Physics-
The graph between the displacement
and
for a particle moving in a straight line is shown in figure. During the interval
and
the acceleration of the particle is

, 
Physics-General
- - 0 + 0
- + 0 + +
- + 0 - +
- - 0 - 0
Answer:The correct answer is: - 0 + 0Region
shows that graph bending toward time axis
acceleration is negative.
Region
shows that graph is parallel to time axis
velocity is zero. Hence acceleration is zero.
Region
shows that graph is bending towards displacement axis
acceleration is positive.
Region
shows that graph having constant slope
velocity is constant. Hence acceleration is zero
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maths-
The minimum and maximum values of 3x are
The minimum and maximum values of 3x are
maths-General
physics-
The displacement-time graphs of two moving particles make angles of
with the
axis. The ratio of their velocities is

Slope of displacement time-graph is velocity


The displacement-time graphs of two moving particles make angles of
with the
axis. The ratio of their velocities is

physics-General
Slope of displacement time-graph is velocity


maths-
Extreme Values:The range of 
Extreme Values:The range of 
maths-General
physics-
The given graph shows the variation of velocity with displacement. Which one of the graph given below correctly represents the variation of acceleration with displacement?

The
equation from the given graph can be written as,


Substituting
from Eq. (i), we get


Thus,
graph is a straight line with positive slope and negative intercept.
Substituting
Thus,
The given graph shows the variation of velocity with displacement. Which one of the graph given below correctly represents the variation of acceleration with displacement?

physics-General
The
equation from the given graph can be written as,


Substituting
from Eq. (i), we get


Thus,
graph is a straight line with positive slope and negative intercept.
Substituting
Thus,
physics-
What is the equivalent resistance between
in the given circuit?


Now,
What is the equivalent resistance between
in the given circuit?

physics-General

Now,
physics-
The current in the 1
resistor shown in the circuit is

In the given circuit 4
resistors are connected in parallel, this combination is connected in series with 1
resistance.



Also, R’’=2
+1
=3
From Ohm’s law,


Also, R’’=2
From Ohm’s law,
The current in the 1
resistor shown in the circuit is

physics-General
In the given circuit 4
resistors are connected in parallel, this combination is connected in series with 1
resistance.



Also, R’’=2
+1
=3
From Ohm’s law,


Also, R’’=2
From Ohm’s law,
physics-
The current in the 1
resistor shown in the circuit is

In the given circuit 4
resistors are connected in parallel, this combination is connected in series with 1
resistance.



Also, R’’=2
+1
=3
From Ohm’s law,


Also, R’’=2
From Ohm’s law,
The current in the 1
resistor shown in the circuit is

physics-General
In the given circuit 4
resistors are connected in parallel, this combination is connected in series with 1
resistance.



Also, R’’=2
+1
=3
From Ohm’s law,


Also, R’’=2
From Ohm’s law,
physics-
The total current supplied to the given circuit by the battery is

The equivalent circuit of the given circuit is as shown

Resistances 6
and 2
are in parallel

Resistances

Resistances 3
and 3
are in parallel

The current,


Resistances 6
Resistances
Resistances 3
The current,
The total current supplied to the given circuit by the battery is

physics-General
The equivalent circuit of the given circuit is as shown

Resistances 6
and 2
are in parallel

Resistances

Resistances 3
and 3
are in parallel

The current,


Resistances 6
Resistances
Resistances 3
The current,
physics-
A current of 2A flows in an electric circuit as shown in figure. The potential difference
, in volts(
are potentials at R and S respectively) is

Current through each arm
PRQ and PSQ=1A


From Eqs. (i) and (ii), we get

PRQ and PSQ=1A
From Eqs. (i) and (ii), we get
A current of 2A flows in an electric circuit as shown in figure. The potential difference
, in volts(
are potentials at R and S respectively) is

physics-General
Current through each arm
PRQ and PSQ=1A


From Eqs. (i) and (ii), we get

PRQ and PSQ=1A
From Eqs. (i) and (ii), we get
physics-
A 3 V battery with negligible internal resistance is connected in a circuit as shown in the figure. The current I, in the circuit will be

Resistance in the arms AC and BC are in series,

∴ R’=3+3=6
Now, R’ and 3
are in parallel,

Now, V=IR


∴ R’=3+3=6
Now, R’ and 3
Now, V=IR
A 3 V battery with negligible internal resistance is connected in a circuit as shown in the figure. The current I, in the circuit will be

physics-General
Resistance in the arms AC and BC are in series,

∴ R’=3+3=6
Now, R’ and 3
are in parallel,

Now, V=IR


∴ R’=3+3=6
Now, R’ and 3
Now, V=IR
physics-
The equivalent resistance between the points A and B will be (each resistance is
15
)

The circuit can be shown as given below

The equivalent resistance between D and C.



Now, between A and B, the resistance of upper part ADCB,

Between A and B, the resistance of middle part AOB

Therefore, equivalent resistance between A and B






The equivalent resistance between D and C.
Now, between A and B, the resistance of upper part ADCB,
Between A and B, the resistance of middle part AOB
Therefore, equivalent resistance between A and B
The equivalent resistance between the points A and B will be (each resistance is
15
)

physics-General
The circuit can be shown as given below

The equivalent resistance between D and C.



Now, between A and B, the resistance of upper part ADCB,

Between A and B, the resistance of middle part AOB

Therefore, equivalent resistance between A and B






The equivalent resistance between D and C.
Now, between A and B, the resistance of upper part ADCB,
Between A and B, the resistance of middle part AOB
Therefore, equivalent resistance between A and B
physics-
There resistances of 4
each are connected as shown in figure. If the point D divides the resistance into two equal halves, the resistance between points A and D will be

The equivalent circuit is given by

4
and 2
resistances are in series on both sides.

Then 6
and6
resistances are in parallel on both sides

R=3

4
Then 6
R=3
There resistances of 4
each are connected as shown in figure. If the point D divides the resistance into two equal halves, the resistance between points A and D will be

physics-General
The equivalent circuit is given by

4
and 2
resistances are in series on both sides.

Then 6
and6
resistances are in parallel on both sides

R=3

4
Then 6
R=3
physics-
In the circuit shown the value of I in ampere is

We can simplify the network as shown

So, net resistance,
R=2.4+1.6=4.0
Therefore, current from the battery.

Now, from the circuit (b),
4I’ =6I

But
=I+I’




So, net resistance,
R=2.4+1.6=4.0
Therefore, current from the battery.
Now, from the circuit (b),
4I’ =6I
But
In the circuit shown the value of I in ampere is

physics-General
We can simplify the network as shown

So, net resistance,
R=2.4+1.6=4.0
Therefore, current from the battery.

Now, from the circuit (b),
4I’ =6I

But
=I+I’




So, net resistance,
R=2.4+1.6=4.0
Therefore, current from the battery.
Now, from the circuit (b),
4I’ =6I
But
physics-
Six resistors, each of value 3
are connected as shown in the figure. A cell of emf 3V is connected across
The effective resistance across
and the current through the arm
will be

The equivalent circuit is shown as

We can emit the resistance in the arm DF as balance condition is satisfied.
Therefore, the 3
resistances in arm CD and DE are in series.

Similarly, for arms CF and FE, R’’=6
are in parallel

R’’’=3
Now, R’’’ and 3
resistances are in parallel


Moreover, V across AB=3V and resistance in the arm=3
∴ Current through the arm will be


We can emit the resistance in the arm DF as balance condition is satisfied.
Therefore, the 3
Similarly, for arms CF and FE, R’’=6
R’’’=3
Now, R’’’ and 3
Moreover, V across AB=3V and resistance in the arm=3
∴ Current through the arm will be
Six resistors, each of value 3
are connected as shown in the figure. A cell of emf 3V is connected across
The effective resistance across
and the current through the arm
will be

physics-General
The equivalent circuit is shown as

We can emit the resistance in the arm DF as balance condition is satisfied.
Therefore, the 3
resistances in arm CD and DE are in series.

Similarly, for arms CF and FE, R’’=6
are in parallel

R’’’=3
Now, R’’’ and 3
resistances are in parallel


Moreover, V across AB=3V and resistance in the arm=3
∴ Current through the arm will be


We can emit the resistance in the arm DF as balance condition is satisfied.
Therefore, the 3
Similarly, for arms CF and FE, R’’=6
R’’’=3
Now, R’’’ and 3
Moreover, V across AB=3V and resistance in the arm=3
∴ Current through the arm will be
physics-
A particle starts from rest at
and moves in a straight line with an acceleration as shown below. The velocity of the particle at
is

Velocity of graph
Area of
-
graph

A particle starts from rest at
and moves in a straight line with an acceleration as shown below. The velocity of the particle at
is

physics-General
Velocity of graph
Area of
-
graph
