Physics-
If the shear modulus of a wire material is 5.9
then the potential energy of a wire of 
in diameter and 5 cm long twisted through an angle of 10’ , is
Physics-General
Answer:The correct answer is: To twist the wire through the angle 
it is necessary to do the work
And 
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physics-
The graph shows the behaviour of a length of wire in the region for which the substance obeys Hooke’s law. 
and 
represent
Graph between applied force and extension will be straight line because in elastic range
Applied force
extension
But the graph between extension and stored elastic energy will be parabolic in nature
As
or 
Applied force
extensionBut the graph between extension and stored elastic energy will be parabolic in nature
As
or The graph shows the behaviour of a length of wire in the region for which the substance obeys Hooke’s law. and represent
physics-General
Graph between applied force and extension will be straight line because in elastic range
Applied force extension
But the graph between extension and stored elastic energy will be parabolic in nature
As or
Applied force
extensionBut the graph between extension and stored elastic energy will be parabolic in nature
As
or physics-
A uniform slender rod of length L, cross-sectional area A and Young’s modulus Y is acted upon by the forces shown in the figure. The elongation of the rod is
Net elongation of the rod is
A uniform slender rod of length L, cross-sectional area A and Young’s modulus Y is acted upon by the forces shown in the figure. The elongation of the rod is
physics-General
Net elongation of the rod is
physics-
A cube of aluminium of sides 0.1 m is subjected to a sharing force of 100 N. The top face of the cube is displaced through 0.02 cm with respect to the bottom face. The shearing strain would be
Shearing strain = 
A cube of aluminium of sides 0.1 m is subjected to a sharing force of 100 N. The top face of the cube is displaced through 0.02 cm with respect to the bottom face. The shearing strain would be
physics-General
Shearing strain =
physics-
The Young’s modulus of the material of a wire is equal to the
Young’s modulus of material 
If longitudinal strain is equal unity, then
Linear stress produced
If longitudinal strain is equal unity, then
Linear stress producedThe Young’s modulus of the material of a wire is equal to the
physics-General
Young’s modulus of material
If longitudinal strain is equal unity, then
Linear stress produced
If longitudinal strain is equal unity, then
Linear stress producedphysics-
A wire of length 
and radius 
is stretched between 
and 
without the application of any tension. If 
is the Young’s modulus of the wire and it is stretched like 
, then the tension in the wire will be
Increase in length of one segment of wire
So,
A wire of length and radius is stretched between and without the application of any tension. If is the Young’s modulus of the wire and it is stretched like , then the tension in the wire will be
physics-General
Increase in length of one segment of wire
So,
physics-
The work done in deforming body is given by
Let L be length of body, A the area of cross-section and 
the increase in length.
Force necessary to deform the body is
If body is deformed by a distance, then
Hence, work done for unit volume is
the increase in length.Force necessary to deform the body is
If body is deformed by a distance, then
Hence, work done for unit volume is
The work done in deforming body is given by
physics-General
Let L be length of body, A the area of cross-section and the increase in length.
Force necessary to deform the body is
If body is deformed by a distance, then
Hence, work done for unit volume is
the increase in length.Force necessary to deform the body is
If body is deformed by a distance, then
Hence, work done for unit volume is
maths-
maths-General
physics
A particle is thrown in upward direction with initial velocity of 60 m/s. Find average speed and average velocity after 10 seconds. [g =10 MS2]
A particle is thrown in upward direction with initial velocity of 60 m/s. Find average speed and average velocity after 10 seconds. [g =10 MS2]
physicsGeneral
physics
The ratio of pathlength and the respective time interval is
The ratio of pathlength and the respective time interval is
physicsGeneral
physics-
Current through ABC and A’ B’ C’ is I. What is the magnetic field at P? 
(Here C’ B’ PBC are collinear)
Magnetic field 
Current through ABC and A’ B’ C’ is I. What is the magnetic field at P? (Here C’ B’ PBC are collinear)
physics-General
Magnetic field
physics-
PQ and RS are long parallel conductors separated by certain distance. M is the mid-point between them (see the figure). The net magnetic field at M is B. Now, the current 2A is switched off. The field at M now becomes
Magnetic field at mid-point 
in first case is 
When the current 2 A is switched off, the net magnetic field at is due to current 1 A
in first case is When the current 2 A is switched off, the net magnetic field at
is due to current 1 APQ and RS are long parallel conductors separated by certain distance. M is the mid-point between them (see the figure). The net magnetic field at M is B. Now, the current 2A is switched off. The field at M now becomes
physics-General
Magnetic field at mid-point in first case is
When the current 2 A is switched off, the net magnetic field at is due to current 1 A
in first case is When the current 2 A is switched off, the net magnetic field at
is due to current 1 Aphysics-
In the figure shown, the magnetic field induction at the point 
will be
Field due to a straight wire of infinite length is 
if the point is on a line perpendicular to its length while at the centre of a semicircular coil is 
.
out of the page
if the point is on a line perpendicular to its length while at the centre of a semicircular coil is . out of the pageIn the figure shown, the magnetic field induction at the point will be
physics-General
Field due to a straight wire of infinite length is if the point is on a line perpendicular to its length while at the centre of a semicircular coil is .
out of the page
if the point is on a line perpendicular to its length while at the centre of a semicircular coil is . out of the pagephysics-
A current of 10 A is passing through a long wire which has semicircular loop of the radius 20 cm as shown in the figure. Magnetic field produced at the centre of the loop is
A current of 10 A is passing through a long wire which has semicircular loop of the radius 20 cm as shown in the figure. Magnetic field produced at the centre of the loop is
physics-General
physics-
Two short bar magnets of equal dipole moment M are fastened perpendicularly at their centers, figure. The magnitude of resultant of two magnetic field at a distance 
from the center on the bisector of the right angle is
Resolving the magnetic moments along 
and perpendicular to
figure we find that component perpendicular cancel out. Resultant magnetic moment along 
The point lies on axial line of magnet of moment
and perpendicular to figure we find that component perpendicular cancel out. Resultant magnetic moment along The point
lies on axial line of magnet of momentTwo short bar magnets of equal dipole moment M are fastened perpendicularly at their centers, figure. The magnitude of resultant of two magnetic field at a distance from the center on the bisector of the right angle is
physics-General
Resolving the magnetic moments along and perpendicular to figure we find that component perpendicular cancel out. Resultant magnetic moment along
The point lies on axial line of magnet of moment
and perpendicular to figure we find that component perpendicular cancel out. Resultant magnetic moment along The point
lies on axial line of magnet of momentphysics-
Two magnets of equal mass are joined at 90
each other as shown in figure. Magnet 
has a magnetic moment 
times that of 
. The arrangement is pivoted so that it is free to rotate in horizontal plane. When in equilibrium, what angle should make with magnetic meridian?
In equilibrium, the resultant magnetic moment will be along magnetic meridian. Let make 
with resultant
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physics-General
In equilibrium, the resultant magnetic moment will be along magnetic meridian. Let make with resultant
make with resultant