General
Answer:The correct answer is:
To twist the wire through the angle
it is necessary to do the work

And 



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physics-
The graph shows the behaviour of a length of wire in the region for which the substance obeys Hooke’s law.
and
represent

Graph between applied force and extension will be straight line because in elastic range
Applied force
extension
But the graph between extension and stored elastic energy will be parabolic in nature
As
or 
Applied force
But the graph between extension and stored elastic energy will be parabolic in nature
As
The graph shows the behaviour of a length of wire in the region for which the substance obeys Hooke’s law.
and
represent

physics-General
Graph between applied force and extension will be straight line because in elastic range
Applied force
extension
But the graph between extension and stored elastic energy will be parabolic in nature
As
or 
Applied force
But the graph between extension and stored elastic energy will be parabolic in nature
As
physics-
A uniform slender rod of length L, cross-sectional area A and Young’s modulus Y is acted upon by the forces shown in the figure. The elongation of the rod is

Net elongation of the rod is




A uniform slender rod of length L, cross-sectional area A and Young’s modulus Y is acted upon by the forces shown in the figure. The elongation of the rod is

physics-General
Net elongation of the rod is




physics-
A cube of aluminium of sides 0.1 m is subjected to a sharing force of 100 N. The top face of the cube is displaced through 0.02 cm with respect to the bottom face. The shearing strain would be
Shearing strain = 
A cube of aluminium of sides 0.1 m is subjected to a sharing force of 100 N. The top face of the cube is displaced through 0.02 cm with respect to the bottom face. The shearing strain would be
physics-General
Shearing strain = 
physics-
The Young’s modulus of the material of a wire is equal to the
Young’s modulus of material 
If longitudinal strain is equal unity, then
Linear stress produced
If longitudinal strain is equal unity, then
The Young’s modulus of the material of a wire is equal to the
physics-General
Young’s modulus of material 
If longitudinal strain is equal unity, then
Linear stress produced
If longitudinal strain is equal unity, then
physics-
A wire of length
and radius
is stretched between
and
without the application of any tension. If
is the Young’s modulus of the wire and it is stretched like
, then the tension in the wire will be

Increase in length of one segment of wire
So,
A wire of length
and radius
is stretched between
and
without the application of any tension. If
is the Young’s modulus of the wire and it is stretched like
, then the tension in the wire will be

physics-General
Increase in length of one segment of wire
So,
physics-
The work done in deforming body is given by
Let L be length of body, A the area of cross-section and
the increase in length.

Force necessary to deform the body is

If body is deformed by a distance, then




Hence, work done for unit volume is

Force necessary to deform the body is
If body is deformed by a distance, then
Hence, work done for unit volume is
The work done in deforming body is given by
physics-General
Let L be length of body, A the area of cross-section and
the increase in length.

Force necessary to deform the body is

If body is deformed by a distance, then




Hence, work done for unit volume is

Force necessary to deform the body is
If body is deformed by a distance, then
Hence, work done for unit volume is
maths-
maths-General
physics
A particle is thrown in upward direction with initial velocity of 60 m/s. Find average speed and average velocity after 10 seconds. [g =10 MS2]
A particle is thrown in upward direction with initial velocity of 60 m/s. Find average speed and average velocity after 10 seconds. [g =10 MS2]
physicsGeneral
physics
The ratio of pathlength and the respective time interval is
The ratio of pathlength and the respective time interval is
physicsGeneral
physics-
Current through ABC and A’ B’ C’ is I. What is the magnetic field at P?
(Here C’ B’ PBC are collinear)

Magnetic field 


Current through ABC and A’ B’ C’ is I. What is the magnetic field at P?
(Here C’ B’ PBC are collinear)

physics-General
Magnetic field 


physics-
PQ and RS are long parallel conductors separated by certain distance. M is the mid-point between them (see the figure). The net magnetic field at M is B. Now, the current 2A is switched off. The field at M now becomes

Magnetic field at mid-point
in first case is 


When the current 2 A is switched off, the net magnetic field at
is due to current 1 A

When the current 2 A is switched off, the net magnetic field at
PQ and RS are long parallel conductors separated by certain distance. M is the mid-point between them (see the figure). The net magnetic field at M is B. Now, the current 2A is switched off. The field at M now becomes

physics-General
Magnetic field at mid-point
in first case is 


When the current 2 A is switched off, the net magnetic field at
is due to current 1 A

When the current 2 A is switched off, the net magnetic field at
physics-
In the figure shown, the magnetic field induction at the point
will be

Field due to a straight wire of infinite length is
if the point is on a line perpendicular to its length while at the centre of a semicircular coil is
.



out of the page

In the figure shown, the magnetic field induction at the point
will be

physics-General
Field due to a straight wire of infinite length is
if the point is on a line perpendicular to its length while at the centre of a semicircular coil is
.



out of the page

physics-
A current of 10 A is passing through a long wire which has semicircular loop of the radius 20 cm as shown in the figure. Magnetic field produced at the centre of the loop is

A current of 10 A is passing through a long wire which has semicircular loop of the radius 20 cm as shown in the figure. Magnetic field produced at the centre of the loop is

physics-General
physics-
Two short bar magnets of equal dipole moment M are fastened perpendicularly at their centers, figure. The magnitude of resultant of two magnetic field at a distance
from the center on the bisector of the right angle is

Resolving the magnetic moments along
and perpendicular to
figure we find that component
perpendicular
cancel out. Resultant magnetic moment along 


The point
lies on axial line of magnet of moment



The point
Two short bar magnets of equal dipole moment M are fastened perpendicularly at their centers, figure. The magnitude of resultant of two magnetic field at a distance
from the center on the bisector of the right angle is

physics-General
Resolving the magnetic moments along
and perpendicular to
figure we find that component
perpendicular
cancel out. Resultant magnetic moment along 


The point
lies on axial line of magnet of moment



The point
physics-
Two magnets of equal mass are joined at 90
each other as shown in figure. Magnet
has a magnetic moment
times that of
. The arrangement is pivoted so that it is free to rotate in horizontal plane. When in equilibrium, what angle should
make with magnetic meridian?

In equilibrium, the resultant magnetic moment will be along magnetic meridian. Let
make
with resultant

Two magnets of equal mass are joined at 90
each other as shown in figure. Magnet
has a magnetic moment
times that of
. The arrangement is pivoted so that it is free to rotate in horizontal plane. When in equilibrium, what angle should
make with magnetic meridian?

physics-General
In equilibrium, the resultant magnetic moment will be along magnetic meridian. Let
make
with resultant
