Physics-
The relation between the displacement
of an object produced by the application of the variable force
is represented by a graph shown in the figure. If the object undergoes a displacement from
to
the work done will be approximately equal to

Physics-General
Answer:The correct answer is:
Work done = Area under curve and displacement axis
= Area of trapezium


As the area actually is not trapezium so work done will be more than
approximately 
Book A Free Demo

Grade*
Select Grade
Related Questions to study
physics-
In the given curved road, if particle is released from
then

If the surface is smooth then the kinetic energy at
never be zero
If the surface is rough, the kinetic energy at
be zero. Because, work done by force of friction is negative. If work done by friction is equal to
then, net work done on body will be zero. Hence, net change in kinetic energy is zero. Hence, (b) is correct If the surface is rough, the kinetic energy at
must be lesser than
. If surface is smooth, the kinetic energy at
is equal to
The reason is same as in (a) and (b)
If the surface is rough, the kinetic energy at
In the given curved road, if particle is released from
then

physics-General
If the surface is smooth then the kinetic energy at
never be zero
If the surface is rough, the kinetic energy at
be zero. Because, work done by force of friction is negative. If work done by friction is equal to
then, net work done on body will be zero. Hence, net change in kinetic energy is zero. Hence, (b) is correct If the surface is rough, the kinetic energy at
must be lesser than
. If surface is smooth, the kinetic energy at
is equal to
The reason is same as in (a) and (b)
If the surface is rough, the kinetic energy at
physics-
Three objects
and
are kept in a straight line on a frictionless horizontal surface. These have masses
and
respectively. The object
moves towards
with a speed
and makes an elastic collision with it. Thereafter,
makes completely inelastic collision with
. All motions occur on the same straight line. Find the final speed (in
) of the object 



By the law of conservation of momentum
Three objects
and
are kept in a straight line on a frictionless horizontal surface. These have masses
and
respectively. The object
moves towards
with a speed
and makes an elastic collision with it. Thereafter,
makes completely inelastic collision with
. All motions occur on the same straight line. Find the final speed (in
) of the object 

physics-General


By the law of conservation of momentum
physics-
A body of mass
slides down a curved track which is quadrant of a circle of radius
. All the surfaces are frictionless. If the body starts from rest, its speed at the bottom of the track is

By conservation of energy, 

A body of mass
slides down a curved track which is quadrant of a circle of radius
. All the surfaces are frictionless. If the body starts from rest, its speed at the bottom of the track is

physics-General
By conservation of energy, 

physics-
The relationship between the force F and position
of a body is as shown in figure. The work done in displacing the body from
to
m will be

Work done=area enclosed by
graph
=area of ABNM + area of CDEN - area of EFGH + area of HIJ

=

=area of ABNM + area of CDEN - area of EFGH + area of HIJ

=
The relationship between the force F and position
of a body is as shown in figure. The work done in displacing the body from
to
m will be

physics-General
Work done=area enclosed by
graph
=area of ABNM + area of CDEN - area of EFGH + area of HIJ

=

=area of ABNM + area of CDEN - area of EFGH + area of HIJ

=
physics-
A block of mass
kg sliding on a smooth horizontal surface with a velocity
meets the spring of spring constant
fixed at one end as shown in figure. The maximum compression of the spring and velocity of block as is returns to the original position respectively are

When block strikes the spring, the kinetic energy of block converts into potential energy of spring ie,

Or

When block returns to the original position, again potential energy converts into kinetic energy of the blocks, so velocity of the block is same as before but its sign changes as it goes to mean position.

Or
When block returns to the original position, again potential energy converts into kinetic energy of the blocks, so velocity of the block is same as before but its sign changes as it goes to mean position.
A block of mass
kg sliding on a smooth horizontal surface with a velocity
meets the spring of spring constant
fixed at one end as shown in figure. The maximum compression of the spring and velocity of block as is returns to the original position respectively are

physics-General
When block strikes the spring, the kinetic energy of block converts into potential energy of spring ie,

Or

When block returns to the original position, again potential energy converts into kinetic energy of the blocks, so velocity of the block is same as before but its sign changes as it goes to mean position.

Or
When block returns to the original position, again potential energy converts into kinetic energy of the blocks, so velocity of the block is same as before but its sign changes as it goes to mean position.
physics-
A 10 kg brick moves along an
-axis. Its acceleration as a function of its position is shown in figure. What is the net work performed on the brick by the force causing the acceleration as the brick moves from
to
m?

According to the graph the acceleration
varies linearly with the coordinate
. We may write
, where
is the slope of the graph.
From the graph

The force on the brick is in the positive
-direction and according to Newton’s second law, its magnitude is given by

If
is the final coordinate, the work done by the force is



From the graph
The force on the brick is in the positive
If
A 10 kg brick moves along an
-axis. Its acceleration as a function of its position is shown in figure. What is the net work performed on the brick by the force causing the acceleration as the brick moves from
to
m?

physics-General
According to the graph the acceleration
varies linearly with the coordinate
. We may write
, where
is the slope of the graph.
From the graph

The force on the brick is in the positive
-direction and according to Newton’s second law, its magnitude is given by

If
is the final coordinate, the work done by the force is



From the graph
The force on the brick is in the positive
If
physics-
An object of mass
is tied to a string of length
and a variable horizontal force is applied on it which starts at zero and gradually increases until the string makes an angel
with the vertical. Work done by the force
is

(Since, change in kinetic energy is zero)

Here,
An object of mass
is tied to a string of length
and a variable horizontal force is applied on it which starts at zero and gradually increases until the string makes an angel
with the vertical. Work done by the force
is

physics-General
(Since, change in kinetic energy is zero)

Here,
physics-
A light inextensible string that goes over a smooth fixed pulley as shown in the figure connects two blocks of masses
and
. Taking
, find the work done (in joules) by the string on the block of mass
during the first second after the system is released from rest

In the given condition tension in the string



And acceleration of each block

Let ‘S’ is the distance covered by block of mass
in first sec

Work done by the string 


And acceleration of each block
Let ‘S’ is the distance covered by block of mass
A light inextensible string that goes over a smooth fixed pulley as shown in the figure connects two blocks of masses
and
. Taking
, find the work done (in joules) by the string on the block of mass
during the first second after the system is released from rest

physics-General
In the given condition tension in the string



And acceleration of each block

Let ‘S’ is the distance covered by block of mass
in first sec

Work done by the string 


And acceleration of each block
Let ‘S’ is the distance covered by block of mass
maths-
Range of function f(x) =
,
is given by -
]
(C)
(C)
Range of function f(x) =
,
is given by -
maths-General
]
(C)
(C)
physics-
Force
on a particle moving in a straight line varies with distance
as shown in the figure. The work done on the particle during its displacement of 

Work = Area under
graph

Force
on a particle moving in a straight line varies with distance
as shown in the figure. The work done on the particle during its displacement of 

physics-General
Work = Area under
graph

physics-
The potential energy of a system is represented in the first figure. The force acting on the system will be represented by

As slope of problem graph is positive and constant upto certain distance and then it becomes zero
So from
, up to distance
,
constant (negative) and becomes zero suddenly
So from
The potential energy of a system is represented in the first figure. The force acting on the system will be represented by

physics-General
As slope of problem graph is positive and constant upto certain distance and then it becomes zero
So from
, up to distance
,
constant (negative) and becomes zero suddenly
So from
physics-
The work done by force acting on a body is as shown in the graph. The total work done in covering an initial distance of 20 m is

Work done 
ABCD +Area CEFD




The work done by force acting on a body is as shown in the graph. The total work done in covering an initial distance of 20 m is

physics-General
Work done 
ABCD +Area CEFD




physics-
Figure shows the
-
graph. Where
is the force applied and
is the distance covered

By the body along a straight line path. Given that
is in
and
in
, what is the work done?
Work done =area under curve and displacement axis

Figure shows the
-
graph. Where
is the force applied and
is the distance covered

By the body along a straight line path. Given that
is in
and
in
, what is the work done?
physics-General
Work done =area under curve and displacement axis

physics-
A vertical spring with force constant
is fixed on a table. A ball of mass
at a height
above the free upper end of the spring falls vertically on the spring so that the spring is compressed by a distance
. The net work done in the process is

Gravitational potential energy of ball gets converted into elastic potential energy of the spring 
Net work done
Net work done
A vertical spring with force constant
is fixed on a table. A ball of mass
at a height
above the free upper end of the spring falls vertically on the spring so that the spring is compressed by a distance
. The net work done in the process is

physics-General
Gravitational potential energy of ball gets converted into elastic potential energy of the spring 
Net work done
Net work done
physics-
Two rectangular blocks
and
of masses 2kg and 3 kg respectively are connected by spring of spring constant 10.8
and are placed on a frictionless horizontal surface. The block
was given an initial velocity of 0.15
in the direction shown in the figure. The maximum compression of the spring during the motion is

As the block A moves with velocity with velocity 0.15
, it compresses the spring Which pushes B towards right. A goes on compressing the spring till the velocity acquired by B becomes equal to the velocity of A, i.e. 0.15
. Let this velocity be v. Now, spring is in a state of maximum compression. Let x be the maximum compression at this stage.

According to the law of conservation of linear momentum, we get

Or

According to the law of conservation of energy





Or

According to the law of conservation of linear momentum, we get
Or
According to the law of conservation of energy
Or
Two rectangular blocks
and
of masses 2kg and 3 kg respectively are connected by spring of spring constant 10.8
and are placed on a frictionless horizontal surface. The block
was given an initial velocity of 0.15
in the direction shown in the figure. The maximum compression of the spring during the motion is

physics-General
As the block A moves with velocity with velocity 0.15
, it compresses the spring Which pushes B towards right. A goes on compressing the spring till the velocity acquired by B becomes equal to the velocity of A, i.e. 0.15
. Let this velocity be v. Now, spring is in a state of maximum compression. Let x be the maximum compression at this stage.

According to the law of conservation of linear momentum, we get


According to the law of conservation of linear momentum, we get