Physics-
General
Easy

Question

The relation between the displacement X of an object produced by the application of the variable force F is represented by a graph shown in the figure. If the object undergoes a displacement from X equals 0.5 blank m to X equals 2.5 blank m the work done will be approximately equal to

  1. 16 blank J    
  2. 32 blank J    
  3. 1.6 blank J    
  4. 8 blank J    

The correct answer is: 16 blank J


    Work done = Area under curve and displacement axis
    = Area of trapezium
    equals fraction numerator 1 over denominator 2 end fraction cross times open parentheses s u m blank o f blank t w o blank p a r a l l e l blank l i n e s close parentheses cross times d i s t a n c e blank b e t w e e n blank t h e m
    equals fraction numerator 1 over denominator 2 end fraction open parentheses 10 plus 4 close parentheses cross times open parentheses 2.5 minus 0.5 close parentheses equals fraction numerator 1 over denominator 2 end fraction 14 cross times 2 equals 14 blank J
    As the area actually is not trapezium so work done will be more than 14 blank J i. e. approximately 16 blank J

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