Physics-

#### The graph between the displacement and for a particle moving in a straight line is shown in figure. During the interval and the acceleration of the particle is

,

Physics-General

- - 0 + 0
- + 0 + +
- + 0 - +
- - 0 - 0

#### Answer:The correct answer is: - 0 + 0Region shows that graph bending toward time axis acceleration is negative.

Region shows that graph is parallel to time axis velocity is zero. Hence acceleration is zero.

Region shows that graph is bending towards displacement axis acceleration is positive.

Region shows that graph having constant slope velocity is constant. Hence acceleration is zero

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### Related Questions to study

maths-

The minimum and maximum values of 3x are

The minimum and maximum values of 3x are

maths-General

physics-

#### The displacement-time graphs of two moving particles make angles of with the axis. The ratio of their velocities is

Slope of displacement time-graph is velocity

#### The displacement-time graphs of two moving particles make angles of with the axis. The ratio of their velocities is

physics-General

Slope of displacement time-graph is velocity

maths-

#### Extreme Values:The range of

#### Extreme Values:The range of

maths-General

physics-

#### The given graph shows the variation of velocity with displacement. Which one of the graph given below correctly represents the variation of acceleration with displacement?

The equation from the given graph can be written as,

Substituting from Eq. (i), we get

Thus, graph is a straight line with positive slope and negative intercept.

Substituting from Eq. (i), we get

Thus, graph is a straight line with positive slope and negative intercept.

#### The given graph shows the variation of velocity with displacement. Which one of the graph given below correctly represents the variation of acceleration with displacement?

physics-General

The equation from the given graph can be written as,

Substituting from Eq. (i), we get

Thus, graph is a straight line with positive slope and negative intercept.

Substituting from Eq. (i), we get

Thus, graph is a straight line with positive slope and negative intercept.

physics-

#### What is the equivalent resistance between in the given circuit?

and are in series

are in parallel

and are in series

and are in parallel

and are in series

Now, and are in parallel

are in parallel

and are in series

and are in parallel

and are in series

Now, and are in parallel

#### What is the equivalent resistance between in the given circuit?

physics-General

and are in series

are in parallel

and are in series

and are in parallel

and are in series

Now, and are in parallel

are in parallel

and are in series

and are in parallel

and are in series

Now, and are in parallel

physics-

#### The current in the 1 resistor shown in the circuit is

In the given circuit 4 resistors are connected in parallel, this combination is connected in series with 1 resistance.

Also, R’’=2 +1 =3

From Ohm’s law,

Also, R’’=2 +1 =3

From Ohm’s law,

#### The current in the 1 resistor shown in the circuit is

physics-General

In the given circuit 4 resistors are connected in parallel, this combination is connected in series with 1 resistance.

Also, R’’=2 +1 =3

From Ohm’s law,

Also, R’’=2 +1 =3

From Ohm’s law,

physics-

#### The current in the 1 resistor shown in the circuit is

In the given circuit 4 resistors are connected in parallel, this combination is connected in series with 1 resistance.

Also, R’’=2 +1 =3

From Ohm’s law,

Also, R’’=2 +1 =3

From Ohm’s law,

#### The current in the 1 resistor shown in the circuit is

physics-General

Also, R’’=2 +1 =3

From Ohm’s law,

physics-

#### The total current supplied to the given circuit by the battery is

The equivalent circuit of the given circuit is as shown

Resistances 6 and 2 are in parallel

Resistances

Resistances 3 and 3 are in parallel

The current,

Resistances 6 and 2 are in parallel

Resistances

Resistances 3 and 3 are in parallel

The current,

#### The total current supplied to the given circuit by the battery is

physics-General

The equivalent circuit of the given circuit is as shown

Resistances 6 and 2 are in parallel

Resistances

Resistances 3 and 3 are in parallel

The current,

Resistances 6 and 2 are in parallel

Resistances

Resistances 3 and 3 are in parallel

The current,

physics-

#### A current of 2A flows in an electric circuit as shown in figure. The potential difference, in volts( are potentials at R and S respectively) is

Current through each arm

PRQ and PSQ=1A

From Eqs. (i) and (ii), we get

PRQ and PSQ=1A

From Eqs. (i) and (ii), we get

#### A current of 2A flows in an electric circuit as shown in figure. The potential difference, in volts( are potentials at R and S respectively) is

physics-General

Current through each arm

PRQ and PSQ=1A

From Eqs. (i) and (ii), we get

PRQ and PSQ=1A

From Eqs. (i) and (ii), we get

physics-

#### A 3 V battery with negligible internal resistance is connected in a circuit as shown in the figure. The current I, in the circuit will be

Resistance in the arms AC and BC are in series,

∴ R’=3+3=6

Now, R’ and 3 are in parallel,

Now, V=IR

∴ R’=3+3=6

Now, R’ and 3 are in parallel,

Now, V=IR

#### A 3 V battery with negligible internal resistance is connected in a circuit as shown in the figure. The current I, in the circuit will be

physics-General

Resistance in the arms AC and BC are in series,

∴ R’=3+3=6

Now, R’ and 3 are in parallel,

Now, V=IR

∴ R’=3+3=6

Now, R’ and 3 are in parallel,

Now, V=IR

physics-

#### The equivalent resistance between the points A and B will be (each resistance is

15 )

The circuit can be shown as given below

The equivalent resistance between D and C.

Now, between A and B, the resistance of upper part ADCB,

Between A and B, the resistance of middle part AOB

Therefore, equivalent resistance between A and B

The equivalent resistance between D and C.

Now, between A and B, the resistance of upper part ADCB,

Between A and B, the resistance of middle part AOB

Therefore, equivalent resistance between A and B

#### The equivalent resistance between the points A and B will be (each resistance is

15 )

physics-General

The circuit can be shown as given below

The equivalent resistance between D and C.

Now, between A and B, the resistance of upper part ADCB,

Between A and B, the resistance of middle part AOB

Therefore, equivalent resistance between A and B

The equivalent resistance between D and C.

Now, between A and B, the resistance of upper part ADCB,

Between A and B, the resistance of middle part AOB

Therefore, equivalent resistance between A and B

physics-

#### There resistances of 4 each are connected as shown in figure. If the point D divides the resistance into two equal halves, the resistance between points A and D will be

The equivalent circuit is given by

4 and 2 resistances are in series on both sides.

Then 6 and6 resistances are in parallel on both sides

R=3

4 and 2 resistances are in series on both sides.

Then 6 and6 resistances are in parallel on both sides

R=3

#### There resistances of 4 each are connected as shown in figure. If the point D divides the resistance into two equal halves, the resistance between points A and D will be

physics-General

The equivalent circuit is given by

4 and 2 resistances are in series on both sides.

Then 6 and6 resistances are in parallel on both sides

R=3

4 and 2 resistances are in series on both sides.

Then 6 and6 resistances are in parallel on both sides

R=3

physics-

#### In the circuit shown the value of I in ampere is

We can simplify the network as shown

So, net resistance,

R=2.4+1.6=4.0

Therefore, current from the battery.

Now, from the circuit (b),

4I’ =6I

But =I+I’

So, net resistance,

R=2.4+1.6=4.0

Therefore, current from the battery.

Now, from the circuit (b),

4I’ =6I

But =I+I’

#### In the circuit shown the value of I in ampere is

physics-General

We can simplify the network as shown

So, net resistance,

R=2.4+1.6=4.0

Therefore, current from the battery.

Now, from the circuit (b),

4I’ =6I

But =I+I’

So, net resistance,

R=2.4+1.6=4.0

Therefore, current from the battery.

Now, from the circuit (b),

4I’ =6I

But =I+I’

physics-

#### Six resistors, each of value 3 are connected as shown in the figure. A cell of emf 3V is connected across The effective resistance across and the current through the arm will be

The equivalent circuit is shown as

We can emit the resistance in the arm DF as balance condition is satisfied.

Therefore, the 3 resistances in arm CD and DE are in series.

Similarly, for arms CF and FE, R’’=6

are in parallel

R’’’=3

Now, R’’’ and 3 resistances are in parallel

Moreover, V across AB=3V and resistance in the arm=3

∴ Current through the arm will be

We can emit the resistance in the arm DF as balance condition is satisfied.

Therefore, the 3 resistances in arm CD and DE are in series.

Similarly, for arms CF and FE, R’’=6

are in parallel

R’’’=3

Now, R’’’ and 3 resistances are in parallel

Moreover, V across AB=3V and resistance in the arm=3

∴ Current through the arm will be

#### Six resistors, each of value 3 are connected as shown in the figure. A cell of emf 3V is connected across The effective resistance across and the current through the arm will be

physics-General

The equivalent circuit is shown as

We can emit the resistance in the arm DF as balance condition is satisfied.

Therefore, the 3 resistances in arm CD and DE are in series.

Similarly, for arms CF and FE, R’’=6

are in parallel

R’’’=3

Now, R’’’ and 3 resistances are in parallel

Moreover, V across AB=3V and resistance in the arm=3

∴ Current through the arm will be

We can emit the resistance in the arm DF as balance condition is satisfied.

Therefore, the 3 resistances in arm CD and DE are in series.

Similarly, for arms CF and FE, R’’=6

are in parallel

R’’’=3

Now, R’’’ and 3 resistances are in parallel

Moreover, V across AB=3V and resistance in the arm=3

∴ Current through the arm will be

physics-

#### A particle starts from rest at and moves in a straight line with an acceleration as shown below. The velocity of the particle at is

Velocity of graph Area of- graph

#### A particle starts from rest at and moves in a straight line with an acceleration as shown below. The velocity of the particle at is

physics-General

Velocity of graph Area of- graph